a) Ta có: \(\frac{3+x}{5+y}=\frac{3}{5}\)

=> (3 + x).5 = 3(5 + y)

=> 15 + 5x = 15 + 3y

=> 5x = 3y

=> x = 3/5y

Mà x + y = 16

hay 3/5y + y = 16

=> (3/5 + 1).y = 16

=> 8/5.y = 16

=> y = 16 : 8/5

=> y = 10

=> x = 16 - 10 = 6

Vậy x = 6; y = 10

b) Ta có: \(\frac{x-7}{y-6}=\frac{7}{6}\)

=> (x - 7).6 = 7.(y - 6)

=> 6x - 42 = 7y - 42

=> 6x = 7y

=> x = 7/6y

Mà x - y = -4

hay 7/6y - y = -4

=> 1/6y = -4

=> y = -4 : 1/6

=> y = -24

=> x = -4 - 24 = -28

Vậy x =  -28; y = -24

\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{12}\)

\(\frac{y}{z}=\frac{4}{5}\Rightarrow\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{y}{12}=\frac{z}{15}\)

nên :

\(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)

\(\Rightarrow\frac{x+y-z}{8+12-15}=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\) mà x + y - z = 10

\(\Rightarrow\frac{10}{5}=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)

\(\Rightarrow2=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)

\(\Rightarrow\hept{\begin{cases}x=2\cdot8=16\\y=2\cdot12=24\\z=2\cdot15=30\end{cases}}\)

vậy_

?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????//

a) \(\frac{x}{6}=\frac{5}{24}\Rightarrow x=\frac{5}{24}.6=\frac{5}{4}\)

b) \(-\frac{4}{y}=\frac{20}{14}\Rightarrow y=-4:\frac{20}{14}=-\frac{14}{5}\)

c) \(\frac{4}{7}=\frac{12}{x}\Rightarrow x=12:\frac{4}{7}=21\)

d) \(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3}{7}.21=9\)

a)-6x=6

x=-1

b)8x=35->x=35/8

c)8|x|=35->|x|=35/2->x=35/2;x=-35/2

mấy ý kia tương tự bạn ạ!

Các bạn giải bài 2 trước đi,  năn nỉ mà!!!

Bài làm:

\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).y=\frac{2}{3}\)

\(\Leftrightarrow\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).y=\frac{4}{3}\)

\(\Leftrightarrow\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+\frac{9-7}{7.9}+\frac{11-9}{9.11}\right).y=\frac{4}{3}\)

\(\Leftrightarrow\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).y=\frac{4}{3}\)

\(\Leftrightarrow\left(1-\frac{1}{11}\right).y=\frac{4}{3}\)

\(\Leftrightarrow\frac{10}{11}.y=\frac{4}{3}\)

\(\Leftrightarrow y=\frac{4}{3}:\frac{10}{11}=\frac{4}{3}.\frac{11}{10}=\frac{22}{15}\)

Chú ý dấu \(\left(.\right)\)là dấu \(\left(\times\right)\)

Vậy \(y=\frac{22}{15}\)

\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).y=\frac{2}{3}\)

\(\Leftrightarrow\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)

\(\Leftrightarrow\frac{1}{2}.\left(1-\frac{1}{11}\right).y=\frac{2}{3}\)

\(\Leftrightarrow\frac{1}{2}.\frac{10}{11}.y=\frac{2}{3}\)

\(\Leftrightarrow\frac{5}{11}.y=\frac{2}{3}\)

\(\Rightarrow y=\frac{2}{3}:\frac{5}{11}=\frac{22}{15}\)

LƯU Ý:các dấu chấm(.) là dấu nhân ^^.

(\(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}\)) *y = \(\frac{2}{3}\)