( 500 x 9 - 250 x 2 x 9 ) x ( 1 + 2 + 3 .... +9 )
(500 x 9 - 250 x 18) x (1 + 2 + 3 + .... + 9)
a. (72 - 8 x9 ) : ( 20 + 21 + 22 + 23 + 24 + 25)
b. (500 x 9 - 250 x18 ) x (1 + 2 + 3 + ...+9)
c. (11 + 13 + 15 + ...+ 19) x (6 x 8 - 48)
a) ( 72 - 8x9 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= ( 72 - 72 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0 : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0
b) ( 500 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 250 x 2 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 250 x 18 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= 0 x ( 1 + 2 + 3 + ... + 9 )
= 0
c ) ( 11 + 13 + 15 + ... + 19 ) x ( 6 x 8 - 48 )
= ( 11 + 13 + 15 + ... + 19 ) x ( 48 - 48 )
= ( 11 + 13 + 15 + ... + 19 ) x 0
= 0
a) ( 72 - 8x9 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= ( 72 - 72 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0 : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0
b) ( 500 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 250 x 2 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 250 x 18 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= 0 x ( 1 + 2 + 3 + ... + 9 )
= 0
a. (72 - 8 x9) : (20 + 21 + 22 + 23 + 24 + 25)
b. (500 x 9 - 250 x 18 ) x (1 + 2 + 3 + ...+ 9)
c. (11 + 13 + 15 + ...+ 19) x (6 x 8 - 48)
Ủa bạn chép vndoc hả, mình cũng vậy
k) 4 x 113 x 25 - 5 x 112 x 20
p) 1235 x 6789 x ( 630 - 315 x 2 ) :1996
l) 54 x 113 + 45 x 113 + 113
u) ( 500 x 9 - 250 x 18 ) x ( 1 +2 +3 +.......+ 9 )
k) 4 x 113 x 25 - 5 x 112 x 20
= (4 x 25) x 113 - (5 x 20) x 112
= 100 x 113 - 100 x 112
= 100 x (113 - 112)
= 100
p) 1235 x 6789 x (630 - 315 x 2) : 1996
= 1235 x 6789 x (630 - 630) : 1996
= 1235 x 6789 x 0 : 1996
= 0
l) 54 x 113 + 45 x 113 + 113
= 113 (54 + 45 + 1)
= 113 x 100
= 11300
u) (500 x 9 - 250 x 18) x (1 + 2 + 3 + ... + 9)
= (2 x 250 x 9 - 250 x 2 x 9) x (1 +2 + 3 + ... + 9)
= 0 x (1 + 2 + 3 + ... + 9)
= 0
Tính nhanh
a. (72 - 8 x9) : (20 + 21 + 22 + 23 + 24 + 25)
b. (500 x 9 - 250 x 18 ) x (1 + 2 + 3 + ...+ 9)
c. (11 + 13 + 15 + ...+ 19) x (6 x 8 - 48)
Trả lời từng bước cho mình nhé(ai đúng mình tick.)
a) ( 72 - 8 x 9 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= ( 72 - 72 ) : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0 : ( 20 + 21 + 22 + 23 + 24 + 25 )
= 0
b) ( 500 x 9 - 250 x 18 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 500 x 9 - 250 x 2 x 9 ) x ( 1 + 2 + 3 + ... + 9 )
= ( 500 x 9 - 500 x 9 ) x ( 1 + 2 + 3 + ... + 9 )
= 0 x ( 1 + 2 + 3 + ... + 9 )
= 0
a)=(72-72):(20+.....+25)
=0:(20+.......+25)
=0
b)=(4500-4500)*(1+........+9)
=0*(1+........+9)
=0
c)=(11+.............+19)*(48-48)
=(11+...........+19)*0
=0
a)=(72-72):(20+21+22+....)=0:(20+21+......)=0
b)=(4500-4500)x(1+2+3+...+9)=0x(1+2+3+...+9)=0
c)=(11+13+15+....+19)x(48-48)=911+13+15+..+19)x0=0
Tìm x ϵ N,biết
a)22+x.5-43=251
b)1+23+33-42-x=20
c)x-4300-(5250:1050:250)=4250
d)460-85.4=(x+200):4
e)4.120+[45:9+15.(x+1)]=500
Các bạn giúp mình nha thanks
a: \(\Leftrightarrow5x-42=251\)
=>5x=293
hay x=293/5
b: \(\Leftrightarrow20-x=20\)
hay x=0
c: \(\Leftrightarrow x-4300-\dfrac{1}{50}=4250\)
\(\Leftrightarrow x=\dfrac{427501}{50}\)
d: =>(x+200):4=460-340=120
=>x+200=480
hay x=280
e: =>5+15(x+1)=500-480=20
=>15(x+1)=15
=>x+1=1
hay x=0
1,Tính
a, (1/4)^3.4^3
b, 1000^4/250^4
d, 2^2.9.1/54.(4/9)^2
2, Tìm x thuộc Q, biết
a, 2^x = 9
b, x^2=9
c,(x+1)^2=4
\(\left(\frac{1}{4}\right)^3\cdot4^3=\left(\frac{1}{4}\cdot4\right)^3=1^3=1\)
\(\frac{1000^4}{250^4}=4^4=256\)
\(2^2\cdot9\cdot\frac{1}{54}\cdot\left(\frac{4}{9}\right)^2=2^2\cdot3^2\cdot2\cdot3^3\cdot\left(\frac{4}{9}\right)^2=\left[\left(2\cdot3\cdot\frac{4}{9}\right)^2\right]\cdot2\cdot3^3=\frac{64}{9}\cdot2\cdot27=384\)
2. a) 2x = 9 => x không thỏa mãn
b) x2 = 9 => x = \(\pm\)3
c) (x + 1)2 = 4 => (x + 1)2 = \(\pm\)22
=> \(\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}\)
Bài 1 :
\(a,\left(\frac{1}{4}\right)^3.4^3\)
\(=\frac{1}{4^3}.4^3\)
\(=1\)
\(b,\frac{1000^4}{250^4}=\frac{\left(250.4\right)^4}{250^4}=\frac{250^4.4^4}{250^4}=4^4=256\)
\(d,2^2.9.\frac{1}{54}.\left(\frac{4}{9}\right)^2\)
\(=36.\frac{1}{54}.\frac{4^2}{9^2}\)
\(=\frac{18.2.16}{18.3.81}\)
\(=\frac{32}{243}\)
Bài 2 :
\(a,2^x=9\)
\(\Rightarrow\)x không thỏa mãn
\(b,x^2=9\)
\(\Rightarrow x^2=3^2\)
\(\Rightarrow\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
\(c,\left(x+1\right)^2=4\)
\(\Rightarrow\left(x+1\right)^2=2^2\)
\(\Rightarrow\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}\)
Học tốt
Làm lại câu d , xin lỗi bạn vì sự nhầm lẫn
\(2^2\cdot9\cdot\frac{1}{54}\cdot\left(\frac{4}{9}\right)^2=4\cdot9\cdot\frac{1}{54}\cdot\frac{16}{81}\)
\(=36\cdot\frac{1}{54}\cdot\frac{16}{81}=2\cdot\frac{1}{3}\cdot\frac{16}{81}=\frac{32}{81}\cdot\frac{1}{3}=\frac{32}{243}\)
Bài 1c, ( 500 x 9 - 250x 18 ) x ( 1 + 2 +.....+ 9 )
(500 x 9 - 250 x 18) x (1 + 2 + 3 + ... + 9)
= (250 x 2 x 9 - 250 x 18) x (1 + 2 + 3 + ... + 9)
= (250 x 18 - 250 x 18) x (1 + 2 + 3 + .. + 9)
= 0 x (1 + 2 + 3 +... +9)
= 0
= ( 500 × 9 - 250 × 2 ×9 ) × ( 1 + 9 ) × 9 : 2
= (500 × 9 - 500 ×9 ) × 45
= 0 × 45
0
( 500 x 9 - 250 x 18 ) x ( 1 + 2 + ... + 9 )
= ( 500 x 9 - 250 x 2 x 9 ) x ( 1 + 2 + ... + 9 )
= ( 500 x 9 - 500 x 9 ) x ( 1 + 2 + ... + 9 )
= 0 x ( 1 + 2 + ... + 9 )
= 0
Rất vui vì giúp đc bạn <3
Tìm x, y biết
a) 2016^1-|y-1|-x^2.3^1000=9^500 (x, y thuộc Z)
b) |x+0,1|+|x+0,2|+...+|x+0,9|=10x
c)5|3-x|+2015(x^2-9)^2016≤0
d) 3^x+9.4^x=12^x+9 (x thuộc N)
Mình cần gấp trong hôm nay, giúp mình với