\(x\times4+\frac{1}{2}\times x=55,35\)

\(x\times\left(4+\frac{1}{2}\right)=55,35\)

\(x\times4,5=55,35\)

\(x=55,35:4,5\)

\(x=12,3\)

x x 4 + 1/2 x x = 55,35

     x x (4 + 1/2) = 55,35

               x x 4,5 = 55,35

                         x = 55,35 : 4,5

                         x = 12,3

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\(x\times4+\frac{1}{2}\times x=55,35\)

\(x\times4+0,5\times x=55,35\)

\(x\times\left(4+0,5\right)=55,35\)

\(x\times4,5=55,35\)

\(x=55,35\div4,5\)​

\(x=12,3\)

Vậy ​\(x=12,3\)​
 

\(x\times9,25\times x=55,35\)

\(x\times x=55,35:9,25\)

\(x\times x\approx5,98\)

\(x\approx2,45\)

hình như em chép sai đề bài

x=2,446177382

x*4+1/2*x=55,35

=x*(4+1/2)=55,35

=x*4,5=55,35

=55,35:4,5

=12,3

123/10 hoặc 12,3

`!`

`x xx 4 +1/2 xx x=55,35`

`=> x xx ( 4+1/2) =55,35`

`=  x xx 9/2=55,35`

`=>x= 55,35 : 9/2`

`=>x= 3,075`

\(\Leftrightarrow x\cdot\dfrac{9}{2}=55.35\)

hay x=12,3

12,3

=>8(x+1/x)^2+4[(x+1/x)^2-2]^2-4[(x+1/x)^2-2](x+1/x)^2=(x+4)^2

Đặt x+1/x=a(a>=2)

=>8a^2+4[a^2-2]^2-4[a^2-2]*a^2=(x+4)^2

=>8a^2+4a^4-16a^2+16-4a^4+8a^2=(x+4)^2

=>(x+4)^2=16

=>x+4=4 hoặc x+4=-4

=>x=-8;x=0

Điều kiện: \(x\ne0\)

\(\Leftrightarrow8\left(x+\dfrac{1}{x}\right)^2+4\left(x^2+\dfrac{1}{x^2}\right)\left[\left(x^2+\dfrac{1}{x^2}\right)-\left(x+\dfrac{1}{x}\right)^2\right]=\left(x+4\right)^2\)

\(\Leftrightarrow8\left(x+\dfrac{1}{x}\right)^2-8\left(x^2+\dfrac{1}{x^2}\right)=\left(x+4\right)^2\\ \Leftrightarrow\left(x+4\right)^2=16\\ \Rightarrow\left\{{}\begin{matrix}x=0\\x=-8\end{matrix}\right.\)

Vì \(x\ne0\) nên \(S=\left\{-8\right\}\)

nếu X*4+1:2*X=55,35

thì X=12,3

x*4 +  1/2 * x = 55,35

x * ( 4 + 1/2 ) = 55,35

x * 4,5 = 55,35

x = 55,35 : 4,5 

x = 12,3

Vậy x = 12,3

Lời giải

\(x\cdot4+\frac{1}{2}\cdot x=55,35\)

\(x\cdot\left(4+\frac{1}{2}\right)=55,35\)

\(x\cdot\frac{9}{2}=55,35\)

      \(x=55,35:\frac{9}{2}\)

      \(x=12,3\)

x=3,507135583 nha bạn

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