ko dễ đâu cẩn thận

A = (1 - \(\frac{1}{2}\)) x (1 - \(\frac{1}{3}\)) x (1 - \(\frac{1}{4}\)) x (1 - \(\frac{1}{5}\)) x ... x (1 - \(\frac{1}{2014}\))  x (1 - \(\frac{1}{2015}\))

A = \(\frac{1}{2}\)x \(\frac{2}{3}\) x \(\frac{3}{4}\) x \(\frac{4}{5}\) x ... x \(\frac{2013}{2014}\)x \(\frac{2014}{2015}\)

A = \(\frac{1x2x3x4x...x2013x2014}{2x3x4x5x...x2014x2015}\)

A = \(\frac{1}{2015}\)

Vậy A = \(\frac{1}{2015}\)

~~~

\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{2014}\right)\left(1-\frac{1}{2015}\right)\)

\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot...\cdot\frac{2013}{2014}\cdot\frac{2014}{2015}\)

\(A=\frac{1\cdot2\cdot3\cdot4\cdot...\cdot2013\cdot2014}{2\cdot3\cdot4\cdot5\cdot...\cdot2014\cdot2015}\)

\(A=\frac{1}{2015}\)

\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{5}\right)\left(1-\frac{1}{6}\right)\)

\(=\left(\frac{2-1}{2}\right)\left(\frac{3-1}{3}\right)\left(\frac{4-1}{4}\right)\left(\frac{5-1}{5}\right)\left(\frac{6-1}{6}\right)\)

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}.\frac{5}{6}\)

\(=\frac{1}{6}\)

 bạn nào biết giải tớ với nha

bạn nào giải cho tớ bài này cho rõ ràng nha

7(x-3)-5(3-x)=11x-5

<=>7(x-3)+5(x-3)=11x-5

<=>(7+5)(x-3)=11x-5

<=>12(x-3)=11x-5

<=>12x-36=11x-5

<=>12x-11x=-5+36

<=>x=31

(31225-18000)x7

2387+4593+452038+789236=1246454

Thuộc thế kỉ 24

bai nay bi sai de bai hay sao ay

Ko bt trả lời thì im

5^2X-3-2*5^2=5^2*3

(24*5-5^2*2):(5*2)-3

=(120-50)/10-3

=7-3=4