tinh nhanh
\(25.4^2-18.3^2+2^3+19\)
Tinh nhanh:
25.6+25.4+25.18+25.12
Ai nhanh mk tick mk nhanh tick cho mk nha!!!!!!!!!!!!
25 . 6 + 25 . 4 + 25 . 18 + 25 . 12
= 25 . (6 + 4 + 18 + 12)
= 25 . 40
= 1000
25 x 6 + 25 x 4 + 25 x 18 + 25 x 12
= 25 x ( 6 + 4 + 18 + 12 )
= 25 x 40
= 1 000
ta có 25.6 + 25.4 + 25.18 + 25.12 = 25.( 6 + 4 +18 + 12 ) = 25.40 =1000
tính nhanh
31.15.72.4+31.49.40
4.24.52-(33.18.33.12}
tinh nhanh:
1+1+1+1+11+11+25.4+10+5+1
1+1+1+1+11+11+25.4+10+5+1
=4+11.2+25.4+10+6
=4+6+10+100+121
=10+10+221
=20+221
=241
k mình nha!
rut gon : Q= \(\frac{25.4^{15}.9^9-2^9.6^{20}}{15.2^{25}.3^{19}-11.2^{11}.6^{18}}\)
`\(=\frac{5.5.4^{15}.9^9-2^9.6^{18}.6^2}{5.3.4^{12}.2.9^9.3-2^9.2^2.6^{18}.11}\)
\(=\frac{5.4^3-6^2}{3.2.3-2^2.11}\)
\(=\frac{320-36}{18-44}\)
\(=\frac{-284}{26}=\frac{-142}{13}\)
Tinh nhanh
(100-1^2)(100-2^2)-(100-3^2)...(100-19^2)
Tinh nhanh
(100-12).(100-22).(100-32)...(100-192)
Giúp tớ vs Tính nhanh a) -3/25.4/17.5/-3.17/2 B)-8/15.13/16:13/30 C)3/11.2/9.-8/33+3/11.7/9 D)-11/25.2/3- -1/6+ -2/3.14/15(âm1/6)
a: \(\dfrac{-3}{25}\cdot\dfrac{4}{17}\cdot\dfrac{5}{-3}\cdot\dfrac{17}{2}=\dfrac{4}{17}\cdot\dfrac{17}{2}\cdot\dfrac{3}{25}\cdot\dfrac{5}{3}=2\cdot\dfrac{1}{5}=\dfrac{2}{5}\)
b: \(=-\dfrac{8}{15}\cdot\dfrac{13}{16}\cdot\dfrac{30}{13}=\dfrac{-8}{15}\cdot\dfrac{15}{8}=-1\)
c: \(=\dfrac{3}{11}\left(\dfrac{2}{9}\cdot\dfrac{-8}{33}+\dfrac{7}{9}\right)=\dfrac{3}{11}\cdot\dfrac{215}{297}=\dfrac{2015}{1089}\)
TINH nhanh
1+(-2)+3+(-4)+57+(-6)+....+19+(-20)
đề sai bn ơi
TINH nhanh
1+(-2)+3+(-4)+57+(-6)+....+19+(-20)
tại sao lại có số 57 ở đấy hả
1+(-2)+3+(-4)+...+19+(-20)
=[1+(-2)]+[3+(-4)]+...+[19+(-20)] (có 10 cặp)
= -1 . 10
= -10
~~~Hk tốt~~~
tinh nhanh
B=\(\dfrac{3}{1^{2^{ }}.2^2}+\dfrac{5}{2^2.3^2}+\dfrac{7}{3^{2^{ }}.4^2}+...+\dfrac{19}{9^2.10^2}\)
Lời giải:
\(B=\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+\frac{7}{3^2.4^2}+...+\frac{19}{9^2.10^2}\)
\(=\frac{2^2-1^2}{1^2.2^2}+\frac{3^2-2^2}{2^2.3^2}+\frac{4^2-3^2}{3^2.4^2}+...+\frac{10^2-9^2}{9^2.10^2}\)
\(=\frac{1}{1^2}-\frac{1}{2^2}+\frac{1}{2^2}-\frac{1}{3^2}+\frac{1}{3^2}-\frac{1}{4^2}+....+\frac{1}{9^2}-\frac{1}{10^2}\)
\(=1-\frac{1}{10^2}=\frac{10^2-1}{10^2}=\frac{99}{100}\)
Tinh nhanh
(100-12)(100-22)-(100-32)...(100-192)
cách 1
trong dãy trên sẽ có (100-102 ) mà 102 bằng 100
suy ra (100-102 ) = (100-100) =0
vậy tích trên bằng 100
cách 2 (trình bày)
=(100-12)(100-22)(100-32)...(100-192)
=(100-12)(100-22)(100-32)....(100-102).....(100-192)
=(100-12)(100-22)(100-32)....(100-100).....(100-192)
=(100-12)(100-22)(100-32)....0.....(100-192)
=0
vậy tích trên bằng 0