Tính tổng: S = 2020 + 2019 – 2018 – 2017 + 2016 + 2015 – 2014 – 2013 + … + 4 + 3 – 2 – 1 . Vậy S = .................
Những câu hỏi liên quan
HÃY TÌM KẾT QUẢ CỦA PHÉP TÍNH "2022+2020-2019-2018-2017+2016+2015 +2014-2013-2012-2011+...+6+5+ 4-3-2-1"
\(...=2022+2020+\left(-2019+2016-2018+2015-2017+2014\right)+...+\left(6-3+5-2+4-1\right)\)
\(=2022+2020+\left(-3-3-3\right)+\left(-3-3-3\right)+...+\left(-3-3-3\right)+\left(-3-2-1\right)\)
\(=2022+2020+\left(-9\right)+\left(-9\right)+...\left(-9\right)+\left(-6\right)\)
\(=2022+2020+\left(-9\right).\left[\left(2019-9\right):6+1\right].\left[\left(2019+6\right)\right]:2+\left(-6\right)\)
\(=2022+2020+\left(-9\right).336.2025:2+\left(-6\right)\)
\(=2022+2020-3061800-6\)
\(=-3057764\)
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tính
2011 + 2012 + 2013 + 2014 + 2015 + 2016 + 2017 + 2018 + 2019+ 2020 + 2021 +2022 +2023
2011+2012+2013+2014+2015+2016+2017+2018+2019+2020+2021+ 2022+2023 =(2011+2023)+(2013+2022)+...+(2016+2018)+2017 =4034+4034+4034+4034+4034+4034+2017 =4034x6+2017=26221
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2011+2012+2013+2014+2015+2016+2017+2018+2019+2020+2021+2022+2023
=(2011+2023)+(2013+2022)+...+(2016+2018)+2017 =4034+4034+4034+4034+4034+4034+2017 =4034x6+2017=26221
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Cho S = 2 mũ 2020 + 2 mũ 2019+ 2 mũ 2018+ 2 mũ 2017+2 mũ 2016+2 mũ 2015 +2 mũ 2014+ 2 mũ 2013.
Chứng tỏ rằng S chia hết cho 15 ?
Ta có : S=22020+22019+22018+22017+22016+22015+22014+22013
=22013(27+26+25+24+23+22+2+1)
=22013.255
Vì 255\(⋮\)15 nên 22013.255\(⋮\)15
hay S\(⋮\)15
Vậy S\(⋮\)15.
1+2-3-4-5+6+7-8-9-10+11+12-13-14-15+...+2011+2012-2013-2014-2015+2016+2017-2018-2019-2020 giup mik v
Lời giải:
$A=(1+2-3-4-5)+(6+7-8-9-10)+(11+12-13-14-15)+....+(2011+2012-2013-2014-2015)+(2016+2017-2018-2019-2020)$
$=(-9)+(-14)+(-19)+....+(-2019)+(-2024)$
$=-(9+14+19+...+2019+2024)$
Số số hạng: $(2024-9):5+1=404$
$A=-(2024+9).404:2=-410666$
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a, 921 + [ 97 + (-921) + ( -47)
b, 2013 + 2014 + 2015+ 2016 + ( -2017) + (-2018) + (-2019) + (-2020)
a, 921 + [ 97 + (-921) + ( -47)]
= 921 + 97 - 921 - 47
= (921 - 921) + (97 - 47)
= 50
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b, 2013 + 2014 + 2015+ 2016 + ( -2017) + (-2018) + (-2019) + (-2020)
= 2013 + 2014 + 2015 + 2016 - 2017 - 2018 - 2019 - 2020
= (2013 - 2017) + (2014 - 2018) + (2015 - 2019) + (2016 - 2020)
= -4 - 4 - 4 - 4
= -16
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Bài làm
a) 921 + [ 97 + (-921) + ( -47) ]
= 921 + 97 + ( -921 ) + ( -47 )
= [ 921 + ( -921 ) ] + [ 97 + ( -47 ) ]
= 0 + 50
= 50
b) 2013 + 2014 + 2015+ 2016 + ( -2017) + (-2018) + (-2019) + (-2020)
= [ 2013 + ( -2017 ) ] + [ 2014 + ( -2018 ) ] + [ 2015 + ( -2019 ) ] + [ 2016 + ( -2020 ) ]
= -4 + ( -4 ) + ( -4 ) + ( -4 )
= -16
# Chúc bạn học tốt #
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Xem thêm câu trả lời
Tính tổng
S= 2+(-3)+4+(-5)+6+(-7)+............ + 2016+(-2017)+2018+(-2019)+2020
S= 2+(-3)+4+(-5)+6+(-7)+............ + 2016+(-2017)+2018+(-2019)+2020
S=[2+(-3)]+[4+(-5)]+[6+(-7)]+...+[2016+(-2017)]+[2018+(-2019)]+2020
S=-1+(-1)+(-1)+...+(-1)+2020 (Có 1009,5 số -1 )
S=-1.1009,5+2020
S=-1009,5+2020
S=1010,5
tính tổng S= (1/2018!)+(1/3!2016!)+(1/5!2014!)+...+(1/2017!2!)+(1/2019!)
\(S=\dfrac{1}{2018!\left(2019-2018\right)!}+\dfrac{1}{2016!\left(2019-2016\right)!}+...+\dfrac{1}{2!\left(2019-2\right)!}+\dfrac{1}{0!\left(2019-0!\right)}\)
\(\Rightarrow2019!.S=\dfrac{2019!}{2018!\left(2019-2018\right)!}+\dfrac{2019!}{2016!\left(2019-2016\right)!}+...+\dfrac{2019!}{2!\left(2019-2\right)!}+\dfrac{2019!}{0!\left(2019-0\right)!}\)
\(=C_{2019}^{2018}+C_{2019}^{2016}+...+C_{2019}^2+C_{2019}^0\)
\(=\dfrac{1}{2}\left(C_{2019}^0+C_{2019}^1+...+C_{2019}^{2018}+C_{2019}^{2019}\right)\)
\(=\dfrac{1}{2}.2^{2019}=2^{2018}\)
\(\Rightarrow S=\dfrac{2^{2018}}{2019!}\)
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Tính tổng các số sau:
a,S=1-2+3-4+...+2015-2016
b,S=1-3+5-7+...+2011-2013
c,S=2-4+6-8+...+2018-2020
a) S=1-2+3-4+...+2015-2016
=(1-2)+(3-4)+...+(2015-2016) (có tất cả 1008 cặp)
=(-1)+(-1)+...+(-1)
=(-1).1008=-1008
Phần b và c tương tự
Học tốt!
#Huyền#
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/1)+(2019/2)+(2019/3)+(2019/4)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]