-3/7x4(2,1y2-0,7x+35)
7x4-28+35=?
giúp em vs em ms lớp 2 thui
7 x 4 - 28 + 35
=28 - 28 + 35
= 0 + 35
= 35!
NHớ tk nha!
Tìm bậc của đa thức:
M(x)=7x4 + 3 - 3x2 - 7x4 + 2x -7
`M(x)=7x^4+3-3x^2-7x^4+2x-7`
`M(x)=(7x^4-7x^4)-3x^2+2x+(3-7)`
`M(x)=-3x^2+2x-4`
`->` Bậc của đa thức là `2.`
Ta có :
`M(x)=7x^4 + 3 - 3x^2 - 7x^4 + 2x -7`
`= (7x^4-7x^4) -3x^2+2x+(3-7)`
`= -3x^2 + 2x - 4`
Bậc của đa thức là : `2`
`@ yngoc`
D=0,7x\(2\frac{2}{3}x20x0,375x\frac{5}{28}\)
Các bạn cố giúp mình nhanh nha
D=\(\frac{28}{15}\times\frac{15}{2}\times\frac{5}{28}\)
D=\(14\times\frac{5}{28}\)
D=\(\frac{5}{2}\)
2/3-3/8
3/7x4/5
2/5:2/3
\(\dfrac{2}{3}-\dfrac{3}{8}=\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)
\(\dfrac{3}{7}\times\dfrac{4}{5}=\dfrac{3\times4}{7\times5}=\dfrac{12}{35}\)
\(\dfrac{2}{5}:\dfrac{2}{3}=\dfrac{2}{5}\times\dfrac{3}{2}=\dfrac{6}{10}=\dfrac{3}{5}\)
3/7x4/5+3/7x2/5-3/7x1/5
3/7*4/5+3/7*2/5-3/7*1/5=3/7
đúng thì k cho mình nha
\(\frac{3}{7}.\frac{4}{5}+\frac{3}{7}.\frac{2}{5}-\frac{3}{7}.\frac{1}{5}=\frac{3}{7}\left(\frac{4}{5}+\frac{2}{5}-\frac{1}{5}\right)\)
\(=\frac{3}{7}.1\)
=\(\frac{3}{7}\)
32,5:0,25+39/7x4/13x420-60%x 35x1/3
\(=130+\dfrac{39}{7}\cdot\dfrac{4}{13}\cdot420-\dfrac{3}{5}\cdot35\cdot\dfrac{1}{3}=130-7+720=843\)
32,5:0,25+39/7x4/13x420-60%x 35x1/3
\(32,5:0,25+\dfrac{39}{7}.\dfrac{4}{13}.420-60\%.35.\dfrac{1}{3}\)
\(\dfrac{325}{10}:\dfrac{1}{4}+\dfrac{39}{7}.\dfrac{4}{13}.420-60\%.35.\dfrac{1}{3}\)
\(\dfrac{325}{10}.4+\dfrac{12}{7}.420-\dfrac{3}{5}.35.\dfrac{1}{3}\)
\(130+\dfrac{1}{5}-\dfrac{3}{7}.\dfrac{1}{3}\)
\(\dfrac{651}{5}-\dfrac{1}{7}\)
\(\dfrac{4552}{35}\)
C=3/7x4/13+3/7x9/13+5va 4/7
\(C=\frac{3}{7}\times\frac{4}{13}+\frac{3}{7}\times\frac{9}{13}+5\frac{4}{7}\)
\(C=\frac{3}{7}\times\frac{4}{13}+\frac{3}{7}\times\frac{9}{13}+\frac{39}{7}\)
\(C=\frac{3}{7}\times\left(\frac{4}{13}+\frac{9}{13}\right)+\frac{39}{7}\)
\(C=\frac{3}{7}\times1+\frac{39}{7}\)
\(C=\frac{3}{7}+\frac{39}{7}\)
\(C=\frac{42}{7}\)
\(C=6\)
_Chúc bạn học tốt_
Bậc của đa thức Q=x^3−7x4^y+xy^3−11 là :
Q= x^3 − 7x4^y + xy^3 − 11
Bậc là 5.