\(\frac{24}{x}-\frac{24}{x+4}=\frac{1}{2}\)
Những câu hỏi liên quan
Tìm x biết: \(1.\frac{1}{30}:\left(24.\frac{1}{6}-24.\frac{1}{5}\right)-\frac{1.\frac{1}{2}-\frac{3}{4}}{4.x-\frac{1}{2}}=\left(-1.\frac{1}{15}\right):\left(8.\frac{1}{5}-8.\frac{1}{3}\right)\)
\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5
\)
=> \(\left(\frac{1}{4}x+\frac{5}{6}x-\frac{3}{8}x\right)-\left(1+2+1\right)=4,5\)
=>\(\frac{17}{24}x-4=4,5\)
=> \(\frac{17}{24}x=8,5\)
=> \(x=8,5:\frac{17}{24}\)
=> \(x=12\)
a. \(\frac{x+109}{3}+\frac{x+125}{5}+\frac{x+149}{7}+\frac{x+181}{9}=24\)24
b. \(\frac{x-96}{2}+\frac{x-88}{4}+\frac{x-76}{6}+\frac{x-60}{8}=14\)
c. \(\frac{155x-24}{51}+\frac{185x-48}{57}+\frac{205x-3}{61}\)= 16
Giai các pt sau:
\(\frac{1}{x^2+2x}+\frac{1}{x^2+6x+8}+\frac{1}{x^2+10x+24}+\frac{1}{x^2+14x+48}=\frac{4}{105}\)
\(ĐKXĐ:x\ne0;-2;-4;-6;-8\)\(\frac{1}{x\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+6\right)}+\frac{1}{\left(x+6\right)\left(x+8\right)}=\frac{4}{105}\)
\(\Leftrightarrow\frac{2}{x\left(x+2\right)}+\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{2}{\left(x+4\right)\left(x+6\right)}+\frac{2}{\left(x+6\right)\left(x+8\right)}=\frac{8}{105}\)
\(\Leftrightarrow\frac{1}{x}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+4}+...+\frac{1}{x+6}-\frac{1}{x+8}=\frac{8}{105}\)
\(\Leftrightarrow\frac{1}{x}-\frac{1}{x+8}=\frac{8}{105}\)
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Tìm x biết \(1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
tìm x biết : \(1\frac{1}{3}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
tìm x \(\frac{1}{2}-\frac{13}{12}< x< \frac{1}{24}-\frac{-5}{24}\)
\(\frac{1}{x^2+2x}+\frac{1}{x^2+6x+8}+\frac{1}{x^2+10x+24}+\frac{1}{x^2+14x+48}=\frac{4}{105}\)
Giúp mk vs
1\(\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\)\(1\frac{1}{\frac{2}{4.x-\frac{1}{2}}}-\frac{3}{4}\)=\(\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)ai nhanh mik tick