a) x : 1/4 = 7/5
    x         = 7/5 x 1/4
    x         = 7/20
b) 9/2 - x = 3/5
            x = 9/2 - 3/5
            x = 39/10
c) 12/5 : x = 7/2
              x = 12/5 : 7/2
              x = 24/35

a) \(x\div\dfrac{1}{4}=\dfrac{7}{5}\)

    \(x=\dfrac{7}{5}\times\dfrac{1}{4}\)

    \(x=\dfrac{7}{20}\)

b) \(\dfrac{9}{2}-x=\dfrac{3}{5}\)

            \(x=\dfrac{9}{2}-\dfrac{3}{5}\)

            \(x=\dfrac{39}{10}\)

c) \(\dfrac{12}{5}\div x=\dfrac{7}{2}\)

             \(x=\dfrac{12}{5}\div\dfrac{7}{2}\)

             \(x=\dfrac{12}{5}\times\dfrac{2}{7}\)

             \(x=\dfrac{24}{35}\)

a)\(x=\dfrac{1}{4}\)x\(\dfrac{7}{5}=\dfrac{7}{20}\)

b)\(x=\dfrac{9}{2}-\dfrac{3}{5}=\dfrac{39}{10}\)

c)\(x=\dfrac{12}{5}:\dfrac{7}{2}=\dfrac{24}{35}\)

b.\(\left(\dfrac{1}{2}-\dfrac{3}{2x-5^2-5}\right)=11\)

\(\Leftrightarrow\left(\dfrac{1}{2}-\dfrac{3}{2x-30}\right)=11\);\(x\ne15\)

\(\Leftrightarrow-\dfrac{3}{2x-30}=\dfrac{21}{2}\)

\(\Leftrightarrow-\dfrac{3}{2\left(x-15\right)}=\dfrac{21}{2}\)

\(\Leftrightarrow-\dfrac{3}{2\left(x-15\right)}=\dfrac{21\left(x-15\right)}{2\left(x-15\right)}\)

\(\Leftrightarrow-3=21\left(x-15\right)\)

\(\Leftrightarrow-3=21x-315\)

\(\Leftrightarrow21x=312\)

\(\Leftrightarrow x=\dfrac{104}{7}\)

c.\(\dfrac{2}{3}-\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{2}\)

\(\Leftrightarrow-\left|4x+\dfrac{1}{2}\right|=-\dfrac{1}{6}\)

\(\Leftrightarrow\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{6}\)

\(\Leftrightarrow\left[{}\begin{matrix}4x+\dfrac{1}{2}=\dfrac{1}{6}\\4x+\dfrac{1}{2}=-\dfrac{1}{6}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{12}\\x=-\dfrac{1}{6}\end{matrix}\right.\)

a.\(\left(\dfrac{1}{2}-\dfrac{3}{2x-5^2-5}\right)=11\)

b.\(\dfrac{2}{3}-\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{2}\)

Đề là vậy đk bạn?

xin đếy giải giúp mik ik!!!

a, 6/7, 6/15, 6/17, 6/21

Nhớ ghi dấu ngoặc tránh giải sai. 

\(a.\)  \(\frac{x+4}{2x+6}+\frac{3}{x^2-9}\)

Ta có: 

\(2x+6=2\left(x+3\right)\)

\(x^2-9=\left(x-3\right)\left(x+3\right)\)

nên \(MTC:\)  \(2\left(x-3\right)\left(x+3\right)\)

Do đó:  \(\frac{x+4}{2x+6}+\frac{3}{x^2-9}=\frac{x+4}{2\left(x+3\right)}+\frac{3}{\left(x-3\right)\left(x+3\right)}=\frac{\left(x+4\right)\left(x-3\right)}{2\left(x-3\right)\left(x+3\right)}+\frac{2.3}{2\left(x-3\right)\left(x+3\right)}=\frac{x^2+x-12+6}{2\left(x-3\right)\left(x+3\right)}\)

\(=\frac{x^2+x-6}{2\left(x-3\right)\left(x+3\right)}=\frac{x^2-2x+3x-6}{2\left(x-3\right)\left(x+3\right)}=\frac{x\left(x-2\right)+3\left(x-2\right)}{2\left(x-3\right)\left(x+3\right)}=\frac{\left(x-2\right)\left(x+3\right)}{2\left(x-3\right)\left(x+3\right)}=\frac{x-2}{2\left(x-3\right)}\)

tick mình đi mình giải cho nha

1/

a)19/20

b)(1/4+4/9):(3/2-2/3)^2

=25/36:25/36

=1

2/

a) =>x.4=2.-3

=>x.4=-6

=>x=-1,5

b) =>1/6x=5/3+1/4

=>1/6x=23/12

=>x=11,5

bit lm rùi thì đăng lm j nữa ko ai rảnh mà đi lm

\(M=\dfrac{1}{2^2}+\dfrac{1}{4^2}+...+\dfrac{1}{100^2}\)

Ta thấy \(\dfrac{1}{2^2}< \dfrac{1}{1\cdot2};\dfrac{1}{4^2}< \dfrac{1}{3\cdot4};...;\dfrac{1}{100^2}< \dfrac{1}{99\cdot100}\)

\(\Rightarrow M< \dfrac{1}{1\cdot2}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}\\ =1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\\ =\left(1+\dfrac{1}{3}+...+\dfrac{1}{99}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{100}\right)\\ =\left(1+\dfrac{1}{2}+...+\dfrac{1}{100}\right)-2\left(\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{1}{100}\right)\\ =\left(1+\dfrac{1}{2}+...+\dfrac{1}{100}\right)-1-\dfrac{1}{2}-...-\dfrac{1}{50}\\ =\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}< \dfrac{1}{50}+\dfrac{1}{50}+...+\dfrac{1}{50}\left(50.số\right)=\dfrac{50}{50}=1\)

Vậy \(M< 1\)

Mình chỉ so sánh với 1 được thôi à :((

A : 3 - 2 = -x + 1/7

     1 = -x + 1/7

x= 1/7 -1

x = -6/7

B: 4/5 + (-1/9) = 8/7 -x 

31/45 = 8/7 -x

x= 8/7 -31/45

x=143/315 

C: [x-1/3] =10

=> 10\(\le\)3x-1/3 \(< \)11

=> 30 \(\le\)3x-1 \(< \)33

=> 31\(\le3x\)<34

<=> 11\(\le x< 12\)

=> x=11 

D: [ -x + 2/5 ] = 3,5 -1/2

[-5x+2/5]=3

=> 3\(\le\)-5x+2/5 <4

=> 15\(\le\)-5x+2 <20

=> 13\(\le\)-5x< 18

=> -3\(\ge\)x>-4

=> x = -3