a, \(ab+ac\)

\(=a\left(b+c\right)\)

b, \(ab-ac+ad\)

\(=a\left(b-c+d\right)\)

c, \(ax-bx-cx+dx\)

\(=x\left(a-b-c+d\right)\)

d, \(a\left(b+c\right)-d\left(b+c\right)\)

\(=\left(b+c\right)\left(a-d\right)\)

\(a)ab+ac=a\left(b+c\right)\)

\(b)ab-ac+ad=a\left(b-c+d\right)\)

\(c)ax-bx-cx+dx=x\left(a-b-c+d\right)\)

\(d)a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

\(e)ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

\(g)ax+by+bx+ay=\left(ax+bx\right)+\left(ay+by\right)=x\left(a+b\right)+y\left(a+b\right)=\left(x+y\right)\left(a+b\right)\)

a) ab+ac=a(b+c)

b) ab-ac+ad=a(b-c+d)

c) ax-bx-cx+dx = x(a-b-c+d)

d) a(b+c)-d(b+c)= (b+c)(a-d)

e) ac-ad+bc-bd = a(c-d)+b(c-d)= (c-d)(a+b)

g) ax+by+bx+ay= x(a+b)+y(a+b)=(x+y)(a+b)

a,a.(b+c)

b,a.(b-c+d)

c,x.(a-b-c+d)

d,(a-d).(b+c)

...............

nhớ cho mk nha, mk làm đây, đừng cho ai khác nha, mk sẽ làm ngay bây giờ nhưng khi mk làm xong thì cho mk là đc

a,ab+ac=a(b+c)

b,ab-ac+ad=a(b-c+d)

c,ax-bx-cx+dx=(a-b-c+d)x

d,a(b+c)-d(b+c)

=ab+ac-bd+cd

=b(a-d)+(a+d)c

e,ac-ad+bc-bd

=c(a+b)-(a-b)d

f,ax+by+bx+ay

=a(x+y)+b(y+x)

a) \(ab+ac=a\left(b+c\right)\)

b) \(ab-ac+ad=a\left(b-c+d\right)\)

c) \(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

d) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

e) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(c-d\right)\left(a+b\right)\)

f) \(ax+by+bx+ay=ax+bx+by+ay=x\left(a+b\right)+y\left(a+b\right)=\left(a+b\right)\left(x+y\right)\)

a) \(ab+acbx=ab\left(1+cx\right)\)

b) \(ab-ac+ad=a\left(b-c+d\right)\)

c) \(ax-bx-cx+dx=x\left(a-b-x+d\right)\)

d) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

e) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

f) \(ax+by+bx+ay=\left(ax+bx\right)+\left(by+ay\right)\)

\(=x\left(a+b\right)+y\left(a+b\right)=\left(a+b\right)\left(x+y\right)\)

ab + ac = a(b + c)

ab - ac + ad = a(b - c + d)

ax - bx - cx + dx

=x(a - b - c + d)

chuẩn men

ab+ac=a(b+c)

ab-ac+ad=a(b-c+d)

ax-bx-cx+dx=x(a-b-c+d)

1, ab + ac = a(b+c)

2, ab - ac + ad = a(b-c+d)

3, ax-bx-cx+dx = x(a-b-c+d)

4, a(b+c) - d(b+c) = (a-d)(b+c)

5, ac-ad+bc-bd = a(c-d) + b(c-d) = (a+b)(c-d)

6, ax+by+bx+ay=ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y)

a(b+c)
a(b-c+d)
x(a-b-c+d)
(b+c)(a-d)
a(c-d)+c(c-d)=(c-d)(a+c)
a(x+y)+b(x+y)=(x+y)(a+b)
T

a) ax(b+c)

b) ax(b-c+d)

c) X x(a-b-c+d)

e, f tương tự

k mình nha bạn

ĐẶT NHÂN TỬ CHUNG NHA!

1) ab - ac + ad = a( b- c +d ) 

2) ax - bx - cx + dx = x( a-b-c+d)

3) a.( b + c ) - d . ( b + c )= (b+c)(a-d)

4) ac - ad + bc - bd = a( c-d)  + b( c-d) = (a+b)(c-d)

5) ax + by + bx + ay= a( x+y) + b( x+y) = (a+b)(x+y)

1) ab + ac = a(b + c)

2) ab - ac + ad = a(b - c + d)

3) ax - bx - cx + dx = x(a - b - c + d)

4) a(b + c) - d(b + c) = (b + c)(a - d)

5) ac - ad + bc - bd = a(c - d) + b(c - d) = (c - d)(a + b)

6) ax + by + bx + ay = (ax + ay) + (bx + by) = a(x + y) + b(x + y) = (x + y)(a + b)

ab + ac = a ( b + c )

ab - ac + ad = a ( b - c + d )

ax - bx - cx + dx = x ( a - b - c + d )