a.12x+19x-123=280

12x+19x =280+123

12x+19x =403

31x =403

x=403:31

x=13

b. 5-(17-3)=x-(2-15)

5-14 =x-(-13)

-9 =x+13

=> x=(-9)-13=-22

Tìm x:

a. 12x + 19x - 123 = 280

(12 + 19).x - 123 = 280

31.x - 123 = 280

31.x = 280 + 123

31.x = 403

x = 403 : 31

x = 13

b) 5 - (17 - 3) = x - (2 - 15)

5 - 14 = x - (-13)

(- 9) = x + 13

=> x = (-9) - 13 = -22

Lời giải:

a.

$12x+19x-123=280$

$31x=280+123$

$31x=403$

$x=403:31=13$

b.

$5-(17-3)=x-(2-5)$

$-9=x-(-3)$

$x=(-9)+(-3)=-12$

a: ĐKXD: x<>0

\(\dfrac{14x^3+12x^2-14x}{2x}=\left(x+2\right)\left(3x-4\right)\)

=>\(\dfrac{2x\left(7x^2+6x-7\right)}{2x}=\left(x+2\right)\left(3x-4\right)\)

=>\(7x^2+6x-7=3x^2-4x+6x-8\)

=>\(7x^2+6x-7=3x^2+2x-8\)

=>\(4x^2+4x+1=0\)

=>\(\left(2x+1\right)^2=0\)

=>2x+1=0

=>x=-1/2(nhận)

b: \(\left(4x-5\right)\left(6x+1\right)-\left(8x+3\right)\left(3x-4\right)=15\)

=>\(24x^2+4x-30x-5-\left(24x^2-32x+9x-12\right)=15\)

=>\(24x^2-26x-5-24x^2+23x+12=15\)

=>-3x+7=15

=>-3x=8

=>\(x=-\dfrac{8}{3}\)

c)   \(\left(x+1\right)\left(x+2\right)\left(x+4\right)\left(x+5\right)=40\)

\(\Leftrightarrow\)\(\left(x^2+6x+5\right)\left(x^2+6x+8\right)-40=0\)

Đặt      \(x^2+6x+5=t\)   ta có:

                       \(t\left(t+3\right)-40=0\)

          \(\Leftrightarrow\)\(t^2+3t-40=0\)

          \(\Leftrightarrow\)\(\left(t-5\right)\left(t+8\right)=0\)

        \(\Leftrightarrow\)\(\orbr{\begin{cases}t-5=0\\t+8=0\end{cases}}\)

Thay trở lại ta có:      \(\orbr{\begin{cases}x^2+6x=0\\x^2+6x+13=0\end{cases}}\)

(*)     \(x^2+6x=0\)

 \(\Leftrightarrow\)\(x\left(x+6\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=0\\x+6=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=0\\x=-6\end{cases}}\)

(*)   \(x^2+6x+13=0\)

\(\Leftrightarrow\)\(\left(x+3\right)^2+4=0\)  (vô lý)

Vậy......

<=> 31x=80+123
<=> 31x=203
<=> x=203/31

=31x-123=80

vậy 31x=80+123

=203

x=203;31

=

1)

a) \(\left(-175\right)-123+3+175+\left(-3\right)\)

\(=\left[\left(-175\right)+175\right]+\left[3+\left(-3\right)\right]-123\)

\(=0+0-123\)

\(=-123\)

b) \(17.85+15.17-150\)

\(=17.\left(85+15\right)-150\)

\(=17.100-150\)

\(=1700-150\)

\(=1550\)

c) \(176:\left(4.5^2-3.2^2\right)\)

\(=176:\left(4.25-3.4\right)\)

\(=176:\left(100-12\right)\)

\(=176:88\)

\(=2\)

2)

a) \(8-x=-12\)

\(\Rightarrow x=8-\left(-12\right)\)

\(\Rightarrow x=8+12\)

\(\Rightarrow x=20\)

Vậy \(x=20\)

b) \(20+2^3.x=5^2.4\)

\(\Rightarrow20+8.x=25.4\)

\(\Rightarrow20+8.x=100\)

\(\Rightarrow8.x=100-20\)

\(\Rightarrow8.x=80\)

\(\Rightarrow x=80:8\)

\(\Rightarrow x=10\)

Vậy \(x=10\)

c) \(2\left|x-1\right|+5=15\)

\(\Rightarrow2\left|x-1\right|=15-5\)

\(\Rightarrow2\left|x-1\right|=10\)

\(\Rightarrow\left|x-1\right|=10:2\)

\(\Rightarrow\left|x-1\right|=5\)

Xét trường hợp 1: \(x-1=5\)

\(\Rightarrow x=5+1\)

\(\Rightarrow x=6\)

Xét trường hợp 2: \(x-1=-5\)

\(\Rightarrow x=\left(-5\right)+1\)

\(\Rightarrow x=-5+1\)

\(\Rightarrow x=-\left(5-1\right)\)

\(\Rightarrow x=-4\)

Vậy \(x=6\) hoặc \(x=-4\)

Bài 1:

\(a)\left(-175\right)-123+3+175+\left(-3\right)\)

\(=\left[\left(-175\right)+175\right]+\left[\left(-3+3\right)\right]-123\)

\(=0+0-123\)

\(=-123\)

\(b)17.85+15.17-150\)

\(=17.\left(85+15\right)-150\)

\(=17.100-150=1700-150=1550\)

\(c)176:\left(4.5^2-3.2^2\right)\)

\(=176:\left(4.25-3.4\right)\)

\(=176:\left(100-12\right)=176:88=2\)

Bài 2:

\(a)8-x=-12\)

\(\Rightarrow x=8-\left(-12\right)\)

\(\Rightarrow x=20\)

\(b)20+2^3.x=5^2.4\)

\(\Rightarrow20+8.x=25.4\)

\(\Rightarrow20+8.x=100\)

\(\Rightarrow8.x=100-20\)

\(\Rightarrow8.x=80\)

\(\Rightarrow x=80:8=10\)

\(c)2\left|x-1\right|+5=15\)

\(\Rightarrow2\left|x-1\right|=15-5\)

\(\Rightarrow2\left|x-1\right|=10\)

\(\Rightarrow\left|x-1\right|=10:2\)

\(\Rightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)

c) (x+1)(x+2)(x+4)(x+5)=40

<=> (x+1)(x+5)(x+2)(x+4)=40

<=>(x^2+6x+5)(x^2+6x+8)=40

Đặt x^2+6x+5=y

=>y(y+3)=40

=>y^2+3y=40<=>y^2+2.\(\frac{3}{2}\)y+\(\frac{9}{4}\)=40+\(\frac{9}{4}\)<=> (y+\(\frac{3}{2}\))²=42,25<=> y+\(\frac{3}{2}\)=6,5 hoặc -6,5

Bạn tự làm tiếp nha :333

a)x⁴ - 4x³ - 19x² +106x - 120 = 0

=>x⁴ -2x³ -2x³+4x² -23x² +46x +60x - 120 = 0

=>x³(x-2) -2x²(x-2) -23x(x-2) +60(x-2)= 0

=>(x³- 2x² -23x+ 60)(x-2) =0

=>(x³ - 3x² +x² -3x -20x+60)(x -2) = 0

=>(x² +x -20)(x-3)(x-2) = 0

=>(x² -4x +5x -20)(x-3)(x-2) = 0

=>(x+5)(x-4)(x-3)(x-2) =0

=>x= -5; 4; 3; 2

b)=>4x⁴ -4x³ +16x³ -16x² +21x² -21x +15x -15= 0

=>(x-1)(4x³ +16x² +21x+15)= 0

=>...bạn tự làm phần tiếp theo nhé

c)Làm giống nguyễn thị ngọc linh