\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=2^2.3=12\)

Có gì sai sót thì bỏ qua nhé chị !

Ta có : \(\frac{2^7.9^2}{3^3.2^5}=\frac{2^5.2^2.81}{27.2^5}=\frac{2^5.2^2.27.3}{27.2^5}=2^2.3=12\)

Vậy \(\frac{2^7.9^2}{3^3.2^5}=12\)

\(\frac{2^7\cdot9^2}{3^3\cdot2^5}=\frac{2^7\cdot\left(3^2\right)^2}{3^3\cdot2^5}=\frac{2^7\cdot3^4}{3^3\cdot2^5}=2^2\cdot3=4\cdot3=12\)

\(\dfrac{2^7.9^2}{3^3.2^5}\)

\(=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}\)

\(=\dfrac{2^7.3^4}{3^3.2^5}\)

\(=2^2.3\)

\(=4.3\)

\(=12\)

\(\dfrac{2^7.9^2}{3^3.2^5}=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}=\dfrac{2^7.3^4}{3^3.2^5}=\dfrac{2^2.3}{1}=4.3=12\)

\(\dfrac{2^7.9^2}{3^3.2^5}=\dfrac{2^7.\left(3^2\right)^2}{3^3.2^5}=\dfrac{2^2.3^4}{3^3}=2^2.3=4.3=12\)

Ta có :\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.\left(3^2\right)^2}{3^3.2^5}\)

\(=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1}=12\)

Trả lời:

\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^2.\left(3^2\right)^2}{3^3}=\frac{2^2.3^4}{3^3}=\frac{2^2.3}{1}=4.3=12\)

Học tốt

\(\frac{2^7.9^2}{3^3.2^5}=\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1.1}=12\)

\(\frac{2^7.9^2}{3^3.2^5}\)

\(=\frac{2^{5+2}.\left(3^2\right)^2}{3^3.2^5}\)

\(=\frac{2^5.2^2.3^4}{3^3.2^5}\)

\(=2^2.3\)

\(=4.3\)

\(=12\)

^_^

\(\frac{2^7\cdot9^2}{3^3\cdot2^5}\)

⇒\(\frac{2^7\cdot\left(3^2\right)^2}{3^3\cdot2^5}\)

⇒\(\frac{2^7\cdot3^4}{3^3\cdot2^5}\)

⇒\(2^2\cdot2\)

⇒\(4\cdot2\)

➩\(8\)

Chúc bạn học tốt nhé Thuong Hoai!

=32+63=95

Mk sửa đề nha :

\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)

   \(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

   \(=\frac{-5}{7}.1+\frac{12}{7}\)

   \(=\frac{-5}{7}+\frac{12}{7}\)

   \(=1\)

Study well ! >_<