thu gon bieu thuc
(x+1)^3-x(x^2+3)
Những câu hỏi liên quan
thu gon bieu thuc sau (2x-1)^3-(3x^2-1)(x-2)-(x+3)^3
Ta có: \(\left(2x-1\right)^3-\left(3x^2-1\right)\left(x-2\right)+\left(x+3\right)^3\)
\(=8x^3-12x^2+6x-1-\left(3x^3-6x^2-x+2\right)+x^3+9x^2+27x+27\)
\(=9x^3-3x^2+33x+26-3x^3+6x^2+x-2\)
\(=6x^3+3x^2+34x+24\)
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Thu gon bieu thuc:
E=|x-3|+|x2+1|-x (x-1)
Giai phuong trinh giup minh
Cho bieu thuc B=(1/x-3-1/x^2-9)*(1/x+2+1)
Tim ĐKXĐ cua B
Rut gon B
TIm x nguyen de bieu thuc B co gia tri nguyen
a: ĐKXĐ: \(x\notin\left\{3;-3;-2\right\}\)
b: \(B=\dfrac{x+3-1}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+2+1}{x+2}\)
\(=\dfrac{x+2}{\left(x-3\right)\left(x+3\right)}\cdot\dfrac{x+3}{x+2}=\dfrac{1}{x-3}\)
c: Để B nguyên thì \(x-3\in\left\{1;-1\right\}\)
hay \(x\in\left\{4;2\right\}\)
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rut gon bieu thuc tren (x-1)^3-(x-1).(x^2+x+1)
Lời giải:
$(x-1)^3-(x-1)(x^2+x+1)=(x-1)[(x-1)^2-(x^2+x+1)]=(x-1)(x^2-2x+1-x^2-x-1)=(x-1)(-3x)=-3x(x-1)$
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rut gon bieu thuc :P=5x(x-3)(x+3)-(2x-3)^2+34x(x+2)-5(x+2)^3+25x-1
\(:P=5x(x-3)(x+3)-(2x-3)^2+34x(x+2)-5(x+2)^3+25x-1\)
\(P=5x(x^2-9)-(4x^2-12x+9)+34x^2+68x-5(x^3+6x^2+12x+8)+25-1\)
\(P=5x^3-45x-4x^2+12x-9+34x^2+68x-5x^3-30x^2-60x-40+25-1\)
\(P=(5x^3-5x^3)+(34x^2-4x^2-30x^2)+(12x-45x++68x+25x-60x)-(9+1)\)
\(P=-10\)
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B1: rut gon bieu thuc
a, (x+y)^2-4(x-y)^2
b, 2(x-y)(x+y)+(x+y)^2+(x-y)^2
B2: tim X
a, (2X-1)^2-4(X+2)^2=9
b, 3(X-1)^2-3X(X-5)=21
B3: Cho bieu thuc
M=(x+3)^3-(x-1)^3+12x(x-1)
a, Rut gon bieu thuc tren
b, Tinh gia tri M tai x=-2/3
c, Tim x de M=16
1)a)=>x2+y2+2xy-4(x2-y2-2xy)
=>x2+y2+2xy-4.x2+4y2+8xy
=>-3.x2+5y2+10xy
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Ai giup m voi: Thu gon roi tinh bieu thuc sau:
C= x^5 - 5x^4 + 5x^3 - 5x^2 + 5x -1 voi x=4
Dễ thấy 5=4+1=x+1
Thay vào C,ta có:
\(C=x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x-1\)
\(=x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x-1=x-1=4-1=3\)
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thu gon bieu thuc |2x+3|-x=1
giúp mk gấp nha
thanks
\(\left|2x+3\right|-x=1\)
\(\Leftrightarrow\orbr{\begin{cases}2x+3=x+1\\2x+3=-x-1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-x=1-3\\2x+x=-1-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\3x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=-\frac{4}{3}\end{cases}}\)
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1) Cho bieu thuc A=\(3+\frac{2}{x-1}\). Tinh gia tri cua bieu thuc A khi |2x-3|=1
2) Rut gon bieu thuc B=\(\frac{x}{x-1}\)-\(\frac{x-5}{x+1}\)-\(\frac{3-x}{1-x^2}\)
3) Tim cac gia tri nguyen cua x de bieu thuc \(\frac{B}{A}\)co gia tri nguyen duong