When I (1) ...................... (go) to bed last night, I (2) ................. (fall) asleep immediately. I must have been tired because I (3) ......................... (work) so hard for several hours. So I forgot (4) ................ (close) the windows before (5) .......................... (get) into bed. If I had remembered, the thief (6) ..................... (not get in) but he (7) ..................... (give) a perfect opportunity (8) .................. (enter) the house. The next time I (9) .................. (work) late, I (10) .................. (lock) the house carefully.

Giải các phương trình sau :

a) \(x^4-\left(x^2+2\right)=4\)

b) \(\frac{x+2}{x-2}-\frac{1}{x}=\frac{2}{x\left(x-2\right)}\)

c) \(\frac{2x-10}{4}=5+\frac{2-3x}{6}\)

d) \(\frac{2x}{\left(x-3\right)\left(x+1\right)}+\frac{x}{2\left(x-3\right)}=\frac{x}{2x+2}\)

e) \(\left(\frac{x+2}{x}\right)^2+\left(\frac{x}{x+2}\right)^2=2\)

f) \(\left(x-a\right)\left(x+a\right)+2x+a^2=-1\)

g) \(\frac{x-a}{2a}+\frac{x-2a}{3a}+\frac{x-3a}{4a}+\frac{x-4a}{5a}=-4\)

h) \(\left(x^2-3x+4\right)^2=\left(x^2-2x+3\right)\left(x^2-4x+5\right)\)

i) \(\frac{x^2-4x+12}{x^2-4x+6}=x^2-4x+8\)

Giải phương trình : \(x^3-6x^2-9x+14=0\)

Giải phương trình : \(\frac{2}{x+3}+\frac{1}{x-3}=\frac{2x}{x^2-9}\)

Giải phương trình : \(\frac{3}{x+1}=\frac{5}{2x-2}\)

Giải phương trình : \(\left(2x+3\right)\left(x-7\right)=0\)