rút gọn : a) (-5x^2y+3xy^2+7)-(-6x^2y+4xy^2-5)
b)(2,4x^3-10x^2y)+(7x^2y-2,4x^3+3xy^2)
c) -(15x^2y-7xy^2-6y^2)-(2x^2-12x^2y+7xy^2)
giúp mình với , mình đang cần gấp
Rút gọn các biểu thức sau:
a) ( -5x2 +3xy + 7) + ( -6x2y + 4xy2 - 5)
b) ( 2,4x3 - 10x2y) + (7x2y - 2,4x3 + 3xy2)
c) ( 15x2y - 7xy2 - 6y2) + (2x2 - 12x2y + 7xy2)
d) ( 4x2 + x2y - 5y3) + (5/3 x3 - 6xy2 - x2y) + (x3/3 + 10y3) + ( 6y3-15xy2 - 4x2y - 10x3)
a) ( -5x2 +3xy + 7) + ( -6x2y + 4xy2 - 5)=4*x*y^2-6*x^2*y+3*a*x*y-5*a*x^2+7*a-5
b) ( 2,4x3 - 10x2y) + (7x2y - 2,4x3 + 3xy2)=3*x*y^2-3*x^2*y
c) ( 15x2y - 7xy2 - 6y2) + (2x2 - 12x2y + 7xy2)=-6*y^2+3*x^2*y+2*x^2
d) ( 4x2 + x2y - 5y3) + (5/3 x3 - 6xy2 - x2y) + (x3/3 + 10y3) + ( 6y3-15xy2 - 4x2y - 10x3)=11*y^3-21*x*y^2-4*x^2*y-8*x^3+4*x^2
Tính tổng:
a) (-5x2y + 3xy2 + 7) + (-6x2y + 4xy2 -5)
b) (2,4a3 - 10a2b) + (7a2b - 2,4a3 + 3ad2)
c) (15x2y - 7xy2 - 6y3) + (2x3 - 12x2y +7xy2)
Mik đag cần gấp. Mong mn có thể giúp mik.
Thanks tất cả mn!
a) (-5x2y + 3xy2 + 7) + (-6x2y + 4xy2 -5)
= -5x2y + 3xy2 + 7 + -6x2y + 4xy2 -5
= -11x2y +7xy2 + 2
b) (2,4a3 - 10a2b) + (7a2b - 2,4a3 + 3ad2)
= 2,4a3 - 10a2b + 7a2b - 2,4a3 + 3ad2
= -3a2b + 3ad2
c) (15x2y - 7xy2 - 6y3) + (2x3 - 12x2y +7xy2)
= 15x2y - 7xy2 - 6y3 + 2x3 - 12x2y +7xy2
= 3x2y- 6y3 + 2x3
A=1/3(xy^2)^2.(-1/2x^2y)^2.4/5x^3
B=-2x^4y.1/4x^2y^2.4/5x^3
Thu gon da thuc tren
Xac dinh he so,tim bac cua da thuc vua tim dc
Tinh A+B
va A-B
Bai 2
A=15x^2y-7xy^2+8-y^3+7xy^2+2y^3-12x^2y-1/2
Thu gon da thuc
Tim bac cua da thuc
Tinh gia tri cua da thuc A tai x=-1/2,y=1
Cho mình hỏi: những hằng đẳng thức này đọc là gì??
Hằng đẳng thức bậc cao sử dụng nhị thức newton
2x^2(x^2-7x-3)
b.(-2x^3)+3/4y^2+7xy)*4xy^2
c.(-5x^3)(2x^2+3x-5)
d.(2x^2-1/3xy+y^2)*(-3x^3)
Bài 3 : Tìm đa hức M , biết
a) M+(5x^2-2xy)=6x^2+9xy-y^2
b)M-(3xy-4y6^2)=x^2-7xy+8y^2
c)25x^2y-13x^2y+y^3)-M=11x^2y-2y^2
d)M+(12x^4-15x^2y+2xy^2+7)=0
a) M + (5x2 - 2xy) = 6x2 + 9xy - y2
=> M = (6x2 + 9xy - y2) - (5x2 - 2xy)
=> M = 6x2 + 9xy - y2 - 5x2 + 2xy = (6x2 - 5x2) + (9xy + 2xy) - y2 = x2 + 11xy - y2
b) Sửa đề lại đi nhé
c) (25x2y - 13x2y + y3) - M = 11x2y - 2y2
=> M = (25x2y - 13x2y + y3) - (11x2y - 2y2)
=> M = 25x2y - 13x2y + y3 - 11x2y + 2y2
=> M = x2y + y3 + 2y2
d) M = 0 - (12x4 - 15x2y + 2xy2 + 7) = -12x4 + 15x2y - 2xy2 - 7
a) Ta có : M = 6x2 + 9xy - y2 - (5x2 - 2xy)
= 6x2 + 9xy - y2 - 5x2 + 2xy
= x2 + 11xy - y2
b) Ta có M = x2 - 7xy + 8y2 - (3xy - 24y2)
= x2 - 7xy + 8y2 - 3xy + 24y2
= x2 - 10xy + 32y2
c) Ta có M = 25x2.y- 13x2y + y3 - (11x2y - 2y2)
= 25x2.y- 13x2y + y3 - 11x2y + 2y2
= x2y + y3 + 2y2
d) Ta có M = -(12x4 - 15x2y + 2xy2 + 7)
= -12x4 + 15x2y - 2xy2 - 7
1,nhân đa thức với đa thức
a, ( -5x2).(3x2-7/5x+1/25)
b, (4x2y-5x-7y2).(-3/4x2y)
c, (15x2y+42xy2-3/4xy).(-2x)
d, (-32x2).(1/8x2y-1/6x+2)
2,rút gọn các đa thức sau.
a, 5x( x+2)-3(4x2+2x-1)-(3x2+1)
b,-7x(x-4)-3x(5x-1/3)+4.(7-2x2)
c, x2(x+2y)-4y(2x2-x+1)-5xy-4x2y.
d, 32xy (4xy-3x3y+3xy2)-4x(3xy2+5x2y2-7xy3)
tim x bt
8x3+12x2+6x+1=0
2x2+5x-3=0
phan tich da thuc thanh nhan tu
x3-x+3x2y+3xy2+y3-y
tim x bt:
x2-2x-3=0
rut gon
(5x-1)+2(1-5x)(4+5x)+(5x+4)2
(x-y)3+(y+x)3+(y-x)3-3xy(x+y)
Phân tích đa thức thành nhân tử:(em làm luôn đấy,ko ghi lại đề)
\(\left(x^3+y^3\right)-\left(x+y\right)+3xy\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2-xy+y^2\right)-\left(x+y\right)+3xy\left(x+y\right)\)
\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)\(=\left(x+y\right)\left[\left(x+y\right)^2-1^2\right]\)
\(=\left(x+y\right)\left(x+y-1\right)\left(x+y+1\right)\)
\(8x^3+12x^2+6x+1=0.\)
\(\Leftrightarrow\left(2x\right)^3+3.\left(2x\right)^2.1+3.2x.1^2+1^3=0\)
\(\Leftrightarrow\left(2x+1\right)^3=0\)
\(\Leftrightarrow2x+1=0\)
\(\Leftrightarrow x=-\frac{1}{2}\)
\(2x^2+5x-3=0\Leftrightarrow\left(2x^2+6x\right)+\left(-x-3\right)=0\)
\(\Leftrightarrow2x\left(x+3\right)-\left(x+3\right)=0\Leftrightarrow\left(x+3\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=0\\x+3=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{1}{2}\\x=-3\end{cases}}\)
\(x^2-2x-3=0\Leftrightarrow\left(x^2-3x\right)+\left(x-3\right)=0\)
\(\Leftrightarrow x\left(x-3\right)+\left(x-3\right)=0\Leftrightarrow\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=0\\x-3=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-1\\x=3\end{cases}.}\)
\(\left(5x-1\right)+2\left(1-5x\right)\left(4+5x\right)+\left(5x+4\right)^2\)
\(=5x-1+2\left(4+5x-20x-25x^2\right)+25x^2+40x+16\)
\(=25x^2+45x+15+8+10x-40x-50x^2\)
\(=-25x^2+15x+23\)
\(\left(x-y\right)^3+\left(y+x\right)^3+\left(y-x\right)^3-3xy\left(x+y\right)\)
\(=\left(x-y\right)^3-\left(x-y\right)^3+\left(x+y\right)^3-3x^2y-3xy^2\)
\(=\left(x+y\right)^3-3x^2y-3xy^2\)
\(=x^3+3x^2y+3xy^2+y^3-3xy^2-3x^2y\)
\(=x^3+y^3\)
\(2x^2-x+6x-3=0\)
\(\Leftrightarrow x.\left(2x-1\right)+3.\left(2x-1\right)=0\)
\(\Leftrightarrow\left(x+3\right).\left(2x-1\right)=0\)
....
^{4}&=x^{4}+4x^{3}y+6x^{2}y^{2}+4xy^{3}+y^{4},\\[8pt](x+y)^{5}&=x^{5}+5x^{4}y+10x^{3}y^{2}+10x^{2}y^{3}+5xy^{4}+y^{5},\\[8pt](x+y)^{6}&=x^{6}+6x^{5}y+15x^{4}y^{2}+20x^{3}y^{3}+15x^{2}y^{4}+6xy^{5}+y^{6},\\[8pt](x+y)^{7}&=x^{7}+7x^{6}y+21x^{5}y^{2}+35x^{4}y^{3}+35x^{3}y^{4}+21x^{2}y^{5}+7xy^{6}+y^{7}.\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/e30228a99653e6b9a65ae6640a3b7f85e2fdf144)
