Tìm ĐKXĐ
1)\(\frac{4x-9}{8x^3+1}\)
2)\(\frac{8x^2+x+1}{2x^2-7x+5}\)
3)\(\frac{x+4}{x^2-1}\)+\(\frac{2x+3}{x\left(x+2\right)}\)+\(\frac{2}{x^2+4}\)=\(\frac{11}{3}\)
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Những câu hỏi liên quan
1)\(\frac{5x-3}{3}\)-\(\frac{6x-7}{4}\)+x=\(\frac{2x-5}{6}\)-x+2
2)\(\frac{x-4}{5}\)+\(\frac{3x-2}{10}\)-x=\(\frac{2x-5}{3}\)-\(\frac{7x+2}{6}\)
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\(1,\frac{5x-3}{3}-\frac{6x-7}{4}+x=\frac{2x-5}{6}-x+2\)
\(\Leftrightarrow\frac{\left(5x-3\right)4}{12}-\frac{\left(6x-7\right)3}{12}+\frac{12x}{12}=\frac{\left(2x-5\right)2}{12}-\frac{12x}{12}+\frac{24}{12}\)
\(\Leftrightarrow\frac{20x-12}{12}-\frac{18x-21}{12}+\frac{12x}{12}=\frac{4x-10}{12}-\frac{12x}{12}+\frac{24}{12}\)
\(\Rightarrow20x-12-18x+21+12x=4x-10-12x+24\)
\(\Leftrightarrow20x-18x+12x-4x+12x=-10+24+12-21\)
\(\Leftrightarrow22x=5\)
\(\Leftrightarrow x=\frac{5}{22}\)
câu 2 tương tự
\(\frac{x-4}{5}+\frac{3x-2}{10}-x=\frac{2x-5}{3}-\frac{7x+2}{6}\)
\(\Leftrightarrow\frac{2x-8}{10}+\frac{3x-2}{10}-x=\frac{4x-10}{6}-\frac{7x+2}{6}\)
\(\Leftrightarrow\frac{5x-10}{10}-x=\frac{-3x-12}{6}\)
\(\Leftrightarrow\frac{2x-2}{5}-x+\frac{x+4}{2}=0\)
\(\Leftrightarrow\frac{4x-4+5x+20-10x}{10}=0\)
\(\Leftrightarrow x=16\)
Vậy tập nghiệm của phương trình là S={16}
AD ơi!Câu 2 đáp án là vô nghiệm mới đúng chứ ạ?
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\(14\frac{1}{2}\)- \(\frac{2\left(x+3\right)}{5}\)=\(\frac{3x}{2}\)-\(\frac{2\left(x-7\right)}{3}\)
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<=> \(\frac{29}{2}-\frac{2x+6}{5}=\frac{3x}{2}-\frac{2x-14}{3}\)
<=> \(\frac{435}{30}-\frac{12x+36}{30}=\frac{45x}{30}-\frac{20x-140}{30}\)
<=> \(\frac{435-12x-36}{30}=\frac{45x-20x+140}{30}\)
<=> 399 - 12x = 25x + 140
<=> 37x = -259
<=> x = -7
Vậy .....
\(\Leftrightarrow\frac{435}{30}-\frac{12\left(x+3\right)}{30}=\frac{45x}{30}-\frac{20\left(x-7\right)}{30}\)
\(\Leftrightarrow\frac{435-12\left(x+3\right)-45x-20\left(x-7\right)}{30}=0\)
\(\Leftrightarrow435-12x-36-45x-20x+140=0\)
\(\Leftrightarrow-77x=-539\)
\(\Leftrightarrow x=7\)
\(Vậyx=7lànghiệmcủaphươngtrình\)
Chỗ kia mk sai nha
37x=259
x=7
vậy ........
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Tìm điều kiện xác định rồi giải các phương trình sau:a) frac{x-2}{2+x}-frac{3}{x-2}frac{2left(x-11right)}{x^2-4}b) frac{3}{4left(x-5right)}+frac{15}{50-2x^2}frac{-7}{6left(x+5right)}c) frac{8x^2}{3left(1-4x^2right)}frac{2x}{6x-3}-frac{1+8x}{4+8x}d) frac{13}{left(x-3right)left(2x+7right)}+frac{1}{2x+7}frac{6}{x^2-9}Help me!
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Tìm điều kiện xác định rồi giải các phương trình sau:
a) \(\frac{x-2}{2+x}-\frac{3}{x-2}=\frac{2\left(x-11\right)}{x^2-4}\)
b) \(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{-7}{6\left(x+5\right)}\)
c) \(\frac{8x^2}{3\left(1-4x^2\right)}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
d) \(\frac{13}{\left(x-3\right)\left(2x+7\right)}+\frac{1}{2x+7}=\frac{6}{x^2-9}\)
Help me!
a) ĐKXĐ: x khác +2
\(\frac{x-2}{2+x}-\frac{3}{x-2}-\frac{2\left(x-11\right)}{x^2-4}\)
<=> \(\frac{x-2}{2+x}-\frac{3}{x-2}=\frac{2\left(x-11\right)}{\left(x-2\right)\left(x+2\right)}\)
<=> (x - 2)^2 - 3(2 + x) = 2(x - 11)
<=> x^2 - 4x + 4 - 6 - 3x = 2x - 22
<=> x^2 - 7x - 2 = 2x - 22
<=> x^2 - 7x - 2 - 2x + 22 = 0
<=> x^2 - 9x + 20 = 0
<=> (x - 4)(x - 5) = 0
<=> x - 4 = 0 hoặc x - 5 = 0
<=> x = 4 hoặc x = 5
làm nốt đi
Giải các phương trình sau:a)frac{left(9x-0.7right)}{4}-frac{left(5x-1.5right)}{7}frac{left(7x-1.1right)}{3}-frac{5left(0.4-2xright)}{6}b)frac{3x-1}{x-1}-frac{2x+5}{x+3}1-frac{4}{left(x-1right)left(x+3right)}c)frac{3}{4left(x-5right)}+frac{15}{50-2x^2}-frac{7}{6left(x+5right)}d)frac{8x^2}{3left(1-4xright)^2}frac{2x}{6x-3}-frac{1+8x}{4+8x}
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Giải các phương trình sau:
a)\(\frac{\left(9x-0.7\right)}{4}-\frac{\left(5x-1.5\right)}{7}=\frac{\left(7x-1.1\right)}{3}-\frac{5\left(0.4-2x\right)}{6}\)
b)\(\frac{3x-1}{x-1}-\frac{2x+5}{x+3}=1-\frac{4}{\left(x-1\right)\left(x+3\right)}\)
c)\(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=-\frac{7}{6\left(x+5\right)}\)
d)\(\frac{8x^2}{3\left(1-4x\right)^2}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
Giải phương trìnha) frac{4}{20-6x-2x^2}+ frac{x^2+4x}{x^2+5x}-frac{x+3}{2-x}+30b)frac{x+5}{x^2-5x}-frac{x-5}{2x^2-10x}+10frac{x+25}{2x^2-50}c) frac{7}{8x}+frac{5-x}{4x^2-8x}frac{x-1}{2x.left(x-2right)}+frac{1}{8x-16}c) frac{7}{8x}+frac{5-x}{4x^2-8x}frac{x-1}{2x.left(x-2right)}+frac{1}{8x-16}
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Giải phương trình
a) \(\frac{4}{20-6x-2x^2}\)+ \(\frac{x^2+4x}{x^2+5x}-\frac{x+3}{2-x}+3=0\)
b)\(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2-10x}+10=\frac{x+25}{2x^2-50}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
1, |x-5|=|2x-9|
2, ||2x-11|-x|=8
3, |4x-7|+\(\left|\frac{7-4x}{4x-7}\right|\)=9
4, \(\frac{\left|7x^2-9x+2\right|}{5x+4}\)=2-7x
5, \(\frac{x^2-8x+15}{\left|2x^2-9x-5\right|}\)=3x-9
Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b0
1. a, frac{5x-2}{3}frac{5-3x}{2}; b, frac{10x+3}{12}1+frac{6+8x}{9}
c, 2left(x+frac{3}{5}right)5-left(frac{13}{5}+xright); d, frac{7}{8}x-5left(x-9right)frac{20x+1,5}{6}
e, frac{7x-1}{6}+2xfrac{16-x}{5}; f, 4 (0,5-1,5x)frac{5x-6}{3}
g, frac{3x+2}{2}-frac{3x+1}{6}frac{5}{3}+2x; h, frac{x+4}{5}.x+4frac{x}{3}-frac{x-2}{2}
i, frac{4x+3}{5}-frac{6x-2}{7}fr...
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Câu 3: Giải các phương trình sau bằng cách đưa về dạng ax+b=0
1. a, \(\frac{5x-2}{3}=\frac{5-3x}{2}\); b, \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
c, \(2\left(x+\frac{3}{5}\right)=5-\left(\frac{13}{5}+x\right)\); d, \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
e, \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\); f, 4 (0,5-1,5x)=\(\frac{5x-6}{3}\)
g, \(\frac{3x+2}{2}-\frac{3x+1}{6}=\frac{5}{3}+2x\); h, \(\frac{x+4}{5}.x+4=\frac{x}{3}-\frac{x-2}{2}\)
i, \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\); k, \(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
m, \(\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{15}\); n, \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right).\frac{1}{3}\left(x+2\right)\)
p, \(\frac{x}{3}-\frac{2x+1}{6}=\frac{x}{6}-x\); q, \(\frac{2+x}{5}-0,5x=\frac{1-2x}{4}+0,25\)
r, \(\frac{3x-11}{11}-\frac{x}{3}=\frac{3x-5}{7}-\frac{5x-3}{9}\); s, \(\frac{9x-0,7}{4}-\frac{5x-1,5}{7}=\frac{7x-1,1}{6}-\frac{5\left(0,4-2x\right)}{6}\)
t, \(\frac{2x-8}{6}.\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\); u, \(\frac{x+5}{4}-\frac{2x-3}{3}=\frac{6x-1}{3}+\frac{2x-1}{12}\)
v, \(\frac{5x-1}{10}+\frac{2x+3}{6}=\frac{x-8}{15}-\frac{x}{30}\); w, \(\frac{2x-\frac{4-3x}{5}}{15}=\frac{7x\frac{x-3}{2}}{5}-x+1\)
Đây là những bài cơ bản mà bạn!
\(\frac{5x-2}{3}=\frac{5-3x}{2}\)
\(< =>\frac{\left(5x-2\right).2}{6}=\frac{\left(5-3x\right).3}{6}\)
\(< =>\left(5x-2\right).2=\left(5-3x\right).3\)
\(< =>10x-4=15-9x\)
\(< =>10x+9x=15+4\)
\(< =>19x=19< =>x=1\)
\(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(< =>\frac{\left(10x+3\right).3}{36}=\frac{36}{36}+\frac{\left(6+8x\right).4}{36}\)
\(< =>\left(10x+3\right).3=36+\left(6+8x\right).4\)
\(< =>30x+9=36+24+32x\)
\(< =>32x-30x=9-36-24\)
\(< =>2x=9-60=-51< =>x=-\frac{51}{2}\)
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giải phương trình
left(3x+2right)left(x^2-1right)left(9x^2-4right)left(x+1right)^{ }
frac{2a-9}{2a-5}+frac{3a}{3a-2}2
frac{1}{x^2+9x+20}+frac{1}{x^2+11x+30}+frac{1}{x^2+13x+42}frac{1}{18}
frac{2}{-x^2+6x-8}-frac{x-1}{x-2}frac{x+3}{x-4}
frac{3}{4left(x-5right)}+frac{15}{50-2x^2}frac{-7}{6left(x+5right)}
frac{8x^23}{3left(1-4x^2right)}frac{2x}{6x-3}-frac{1+8x}{4+8x}
frac{x-3}{x-2}+frac{x-2}{x-4}-1
frac{2x+1}{x-1}frac{5left(x-1right)}{x+1}
frac{x-3}{x-2}-frac{x-2}{x-4}3frac{1}{5}
f...
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giải phương trình
\(\left(3x+2\right)\left(x^2-1\right)=\left(9x^2-4\right)\left(x+1\right)^{ }\)
\(\frac{2a-9}{2a-5}+\frac{3a}{3a-2}=2\)
\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
\(\frac{2}{-x^2+6x-8}-\frac{x-1}{x-2}=\frac{x+3}{x-4}\)
\(\frac{3}{4\left(x-5\right)}+\frac{15}{50-2x^2}=\frac{-7}{6\left(x+5\right)}\)
\(\frac{8x^23}{3\left(1-4x^2\right)}=\frac{2x}{6x-3}-\frac{1+8x}{4+8x}\)
\(\frac{x-3}{x-2}+\frac{x-2}{x-4}=-1\)
\(\frac{2x+1}{x-1}=\frac{5\left(x-1\right)}{x+1}\)
\(\frac{x-3}{x-2}-\frac{x-2}{x-4}=3\frac{1}{5}\)
\(\frac{5x-2}{2-2x}+\frac{2x-1}{2}=1-\frac{x^2+x-3}{1-x}\)
Giải phương trình:1) frac{7x-1}{6}+2xfrac{16-x}{5}2) frac{10x+3}{12}1+frac{6+8x}{9}3)frac{8x-3}{4}-frac{3x-2}{2}frac{2x-1}{2}+frac{x+3}{4}4)frac{3left(3-xright)}{8}+frac{2left(5-xright)}{3}frac{1-x}{2}-25)frac{2left(x-3right)}{7}+frac{x-5}{3}-frac{13x+4}{21}06)frac{6x+5}{2}-left(2x+frac{2x+1}{2}right)frac{10x+3}{4}7)frac{2x-1}{5}-frac{x-2}{3}-frac{x+7}{15}08)frac{x+4}{5}-x+4frac{x}{3}-frac{x-2}{2}giải giúp mik với ạ
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Giải phương trình:
1) \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
2) \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
3)\(\frac{8x-3}{4}-\frac{3x-2}{2}=\frac{2x-1}{2}+\frac{x+3}{4}\)
4)\(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=\frac{1-x}{2}-2\)
5)\(\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}-\frac{13x+4}{21}=0\)
6)\(\frac{6x+5}{2}-\left(2x+\frac{2x+1}{2}\right)=\frac{10x+3}{4}\)
7)\(\frac{2x-1}{5}-\frac{x-2}{3}-\frac{x+7}{15}=0\)
8)\(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
giải giúp mik với ạ
1. \(\frac{7x-1}{6}+2x=\frac{16-x}{5}\)
\(\Leftrightarrow5\left(7x-1\right)+60x=6\left(16-x\right)\)
\(\Leftrightarrow35x-5+60x=96-6x\)
\(\Leftrightarrow95x-5=96-6x\)
\(\Leftrightarrow95x+6x=96+5\)
\(\Leftrightarrow101x=101\)
\(\Leftrightarrow x=1\)
2. \(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)
\(\Leftrightarrow3\left(10x+3\right)=36+4\left(6+8x\right)\)
\(\Leftrightarrow30x+9=36+24+32x\)
\(\Leftrightarrow30x+9=32x+60\)
\(\Leftrightarrow30x-32x=60-9\)
\(\Leftrightarrow-2x=51\)
\(\Leftrightarrow x=-\frac{51}{2}\)
3. \(\frac{8x-3}{4}-\frac{3x-2}{2}=\frac{2x-1}{2}+\frac{x+3}{4}\)
\(\Leftrightarrow8x-3-2\left(3x-2\right)=2\left(2x-1\right)+x+3\)
\(\Leftrightarrow8x-3-6x+4=4x-2+x+3\)
\(\Leftrightarrow2x+1=5x+1\)
\(\Leftrightarrow2x=5x\)
\(\Leftrightarrow x=0\)
4) \(\frac{3\left(3-x\right)}{8}+\frac{2\left(5-x\right)}{3}=\frac{1-x}{2}-2\)
=> \(\frac{9-3x}{8}+\frac{10-2x}{3}=\frac{1-x}{2}-\frac{2}{1}\)
=> \(\frac{3\left(9-3x\right)}{24}+\frac{8\left(10-2x\right)}{24}=\frac{12\left(1-x\right)}{24}-\frac{48}{24}\)
=> \(\frac{27-9x}{24}+\frac{80-16x}{24}=\frac{12-12x}{24}-\frac{48}{24}\)
=> \(\frac{27-9x+80-16x}{24}=\frac{12-12x-48}{24}\)
=> 27 - 9x + 80 - 16x = 12 - 12x - 48
=> 27 - 9x + 80 - 16x - 12 + 12x + 48 = 0
=> (27 + 80 - 12 + 48) + (-9x - 16x + 12x) = 0
=> 143 - 13x = 0
=> 13x = 143
=> x = 11
5) \(\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}-\frac{13x+4}{21}=0\)
=> \(\frac{2x-6}{7}+\frac{x-5}{3}-\frac{13x+4}{21}=0\)
=> \(\frac{3\left(2x-6\right)}{21}+\frac{7\left(x-5\right)}{21}-\frac{13x+4}{21}=0\)
=> \(\frac{6x-18}{21}+\frac{7x-35}{21}-\frac{13x+4}{21}=0\)
=> \(\frac{6x-18+7x-35-13x-4}{21}=0\)
=> 6x - 18 + 7x - 35 - 13x - 4 = 0
=> (6x + 7x - 13x) + (-18 - 35 - 4) = 0
=> -57 = 0(vô nghiệm)
6) \(\frac{6x+5}{2}-\left(2x+\frac{2x+1}{2}\right)=\frac{10x+3}{4}\)
=> \(\frac{6x+5}{2}-\frac{10x+3}{4}=2x+\frac{2x+1}{2}\)
=> \(\frac{2\left(6x+5\right)}{4}-\frac{10x+3}{4}=\frac{8x}{4}+\frac{2\left(2x+1\right)}{4}\)
=> \(\frac{12x+10}{4}-\frac{10x+3}{4}=\frac{8x}{4}+\frac{4x+2}{4}\)
=> \(\frac{12x+10-\left(10x+3\right)}{4}=\frac{8x+4x+2}{4}\)
=> \(\frac{12x+10-10x-3}{4}=\frac{12x+2}{4}\)
=> \(12x+10-10x-3=12x+2\)
=> \(2x+10-3=12x+2\)
=> 2x + 10 - 3 - 12x - 2 = 0
=> (2x - 12x) + (10 - 3 - 2) = 0
=> -10x + 5 = 0
=> -10x = -5
=> x = 1/2
7) \(\frac{2x-1}{5}-\frac{x-2}{3}-\frac{x+7}{15}=0\)
=> \(\frac{3\left(2x-1\right)}{15}-\frac{5\left(x-2\right)}{15}-\frac{x+7}{15}=0\)
=> \(\frac{6x-3}{15}-\frac{5x-10}{15}-\frac{x+7}{15}=0\)
=> \(\frac{6x-3-\left(5x-10\right)-\left(x+7\right)}{15}=0\)
=> 6x - 3 - 5x + 10 - x - 7 = 0
=> (6x - 5x - x) + (-3 + 10 - 7) = 0
=> 0x + 0 = 0
=> 0x = 0
=> x tùy ý
Bài 8 tự làm nhé