có thể làm như sau :

a. Với m = 415 ta có A = m + 185 = 415 + 185 = 600

A x 4 = 600 x 4 = 2400

có thểlàm như sau :

a. Với m = 415 ta có A = m + 185 = 415 + 185 = 600

A x 4 = 600 x 4 = 2400.

a) \(30\times1235\times4-8\times235\times15\)

\(=120\times1235-120\times235\)

\(=120\times\left(1235-235\right)\)

\(=120\times1000\)

\(=120000\)

b) \(\left(120\times99+120\right)-185\times101+185\)

\(=120\times\left(99+1\right)-185\cdot\left(101-1\right)\)

\(=120\times100-185\times100\)

\(=12000-18500\)

\(=-6500\)

a) 30 x 1235 x 4 - 8 x 235 x 15

=(30x4) x 1235 - (8x15)x235

= 120 x 1235 - 120 x 235

=120 x (1235-235)

=120 x 1000

=120000

b) ( 120 x 99 +120)  - 185 x 101-185

=(120 x 99 + 120) - (185x101+185)

=120x(99+1) - 185x(101+1)

=120 x 100-185x102

=12000-18870

= -(18870-12000)

= -6870

Bài 1:

$M=3.4.5+4.5.6+...+13.14.15$

$4M=3.4.5(6-2)+4.5.6(7-3)+....+13.14.15(16-12)$

$=-2.3.4.5+3.4.5.6-3.4.5.6+4.5.6.7+....-12.13.14.15+13.14.15.16$

$=-2.3.4.5+13.14.15.16=43560$

$M=43560:4=10890$

Bài 2:

a.

$3M=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{97.100}$

$=\frac{4-1}{1.4}+\frac{7-4}{4.7}+\frac{10-7}{7.10}+...+\frac{100-97}{97.100}$

$=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{97}-\frac{1}{100}$

$=1-\frac{1}{100}=\frac{99}{100}$

$M=\frac{99}{100}:3=\frac{33}{100}$

a)-22: b)35: c)84

Bài 1 

ta có a+3+b-3 =a +b chia hết cho 4

nên (b-a )(a+b) cũng chia hết cho 4

bài 2.

ta có: \(M=6x^2-5x-6-12xy+6y^2+6y-3x+2y+2027\)

\(=6\left(x-y\right)^2-8\left(x-y\right)+2021=24-16+2021=2029\)

1,

a) |x| + |y + 1| =0

Ta có: |x| \(\ge\) 0 (Với x \(\in\) Z)

|y + 1| \(\ge\) 0 (Với y\(\in\) Z)

\(\Rightarrow\) |x| + |y + 1| \(\ge\) 0

Dấu "=" xảy ra (=):

\(\left\{\begin{matrix}\left|x\right|=0\\\left|y+1\right|=0\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=0\\y+1=0\end{matrix}\right.\Rightarrow}\left\{\begin{matrix}x=0\\y=0-1\end{matrix}\right.\Rightarrow}\left\{\begin{matrix}x=0\\y=-1\end{matrix}\right.\)

Vậy x = 0; y = -1

b) (2 - x)⁴ = 81

\(\Rightarrow\) (2 - x)⁴ = 3⁴ = (-3)⁴

\(\Rightarrow\) \(\left[\begin{matrix}2-x=3\\2-x=-3\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=2-3\\x=2-\left(-3\right)\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-1\\x=5\end{matrix}\right.\)

Vậy: x \(\in\) {-1; 5}

c) |x - 1| + (-3) = 17

\(\Rightarrow\) |x - 1| = 17 - (-3)

\(\Rightarrow\) |x - 1| = 20

\(\Rightarrow\left[\begin{matrix}x-1=-20\\x-1=20\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-20+1\\x=20+1\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-19\\x=21\end{matrix}\right.\)

Vậy: x \(\in\) {-19; 21}

d) 3 - (17 - x) = 289 - (36 + 289)

\(\Rightarrow\) 3 - (17 - x) = 289 - 36 - 289

\(\Rightarrow\) 3 - (17 - x) = 289 - 289 - 36

\(\Rightarrow\) 3 - (17 - x) = 0 - 36

\(\Rightarrow\) 3 - (17 - x) = -36 \(\Rightarrow\) 17 - x = 3 - (-36) \(\Rightarrow\) 17 - x = 39 \(\Rightarrow\) x = 17 - 39 \(\Rightarrow\) x = -22 Vậy: x = -22 e) 25 - (x + 5) = -415 - (15 - 415) \(\Rightarrow\) 25 - (x + 5) = -415 - 15 + 415 \(\Rightarrow\) 25 - (x + 5) = (-415 + 415) - 15 \(\Rightarrow\) 25 - (x + 5) = 0 - 15 \(\Rightarrow\) 25 - (x + 5) = -15 \(\Rightarrow\) x + 5 = 25 - (-15) \(\Rightarrow\) x + 5 = 40 \(\Rightarrow\) x = 40 -5 \(\Rightarrow\) x = 35 Vậy: x = 35 f) 34 + (21 - x) = (3747 - 30) - 3746 \(\Rightarrow\) 34 + (21 - x) = 3747 - 30 - 3746 \(\Rightarrow\) 34 + (21 - x) = 3747 - 3746 - 30 \(\Rightarrow\) 34 + (21 - x) = 1 - 30 \(\Rightarrow\) 34 + (21 - x) = -29 \(\Rightarrow\) 21 - x = -29 - 34 \(\Rightarrow\) 21 - x = -63 \(\Rightarrow\) x = 21 - (-63) \(\Rightarrow\) x = 84 Vậy: x = 84

\(a,76-6\left(x-1\right)=10\)

\(76-6x-6=10\)

\(70-6x=10\)

\(6x=60\)

\(x=10\)

\(b,3.4^x-7=185\)

\(3.4^x=192\)

\(4^x=64\)

\(4^x=4^3\)

\(\Rightarrow x=3\)

Bài 1:Tìm x,biết:

a)  76 - 6( x - 1 ) = 10

=>  6( x - 1 ) =  76 -  10

=> 6( x - 1 ) =  66

=>   x - 1  = 11

=>  x  = 12

b)3.4^x-7=185

=>  3.4^x  =  185 + 7

=>  3.4^x  = 192

=> 4^x  = 64

=>   4^x  = 4^3

=>   x  =   3

Trường THCS Tân Sơn - Huyện Kim Bảng

you sai câu a) rồ ạ