giải các phương trình sau :
a) \(\frac{1}{x^2+4x+4}+\frac{2}{x^2+4x+5}=\frac{6}{x^2+4x+6}\)
b) \(\left(x+2\right)^2+\left(\frac{x+2}{x+1}\right)^2=8\)
B1 :Giải phương trình
a,\(\frac{3\left(x-3\right)}{4}-1=\frac{2x+3\left(x+1\right)}{6}-\frac{7+12x}{12}\)
b,\(\left(x+2\right)\left(3-4x\right)=x^2+4x+4\)
c,\(\frac{x-2}{x+2}-\frac{3}{x-2}=\frac{2\left(x-11\right)}{x^2-4}\)
d,I7-xI-5x=1
B2:Giải bất phương trình
a,\(\left(x-2\right)\left(x+2\right)\ge x\left(x-4\right)\)
b,\(\frac{x-1}{4}-1\ge\frac{x+1}{3}+8\)
GIẢI PHƯƠNG TRÌNH SAU
A) \(\frac{X^2+2X+1}{X^2+2X+2}+\frac{X^2+2X+2}{X^2+2X+3}=\frac{7}{6}\)
B) \(\frac{\left(X^2-3X-4\right)^4}{\left(X-3\right)^5\left(X+2\right)^3}+\frac{\left(X^2+4X+3\right)^6}{\left(X-3\right)^3\left(X+2\right)^5}=0\)
Giải các phương trình,bất phương trình:
c,\(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right)\left(2x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}=0\)
d,\(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
e,\(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}=0\)
g,\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
h,\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
i,\(\left(2x-5\right)^2-\left(x+2\right)^2=0\)
k,\(\left(3x^2+10x-8\right)^2=\left(5x^2-2x+10\right)^2\)
l,\(\left(x^2-2x+1\right)-4=0\)
m,\(4x^2+4x++1=x^2\)
Xin đáy ai giúp mình đi
Giải phương trình:
a. \(\frac{x+4}{x^2-3x+2}-\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
b. \(\frac{1}{x-1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
c. \(\frac{x+2}{3\:\:}+\frac{3\left(2x-1\right)}{4}-\frac{5x-3}{6}=x+\frac{5}{12}\)d. \(\frac{6}{x^2-1}+5=\frac{8x-1}{4x+4}-\frac{12x-1}{4-4x}\)
b, \(\frac{1}{x-1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\left(ĐKXĐ:x\ne\pm1;x\ne2\right)\)
\(\Leftrightarrow\)\(\frac{1}{x-1}+\frac{5}{2-x}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
\(\Leftrightarrow\)\(\frac{\left(x+1\right)\left(2-x\right)+5\left(x-1\right)\left(x+1\right)}{\left(x+1\right)\left(2-x\right)\left(x-1\right)}=\frac{15\left(x-1\right)}{\left(x-1\right)\left(x+1\right)\left(2-x\right)}\)
Suy ra:
\(\Leftrightarrow\)(x+1)(2-x)+5(x-1)(x+1) = 15(x-1)
\(\Leftrightarrow\)2x-x2-x+2+5x2-5 = 15x-15
\(\Leftrightarrow\)2x-x2-x+5x2-15x = -15+5-2
\(\Leftrightarrow\)4x2-14x = -12
\(\Leftrightarrow4x^2-14x+12=0\)
\(\Leftrightarrow4x^2-8x-6x+12=0\)
\(\Leftrightarrow\)4x(x-2) - 6(x-2) = 0
\(\Leftrightarrow\left(x-2\right)\left(4x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\4x-6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\left(kotm\right)\\x=\frac{3}{2}\left(tm\right)\end{matrix}\right.\)
Vậy pt có nghiệm duy nhất x = \(\frac{3}{2}\)
Giải các phương trình sau :
a) \(x^4-\left(x^2+2\right)=4\)
b) \(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)
c) \(\frac{2x-10}{4}=5+\frac{2-3x}{6}\)
d) \(\frac{2x}{\left(x-3\right)\left(x+1\right)}+\frac{x}{2\left(x-3\right)}=\frac{x}{2x+2}\)
e) \(\left(\frac{x+2}{x}\right)^2+\left(\frac{x}{x+2}\right)^2=2\)
f) \(\left(x-a\right)\left(x+a\right)+2x+a^2=-1\)
g) \(\frac{x-a}{2a}+\frac{x-2a}{3a}+\frac{x-3a}{4a}+\frac{x-4a}{5a}=-4\)
h) \(\left(x^2-3x+4\right)^2=\left(x^2-2x+3\right)\left(x^2-4x+5\right)\)
i) \(\frac{x^2-4x+12}{x^2-4x+6}=x^2-4x+8\)
mấy chế ai biết giải thì giải dùm mik mấy bài nè vs.
Giải phương trình:
1) \(\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}=\frac{1}{6}\)
2) \(\frac{1}{x^2-6x+8}+\frac{1}{x^2-10x+24}+\frac{1}{x^2-14x+48}=\frac{1}{9}\)
3) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
4) \(\frac{6}{\left(x+1\right)\left(x+2\right)}+\frac{8}{\left(x-1\right)\left(x+4\right)}=1\)
5) \(4\left(x^3+\frac{1}{x^3}\right)=13\left(x+\frac{1}{x}\right)\)
6) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
7) \(\frac{x^2-3x+5}{x^2-4x+5}-\frac{x^2-5x+5}{x^2-6x+5}=\frac{-1}{4}\)
8) \(x\frac{8-x}{x-1}.\left(x-\frac{8-x}{x-1}\right)=15\)
bài 1. giải các phương trình sau
a / \(x =(4x+1) (\frac{3x+7}{3-5x}+1)=(x+4)(\frac{3x+7}{5x-3}-1)\)
b/ \(\left(x^2+3x+1\right)\left(\frac{4x-3}{3x+1}+2\right)=\left(4x+7\right)\left(\frac{4x-3}{3x+1}+2\right)\)1)
bài 2. giải phương trình sau bằng cách đưa về phương trình tích
a/\(\left(4x-5\right)^2-2\left(16x^2-25\right)=0\)
b/ \(\left(4x+3\right)^2=4\left(x^2-2x+1\right)\)
c. \(3x^3-3x^2-6x=0\)
cảm ơn mọi người nhiều lắm !
Giải các phương trình sau:
a) \(\frac{4}{x-1}-\frac{5}{x-2}=-3\)
b) \(\frac{x+4}{x^2-3x+2}+\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
c) \(3x-\frac{1}{x-2}=\frac{x-1}{2-x}\)
d) \(\frac{2}{x^2-4}-\frac{1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
e) \(\frac{4x}{x^2+4x+3}-1=6\left(\frac{1}{x+3}-\frac{1}{2x+2}\right)\)
Giải các phương trình sau :
a) \(x^4-\left(x^2+2\right)=4\)
b) \(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)
c) \(\frac{2x-10}{4}=5+\frac{2-3x}{6}\)
d) \(\frac{2x}{\left(x-3\right)\left(x+1\right)}+\frac{x}{2\left(x-3\right)}=\frac{x}{2x+2}\)
e) \(\left(\frac{x+2}{x}\right)^2+\left(\frac{x}{x+2}\right)^2=2\)
f) \(\left(x-a\right)\left(x+a\right)+2x+a^2=-1\)
g) \(\frac{x-a}{2a}+\frac{x-2a}{3a}+\frac{x-3a}{4a}+\frac{x-4a}{5a}=-4\)
h) \(\left(x^2-3x+4\right)^2=\left(x^2-2x+3\right)\left(x^2-4x+5\right)\)
i ) \(\frac{x^2-4x+12}{x^2-4x+6}=x^2-4x+8\)
a) đặt \(t=x^2\) (t\(\ge0\))
=>\(t^2-t-2=0\)=>\(\orbr{\begin{cases}t=2\\t=-1\left(loại\right)\end{cases}}\)
=>\(x^2=2\)=>\(\orbr{\begin{cases}x=\sqrt{2}\\x=-\sqrt{2}\end{cases}}\)
a) \(\orbr{\begin{cases}x=\sqrt{3}\\x=-\sqrt{3}\end{cases}}\)
b)\(\orbr{\begin{cases}x=1\\x=-3\end{cases}}\)
c)\(x=\frac{47}{6}\)