a) \(\frac{1}{9}\)

b) -1100

a: \(=-9+\left\{-52:9\right\}=-9+\dfrac{-52}{9}=-\dfrac{133}{9}\)

b: \(=\dfrac{17}{7}+\left(\dfrac{-76}{63}\right):15\)

\(=\dfrac{17}{7}-\dfrac{76}{63}\cdot\dfrac{1}{15}=\dfrac{317}{135}\)

e: \(=\dfrac{-5}{13}\cdot\dfrac{7}{3}-\dfrac{2}{7}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{7}\)

\(=\dfrac{5}{13}\left(-\dfrac{7}{3}+\dfrac{1}{7}\right)-\dfrac{2}{7}\cdot\dfrac{8}{13}\)

\(=\dfrac{5}{13}\cdot\dfrac{-46}{21}-\dfrac{16}{91}=\dfrac{-278}{273}\)

Tính :

a) \(\frac{1}{6}.\frac{9}{-8}.\left(-\frac{12}{11}\right)=\frac{1.9.\left(-12\right)}{6.\left(-8\right).11}=\frac{1.3.3}{2.2.11}=\frac{9}{44}\)

b) \(\frac{1}{8}.\frac{-3}{7}+\frac{1}{8}.\frac{-4}{7}\)

\(=\frac{1}{8}.\left(-\frac{3}{7}+\frac{-4}{7}\right)\)

\(=\frac{1}{8}.\frac{-7}{7}=\frac{1}{8}.\left(-1\right)\)

\(=-\frac{1}{8}\)

c) \(\frac{7}{13}.\frac{3}{-5}+\frac{6}{13}.\frac{-3}{5}\)

\(=-\frac{3}{5}.\left(\frac{7}{13}+\frac{6}{13}\right)\)

\(=-\frac{3}{5}.\frac{13}{13}=-\frac{3}{5}.1\)

\(=-\frac{3}{5}\)

a, \(\frac{1}{6}.\frac{9}{-8}.\frac{-12}{11}\)

\(\Rightarrow\frac{9}{8}.\frac{2}{11}\)

\(\Rightarrow\frac{9}{4}.\frac{1}{11}\)

\(\Rightarrow\frac{9}{44}\)

b,\(\frac{1}{8}.\frac{-3}{7}+\frac{1}{8}.\frac{-4}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{2}.\frac{1}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{2}.\frac{1}{7}\)

\(\Rightarrow\frac{-3}{56}-\frac{1}{14}\)

\(\Rightarrow\frac{-1}{8}\)

c,\(\frac{7}{13}.\frac{3}{-5}+\frac{6}{13}.\frac{-3}{5}\)

\(\Rightarrow\frac{-21}{65}-\frac{18}{65}\)

\(\Rightarrow\frac{-3}{5}\)

a, \(\frac{1}{6}.\frac{9}{-8}.\frac{-12}{11}\)

\(=\frac{1}{6}.\frac{-9}{8}.\frac{-12}{11}\)

\(=\frac{-3}{16}.\frac{-12}{11}\)

\(=\frac{9}{44}\)

b, \(\frac{1}{8}.\frac{-3}{7}+\frac{1}{8}.\frac{-4}{7}\)

\(=\frac{1}{8}.\left(\frac{-3}{7}+\frac{-4}{7}\right)\)

\(=\frac{1}{8}.\left(-1\right)\)

\(=\frac{-1}{8}\)

c, \(\frac{7}{13}.\frac{3}{-5}+\frac{6}{13}.\frac{-3}{5}\)

\(=\frac{7}{13}.\frac{-3}{5}+\frac{6}{13}.\frac{-3}{5}\)

\(=\frac{-3}{5}.\left(\frac{7}{13}+\frac{6}{13}\right)\)

\(=\frac{-3}{5}.1\)

\(=\frac{-3}{5}\)

\(M=\frac{17}{5}\cdot\frac{-31}{125}\cdot\frac{1}{2}\cdot\frac{10}{17}\cdot\frac{-1}{2^3}\)

\(M=\frac{17}{5}\cdot\frac{-31}{125}\cdot\frac{1}{2}\cdot\frac{10}{7}\cdot\frac{-1}{8}\)

\(M=\left(\frac{17}{5}\cdot\frac{10}{17}\cdot\frac{1}{2}\right)\cdot\frac{-31}{125}\cdot\frac{-1}{8}\)

\(M=1\cdot\frac{31}{1000}=\frac{31}{1000}\)

\(P=\frac{6}{7}\cdot\frac{8}{13}+\frac{6}{9}\cdot\frac{9}{7}-\frac{3}{13}\cdot\frac{6}{7}=\frac{6}{7}\cdot\frac{8}{13}+\frac{6}{7}\cdot1-\frac{3}{13}\cdot\frac{6}{7}\)

\(=\frac{6}{7}\left(\frac{8}{13}+1-\frac{3}{13}\right)=\frac{6}{7}\left(\frac{8}{3}+\frac{13}{13}-\frac{3}{13}\right)=\frac{6}{7}\cdot\frac{18}{13}=\frac{108}{91}\)

\(a,13\frac{3}{7}+4\frac{5}{13}-8\frac{3}{7}\)

\(=\left(13+4-8\right)+\left(\frac{3}{7}+\frac{5}{13}-\frac{3}{7}\right)\)

\(=9\frac{5}{13}\)

\(b,\left(6-2\frac{4}{5}\right).3\frac{1}{8}-1\frac{3}{5}:\frac{1}{4}\)

\(=3\frac{1}{5}.3\frac{1}{8}-1\frac{3}{5}.4\)

\(=10-6\frac{2}{5}\)

\(=3\frac{3}{5}\)

A<13 tick minh nha ban

Đáp án là A<13

\(\frac{\frac{3}{7}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)

\(=\frac{3\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{4\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{8}\right)}{5\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{8}\right)}\)

\(=\frac{3}{5}+\frac{4}{5}=\frac{7}{5}\)

Ta có: \(\frac{\frac{3}{7}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)

\(=\frac{3\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{4\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{8}\right)}{5\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{8}\right)}\)

\(=\frac{3}{5}+\frac{4}{5}\)

\(=\frac{7}{5}\)

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Bài 1:

a) Ta có: \(\frac{8}{40}+\frac{-4}{20}-\frac{3}{5}\)

\(=\frac{1}{5}+\frac{-1}{5}-\frac{3}{5}\)

\(=\frac{-3}{5}\)

b) Ta có: \(\frac{-7}{12}+\frac{-2}{12}-\frac{-3}{36}\)

\(=\frac{-7}{12}+\frac{-2}{12}-\frac{-1}{12}\)

\(=\frac{-9+1}{12}=\frac{-8}{12}=\frac{-2}{3}\)

c) Ta có: \(\left(\frac{1}{6}+\frac{-4}{13}\right)-\left(-\frac{17}{6}-\frac{30}{13}\right)\)

\(=\frac{1}{6}+\frac{-4}{13}+\frac{17}{6}+\frac{30}{13}\)

\(=3+2=5\)

d) Ta có: \(-\frac{-5}{4}+\frac{7}{4}-\frac{-11}{7}+\frac{2}{7}\)

\(=\frac{5}{4}+\frac{7}{4}+\frac{11}{7}+\frac{2}{7}\)

\(=3+\frac{13}{7}=\frac{21}{7}+\frac{13}{7}=\frac{34}{7}\)

e) Ta có: \(-\frac{1}{8}+\frac{-7}{9}+\frac{-7}{8}+\frac{6}{7}+\frac{2}{14}\)

\(=-1+1+\frac{-7}{9}\)

\(=-\frac{7}{9}\)

f) Ta có: \(\frac{-2}{9}-\frac{11}{-9}+\frac{5}{7}-\frac{-6}{-7}\)

\(=\frac{-2-\left(-11\right)}{9}+\frac{5-6}{7}\)

\(=1+\frac{-1}{7}=\frac{7}{7}+\frac{-1}{7}=\frac{6}{7}\)

Giúp Mik ik mai nộp oy