\(\frac{2^7.9^2}{3^3.2^5}\)
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Tính bằng cách hợp lí:
\(\frac{2^7.9^2}{3^3.2^5}\)
Ta có :\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}\)
\(=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1}=12\)
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Trả lời:
\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^2.\left(3^2\right)^2}{3^3}=\frac{2^2.3^4}{3^3}=\frac{2^2.3}{1}=4.3=12\)
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thực hiện phép tính:
\(\frac{2^7.9^2}{3^3.2^5}\)
\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1.1}=12\)
\(\frac{2^7.9^2}{3^3.2^5}\)
\(=\frac{2^{5+2}.\left(3^2\right)^2}{3^3.2^5}\)
\(=\frac{2^5.2^2.3^4}{3^3.2^5}\)
\(=2^2.3\)
\(=4.3\)
\(=12\)
^_^
\(\frac{2^7\cdot9^2}{3^3\cdot2^5}\)
⇒\(\frac{2^7\cdot\left(3^2\right)^2}{3^3\cdot2^5}\)
⇒\(\frac{2^7\cdot3^4}{3^3\cdot2^5}\)
⇒\(2^2\cdot2\)
⇒\(4\cdot2\)
➩\(8\)
Chúc bạn học tốt nhé Thuong Hoai!
2^7.9^2/3^3.2^5
\(\frac{2^7.9^2}{3^3.2^5}\)\(=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1}=2^2.3=4.3=12\)
\(\dfrac{2^7.9^2}{3^3.2^5}\)
\(\dfrac{2^7.9^2}{3^3.2^5}\)
\(=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}\)
\(=\dfrac{2^7.3^4}{3^3.2^5}\)
\(=2^2.3\)
\(=4.3\)
\(=12\)
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\(\dfrac{2^7.9^2}{3^3.2^5}=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}=\dfrac{2^7.3^4}{3^3.2^5}=\dfrac{2^2.3}{1}=4.3=12\)
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\(\dfrac{2^7.9^2}{3^3.2^5}=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}=\dfrac{2^2.3^4}{3^3}=2^2.3=4.3=12\)
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Xem thêm câu trả lời
a) \(\left(\frac{1}{2}\right)^2.\frac{4}{11}+\frac{7}{11}.\left(-\frac{1}{3}\right)^2\)
b) \(\frac{2^7.9^2}{3^3.2^5}\)
c) \(\sqrt{25}-3.\sqrt{\frac{4}{9}}\)
(like)
2^3.2^2+7.9
a) \(A=\frac{1}{199}-\frac{1}{199.198}-\frac{1}{198.197}-\frac{1}{197.196}-....-\frac{1}{3.2}-\frac{1}{2.1}\)
b) \(B=1-\frac{2}{3.5}-\frac{2}{5.7}-\frac{2}{7.9}-....-\frac{2}{61.63}-\frac{2}{63-65}\)
\(a)\) \(A=\frac{1}{199}-\frac{1}{199.198}-\frac{1}{198.197}-\frac{1}{197.196}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
\(A=\frac{1}{199}-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{197.198}+\frac{1}{198.199}\right)\)
\(A=\frac{1}{199}-\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{197}-\frac{1}{198}+\frac{1}{198}-\frac{1}{199}\right)\)
\(A=\frac{1}{199}-\left(1-\frac{1}{199}\right)\)
\(A=\frac{1}{199}-1+\frac{1}{199}\)
\(A=\frac{-197}{199}\)
Chúc bạn học tốt ~
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a) \(A=\frac{1}{199}-\frac{1}{199.198}-\frac{1}{198.197}-\frac{1}{197.196}-...-\frac{1}{3.2}-\frac{1}{2.1}\)
\(A=\frac{1}{199}-\left(\frac{1}{1.2}+\frac{1}{2.3}+...\frac{1}{197.198}+\frac{1}{198.199}\right)\)
\(A=\frac{1}{199}-\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{197}-\frac{1}{198}+\frac{1}{198}-\frac{1}{199}\right)\)
\(A=\frac{1}{199}-(1-\frac{1}{199})\)
\(A=\frac{1}{199}-1+\frac{1}{199}\)
\(A=\frac{-197}{199}\)
Vậy \(A=\frac{-197}{199}\)
b) cũng thế
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Xem thêm câu trả lời
tínhA frac{11}{1.3}+ frac{47}{3.5}+ frac{107}{5.7}+ frac{191}{7.9}+...+ frac{971}{17.19}B frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}- frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3-5^9.7^3.2^3}C 1.3+3.5+5.7+...+ (2n-1)(2n+1)Giúp mình vs nhanh nhanh nha các bạn
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tính
A =\(\frac{11}{1.3}\)+ \(\frac{47}{3.5}\)+ \(\frac{107}{5.7}\)+ \(\frac{191}{7.9}\)+...+ \(\frac{971}{17.19}\)
B = \(\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)- \(\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3-5^9.7^3.2^3}\)
C = 1.3+3.5+5.7+...+ (2n-1)(2n+1)
Giúp mình vs nhanh nhanh nha các bạn
A=(-4/5+4/3)+(-5/4+14/5)-7/3
B=8/3.2/5.3/8.10.19/92
C=-5/7.2/11+-5/7.9/14+12/7
Mk sửa đề nha :
\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)
\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)
\(=\frac{-5}{7}.1+\frac{12}{7}\)
\(=\frac{-5}{7}+\frac{12}{7}\)
\(=1\)
Study well ! >_<
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