I

1 B

2 A

3 C

4 A

5 B

6 D

7 C

8 A

II

1 are going to visit

2 went - had  - have you been

3 was

5 do they get up

6 did they do - had

7 has lived

8 have visited

9 is playing

10 has played

11 won't go - will stay

12 watches - isn't watching - is playing

13 got - were

14 stayed - watched

15 has never read

16 won't go - will do

17 likes - is sleeping

18 inviting

19 is

20 is

III

1 B

2 A

3 D

4 B

5 A

6 A

7 C

8 B

9 C

10 C

11 A

12 B

13 B

14 D

15 C

16 B

17 D

18 B

19 D

20 D

21 A

22 A

23 C

số bé là ( 128-54 ) :2=37
số lớn là (128+54):2=91

Số bé là: (128-54):2=37

Số lớn là:128-37=91

HT

Gọi \(M\left(x;y\right)\) là 1 điểm thuộc d \(\Rightarrow2x+y-4=0\) (1)

\(V_{\left(O;2\right)}\left(M\right)=M'\Rightarrow M'\in d'\)

\(\left\{{}\begin{matrix}x'=2x\\y'=2y\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{x'}{2}\\y=\dfrac{y'}{2}\end{matrix}\right.\)

Thế vào (1):

\(2.\left(\dfrac{x'}{2}\right)+\dfrac{y'}{2}-4=0\Leftrightarrow2x'+y'-8=0\)

Vậy pt d' có dạng: \(2x+y-8=0\)

cắt ngắn ra nha b

a.

\(\%_{Fe_{\left(Fe_2O_3\right)}}=\dfrac{56.2}{160}.100\%=70\%\)

\(\%_{O_{\left(Fe_2O_3\right)}}=100\%-70\%=30\%\)

b.

\(\%_{C_{\left(C_6H_{12}O_6\right)}}=\dfrac{12.6}{180}.100\%=7\%\)

\(\%_{H_{\left(C_6H_{12}O_6\right)}}=\dfrac{1.12}{180}.100\%=6,7\%\)

\(\%_{O_{\left(C_6H_{12}O_6\right)}}=100\%-7\%-6,7\%=86,3\%\)

c.

\(\%_{C_{\left(\left(C_6H_{10}O_5\right)_n\right)}}=\dfrac{12.6}{162n}.100\%=44,4n\%\)

\(\%_{H_{\left(\left(C_6H_{10}O_5\right)_n\right)}}=\dfrac{1.10}{162n}.100\%=6,2n\%\)

\(\%_{O_{\left(C_6H_{1o}O_5\right)}}=\dfrac{16.5}{162n}.100\%=49,4n\%\)

\(\Rightarrow49,4n\%=100\%-44,4n\%-6,2n\%\)

\(\Leftrightarrow n=1\)

\(\Rightarrow\left\{{}\begin{matrix}\%_C=44,4\%\\\%_H=6,2\%\\\%_O=49,4\%\end{matrix}\right.\)

d. 

\(\%_{Na_{\left(NaCl\right)}}=\dfrac{23}{58,5}.100\%=39,3\%\)

\(\%_{Cl_{\left(NaCl\right)}}=100\%-39,3\%=60,7\%\)

a/ \(A=1+3+3^2+..........+3^{55}\)

\(\Leftrightarrow3A=3+3^2+...........+3^{55}+3^{56}\)

\(\Leftrightarrow3A-A=\left(3+3^2+........+3^{56}\right)-\left(1+3+....+3^{55}\right)\)

\(\Leftrightarrow2A=3^{56}-1\)

\(\Leftrightarrow A=\frac{3^{56}-1}{2}\)