a) \(\left(3x-2^4\right).7^3=2.7^4\)\(\Leftrightarrow3x-2^4=2.7^4:7^3\)

\(\Leftrightarrow3x-16=2.7\)\(\Leftrightarrow3x-16=14\)\(\Leftrightarrow3x=30\)

\(\Leftrightarrow x=10\)

Vậy \(x=10\)

b) \(3x+4x=\left|-75\right|+23\)\(\Leftrightarrow7x=75+23\)

\(\Leftrightarrow7x=98\)\(\Leftrightarrow x=14\)

Vậy \(x=14\)

a) \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=> \(3x\cdot7^3-2^4\cdot7^3=2\cdot7\cdot7^3\)

=> \(3x\cdot7^3=14\cdot7^3+16\cdot7^3\)

=> \(3x\cdot7^3=\left(14+16\right)\cdot7^3\)

=> \(3x\cdot7^3=30\cdot7^3\)

=> \(3x=30\)(bỏ hai vế 7³)

=> \(x=10\)

Vậy x = 10

b) \(3x+4x=\left|-75\right|+23\)

=> \(7x=75+23\)

=> \(7x=98\)

=> \(x=14\)

Vậy x = 14

a) ( 3x - 2⁴ ). 7³ = 2. 7⁴

    ( 3x - 16 )       = 2 . (7⁴ : 7³ )

     ( 3x - 16)      = 2 . 7

      3x -16         = 14

        3x             = 14 + 16

         3x            = 30

           x            = 30 : 3

            x           = 10

Vậy x =10.

b) 3x + 4x = I - 75 I + 23

    3x + 4x = 75 + 23

     7x        = 98

       x        = 98 : 7

        x       = 14.

Vậy x = 14.

Hok tốt !

VD: 1/2 là 1 phần 2 đó nha.

a: x/3-1/6=1/5

=>x/3=11/30

hay x=11/90

b: =>1/2x=2

hay x=4

c: =>2/3:x=-7-1/3=-22/3

=>x=-1/11

a: x/3-1/6=1/5

=>x/3=11/30

hay x=11/90

b: =>1/2x=2

hay x=4

c: =>2/3:x=-7-1/3=-22/3

=>x=-1/11

a: \(x+\dfrac{3}{9}=\dfrac{7}{6}\cdot\dfrac{2}{3}\)

=>\(x+\dfrac{1}{3}=\dfrac{14}{18}=\dfrac{7}{9}\)

=>\(x=\dfrac{7}{9}-\dfrac{1}{3}=\dfrac{7}{9}-\dfrac{3}{9}=\dfrac{4}{9}\)

b: \(x-\dfrac{2}{3}=\dfrac{1}{8}:\dfrac{5}{4}\)

=>\(x-\dfrac{2}{3}=\dfrac{1}{8}\cdot\dfrac{4}{5}=\dfrac{1}{10}\)

=>\(x=\dfrac{1}{10}+\dfrac{2}{3}=\dfrac{3+20}{30}=\dfrac{23}{30}\)

TThế giới oi oi oi 

\(=\left(x^3-2x^2+x+2x^2-4x+2-2x+7\right):\left(x^2-2x+1\right)\\ =\left[\left(x^2-2x+1\right)\left(x+2\right)-2x+7\right]:\left(x^2-2x+1\right)\\ =x+2\left(dư:-2x+7\right)\)

 x + {(x - 3) - [(x + 3) - (-x - 2)]} = x

=> x + {x - 3 - [x + 3 + x + 2]} = x

=> x + {x - 3 - x - 3 - x - 2} = x

=> x + x - 3 - x - 3 - x - 2 = x

=> (x - x) + (x - x) - (3 + 3 + 2) = x

=> 0 + 0 - 8 = x

=> - 8 = x

vậy x = - 8

=>(x-3)-[(x+3)-(-x-2)]=0

=>(x-3)-(x+3+x+2)=0

=>x-3-2x-5=0

=>-x-8=0

=>-x=8=>x=-8

a,(-12).x= 60-12

(-12).x=48

x=48:(-12)

x = -4

b,(-5).x + 5 = -24+6

(-5).x + 5 = 30

(-5).x      = 30-5

(-5).x      = 25

x = 25 : (-5)

x = -5

c,

$3x+36=-7x-64$

$10x=-100$

$x=-10$

$b,-5x-178=14x+145$

$-19x=323$

$x=-17$

Ta có :\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right).\left(2x-2\right)=\left(-\frac{3}{4}+\frac{5}{22}+\frac{3}{26}\right)\)

=> \(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right).\left(2x-2\right)=-\frac{1}{2}\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\)

=> \(2x-2=-\frac{1}{2}\)

=> \(2x=\frac{3}{2}\)

=> \(x=\frac{3}{4}\)

1) -12.(x-5) + 7.(3-x)=5

   -12x+ 60+21-7x =5

    -12x-7x = 5-60-21

    -19x=-76

     x=-76:(-19)

     x=4

2) (x-2).(x+4) =0

   \(\Rightarrow\)x-2=0 hoặc x+4=0

x-2=0                    x+4=0

x=0+2                    x=0-4     

x=2                         x=-4

Vậy x=2 hoặc x=-4

3) (x-2).(x+15) =0

 \(\Rightarrow\)x-2=0 hoặc x+15=0

 x-2=0                  x+15=0

x=0+2                   x=0-15 

 x=2                       x=-15

1)\(-12.\left(x-5\right)+7.\cdot\left(3-x\right)=5\)

\(-12x+60+21-7x=5\)

\(-19x+81=5\)

\(-19x=5-81\)

-\(-19x=-76\)

\(x=-76:-19\)

\(x=4\)

2) Ta có 2 trường hợp

TH1: x-2=0 =>x=2

TH2: x+4=0 => x=-4

Vậy \(x\in\left(-4;2\right)\)

3) Ta có

TH1: x-2=0=>x=2

TH2: x+15=0=>x=-15

Vậy \(x\in\left(-15;2\right)\)

2)   (x - 2).(x + 4) = 0

\(\hept{\begin{cases}x-2=0\\x+4=0\end{cases}\Rightarrow\hept{\begin{cases}x=0+2\\x=0-4\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=-4\end{cases}}}\)

Vậy x = 2 và (-4)

3)   (x-2).(x + 15) = 0

\(\hept{\begin{cases}x-2=0\\x+15=0\end{cases}\Rightarrow}\hept{\begin{cases}x=0+2\\x=0-15\end{cases}\Rightarrow}\hept{\begin{cases}x=2\\x=-15\end{cases}}\)

Vậy x = 2 và (-15)

\(72-3\left|x\right|=9\)

\(3\left|x\right|=72-9=63\)

\(\left|x\right|=63:3=21\)

\(\Rightarrow x=\pm21\)

\(72-3\left|x\right|=9\)

\(3\left|x\right|=63\)

\(\left|x\right|=21\)

x= 21 hoặc x= -21

\(-12\left(x-5\right)+7\left(3-x\right)=9\)

\(-12x+60+21-7x=9\)

\(-19x=-72\)

\(x=\dfrac{72}{19}\)