a

\(xy+3x-7y-21\\ =\left(xy+3x\right)-\left(7y+21\right)\\ =x\left(y+3\right)-7\left(y+3\right)\\ =\left(y+3\right)\left(x-7\right)\)

b

\(2xy-15-6x+5y\\ =\left(2xy-6x\right)-\left(15-5y\right)\\ =2x\left(y-3\right)-5\left(3-y\right)\\ =2x\left(y-3\right)+5\left(y-3\right)\\ =\left(y-3\right)\left(2x+5\right)\)

c Đề phải là \(\left(2x^2y+2xy^2-x-y\right)\) mới phân tích được: )

\(=2xy\left(x+y\right)-\left(x+y\right)\\ =\left(x+y\right)\left(2xy-1\right)\)

d

\(7x^3y-3xyz-21x^2+9z\\ =\left(7x^3y-21x^2\right)-\left(3xyz-9z\right)\\ =7x^2\left(xy-3\right)-3z\left(xy-3\right)\\ =\left(xy-3\right)\left(7x^2-3z\right)\)

e

\(4x^2-2x-y^2-y\\ =\left(2x\right)^2-y^2-\left(2x+y\right)\\ =\left(2x-y\right)\left(2x+y\right)-\left(2x+y\right)\\ =\left(2x+y\right)\left(2x-y-1\right)\)

f

\(9x^2-25y^2-6x+10y\\ =\left(3x\right)^2-\left(5y\right)^2-\left(6x-10y\right)\\ =\left(3x-5y\right)\left(3x+5y\right)-2\left(3x-5y\right)\\ =\left(3x-5y\right)\left(3x+5y-2\right)\)

a: =x(y+3)-7(y+3)

=(y+3)(x-7)

b: \(=2xy-6x+5y-15\)

=2x(y-3)+5(y-3)

=(y-3)(2x+5)

c: \(=2xy\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(2xy-1\right)\)

d: \(=xy\left(7x^2-3z\right)-3\left(7x^2-3z\right)\)

=(7x^2-3z)(xy-3)

e: =4x^2-y^2-2x-y

=(2x-y)(2x+y)-(2x+y)

=(2x+y)(2x-y-1)

f: =(3x-5y)(3x+5y)-2(3x-5y)

=(3x-5y)(3x+5y-2)

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

a)67/63 x 15/3 + 15/31 x 11/21

Thiếu đề

b)15/31 x 34/63 - 11/21 x 15/31

=15/31 x ( 34/63 -11/21)

= 15/31 x  1/63=  5/651

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: 

(x-15):5+20=22

(x-15):5=22-20

(x-15):5=2

x-15=2x5

x-15=10

x=10+15

x=25

64+(20-3x)=75

20-3x=75-64

20-3x=11

3x=20-11

3x=9

x=9:3

x=3

[(6x-39):3].28=5628

(6x-39):3=5628:28

(6x-39):3=201

6x-39=201x3

6x-39=603

6x=603+39

6x=642

x=642:6

x=107

400-[545-(45+x)]=0

545-(45+x)=400-0

545-(45+x)=400

45+x=545-400

45+x=145

x=145-45

x=100

(111:x+25):14=2

111:x+25=2x14

111:x+25=28

111:x=28-25

111:x=3

x=111:3

x=37

a/ \(\Rightarrow\left(x-15\right):5=2\Rightarrow x-15=10\Rightarrow x=25\)

b/ \(\Rightarrow20-3x=11\Rightarrow3x=9\Rightarrow x=3\)

c/ => \(\left(6x-39\right):3=201\Rightarrow6x-39=603\Rightarrow6x=642\Rightarrow x=107\)

d/ \(\Rightarrow545-\left(45+x\right)=400\Rightarrow45+x=145\Rightarrow x=100\)

e/ \(\Rightarrow111:x+25=28\Rightarrow111:x=3\Rightarrow x=\frac{111}{3}\)

a,-4/7=x/21
-12/21 = x/21
x= -12 

b,(x-3)/15=1/-5
x - 3 = -1/5 * 15
x - 3 = -3
x = 0

c,.(3x+8)/-12=-5/30
=> 3x + 8 = 2
=> 3x=-6
=>x=-2

Giups mình với !

Mai mình phải nộp rồi >o<

a) 25 + 3x = 25 - 1

3x = -1

x = -1/3

b) (6x-39):13 = 201

6x-39 = 2613

6x = 2652

x = 442

c) 2^x + 3⁵:3⁴ = 5¹⁰ : 5⁸

2^x + 3 = 25

2^x = 22

...

a) 25+3.x=25-1

    25+3.x=24

         3.x=24-25

         3.x=-1

           x=-1:3

           x=-1/3

b)(6x-39):13=201

          6x-39=201.13

          6x-39=2613

          6x     =2682

            x     =2682:6

                 x=447

c)2^x+3⁵:3⁴=5¹⁰:5⁸

2^x+3=5²

2^x=25-3

2^x=22

=>x\(\in\varnothing\)

a: 2x-261=-21

=>\(2x=-21+261=240\)

=>\(x=\dfrac{240}{2}=120\)

b: \(15\cdot\left(-2\right)-x=45\)

=>-30-x=45

=>x=-30-45=-75

c: \(-18+\left(7-x\right)^2=-2\)

=>\(\left(x-7\right)^2-18=-2\)

=>\(\left(x-7\right)^2=-2+18=16\)

=>\(\left[{}\begin{matrix}x-7=4\\x-7=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=3\end{matrix}\right.\)

d: \(2x-1⋮x+1\)

=>\(2x+2-3⋮x+1\)

=>\(-3⋮x+1\)

=>\(x+1\inƯ\left(-3\right)\)

=>\(x+1\in\left\{1;-1;3;-3\right\}\)

=>\(x\in\left\{0;-2;2;-4\right\}\)

   a,A=-(8a+21b-45)+(23a-11b-54)-(-32a-61b-11)

= -8a + 21b - 45 + 23a - 11b - 54 +32a -61b - 11

=47a - 51b - 110

b,B=-3(12a-21b+23)-4(-22a+15b-41)+(-11a-b+29)

=-36a + 63b - 69 + 88a - 60b + 164 - 11a - b + 29

=41a + 2b + 124

c,C=(-18a-43b+49)-2(54a-27b+25)+3(-15a+22b-17)

=-18a - 43b +49 - 108a + 54b - 50 - 45a + 66b - 51

=-171a + 77b - 52

BN KACURA GIỎI QUÁ!