b.\(\left(\dfrac{1}{2}-\dfrac{3}{2x-5^2-5}\right)=11\)
\(\Leftrightarrow\left(\dfrac{1}{2}-\dfrac{3}{2x-30}\right)=11\);\(x\ne15\)
\(\Leftrightarrow-\dfrac{3}{2x-30}=\dfrac{21}{2}\)
\(\Leftrightarrow-\dfrac{3}{2\left(x-15\right)}=\dfrac{21}{2}\)
\(\Leftrightarrow-\dfrac{3}{2\left(x-15\right)}=\dfrac{21\left(x-15\right)}{2\left(x-15\right)}\)
\(\Leftrightarrow-3=21\left(x-15\right)\)
\(\Leftrightarrow-3=21x-315\)
\(\Leftrightarrow21x=312\)
\(\Leftrightarrow x=\dfrac{104}{7}\)
c.\(\dfrac{2}{3}-\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{2}\)
\(\Leftrightarrow-\left|4x+\dfrac{1}{2}\right|=-\dfrac{1}{6}\)
\(\Leftrightarrow\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{6}\)
\(\Leftrightarrow\left[{}\begin{matrix}4x+\dfrac{1}{2}=\dfrac{1}{6}\\4x+\dfrac{1}{2}=-\dfrac{1}{6}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{12}\\x=-\dfrac{1}{6}\end{matrix}\right.\)
a.\(\left(\dfrac{1}{2}-\dfrac{3}{2x-5^2-5}\right)=11\)
b.\(\dfrac{2}{3}-\left|4x+\dfrac{1}{2}\right|=\dfrac{1}{2}\)
Đề là vậy đk bạn?
