a) 2345 – 1000 : [19 – 2(21 – 18)2]
b) 128 – [68 + 8(37 – 35)2] : 4
c) 568 – {5[143 – (4 – 1)2] + 10} : 10
d) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3]}:15
e) 307 – [(180 – 160) : 22 + 9] : 2
a) 2345 – 1000 : [19 – 2(21 – 18)2] b) 128 – [68 + 8(37 – 35)2] : 4 c) 568 – {5[143 – (4 – 1)2] + 10} : 10 d) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3]}:15 e) 307 – [(180 – 160) : 22 + 9] : 2 f) 205 – [1200 – (42 – 2.3)3] : 40 g) 177 :[2.(42 – 9) + 32(15 – 10)] h) [(25 – 22.3) + (32.4 + 16)]: 5 i) 125(28 + 72) – 25(32.4 + 64) j) 500 – {5[409 – (23.3 – 21)2] + 103} : 15 |
Viết số mũ giùm mình ạ!
a: \(=47-\left[\left(45\cdot16-25\cdot12\right):14\right]\)
\(=47-30=17\)
b: \(=50-\left[6+34\right]\)
=50-40
=10
k) 2345 – 1000 : [19 – 2(21 – 18)2 ] l) 128 – [68 + 8(37 – 35)2 ] : 4
m) 568 – {5[143 – (4 – 1)2 ] + 10} : 10
n) 107 – {38 + [7.32 – 24 : 6+(9 – 7)3 ]}:15
o) 307 – [(180 – 160) : 22 + 9] : 2
p) 205 – [1200 – (42 – 2.3)3 ] : 40
q) 177 :[2.(42 – 9) + 32 (15 – 10)]
r) [(25 – 2 2 .3) + (32 .4 + 16)]: 5
s) 125(28 + 72) – 25(32 .4 + 64)
giúp mk
s: \(=125\cdot100-25\cdot192\)
\(=12500-4800\)
=7700
2345 - 1000 : [19 - 2(21-18)2 ]
128 - [68 + 8(37 - 352)] : 4
568 - {5[143 - (4 - 1)2 ] + 10 } : 10
107 - {38 + [7.32 - 24 : 6 + (9 - 73 ]} : 15
ai giải nhanh được ticks
2345 - 1000 : [19 - 2(21 - 18)2 ]
128 - [68 + 8(37 - 35)2 ] :4
568 - {5[ 143 - (4 - 1)2 ] : 10
107 - {38 + [7.32 - 24 : 6+(9-7)3 ]} : 15
ai giai nhanh duoc tick
1)2345 - 1000 : [19 - 2(21 - 18)2]
=2345 - 1000 : [19 - 2 . 32]
=2345 - 1000 : 1
=2345 - 1000
=1345
Bài 1: Thực hiện phép tính:
a) 3.52 + 15.22 – 26:2
b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3
d) 2345 – 1000 : [19 – 2(21 – 18)2]
e) 128 – [68 + 8(37 – 35)2] : 4
f) 568 – {5[143 – (4 – 1)2] + 10} : 10
e: \(=128-\left[68+8\cdot4\right]:4=128-25=103\)
\(a.3.5^2+15.2^2-26:2\) \(b.5^3.2-100:4+2^3.5\)
\(=75+60-13\) \(=250-25+40\)
\(=135+13=148\) \(=265\)
\(c.6^2:9+50.2-3^3.3\) \(d.2345-1000:\left[19-2.\left(21-18\right)^2\right]\)
\(=4+100-81\) \(=2345-1000:\left[19-2.3^2\right]\)
\(=23\) \(=2345-1000:\left[19-18\right]\)
\(=2345-1000:1\)
\(=2345-1000=1345\)
\(e.128-\left[68+8.\left(37-35\right)^2\right]:4\)
\(=128-\left[68+8.2^2\right]:4\)
\(=128-\left[68+32\right]:4\)
\(=128-100:4\)
\(=128-25=103\)
\(f.568-\left\{5.\left[143-\left(4-1\right)^2\right]+10\right\}:10\)
\(=568-\left\{5.\left[143-3^2\right]+10\right\}:10\)
\(=568-\left\{5.134+10\right\}:10\)
\(=568-\left\{670+10\right\}:10\)
\(=568-680:10\)
\(=568-68=500\)
a) 47 – [(45.24 – 52.12):14] e) 10 – [(82 – 48).5 + (23.1 + 8) -12] : 28
b) 2010 – 2000 : [486 – 2(72 – 6)] g) 128 – [68 + 8(37 – 35)2] : 4
c) 568 – {5[143 – (4 – 1)2] + 10} : 10
d) 307 – [(180 – 160) : 22 + 9] : 2 h) 205 – [1200 – (42 – 2.3)3] : 40
giúp
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Thực hiện phép tính:
a) 2010 - 2000 : [486 - 2(72 - 6)]
b) 2345 - 1000 : [19 - 2(21 - 18)2 ]
c) 128 - [68 + 8(37 - 35)2 ] : 4
d) 568 - {5[143 - (4 - 1)2 ] + 10} : 10
a) 2010 - 2000 : [486 - 2(72 - 6)]
= 2010 - 2000 : [486 - 2(49 - 6)]
= 2010 - 2000 : [486 - 2 . 43]
= 2010 - 2000 : [486 - 86]
= 2010 - 2000 : 400
= 2010 - 5
= 2005
b) 2345 - 1000 : [19 - 2(21 - 18)2 ]
= 2345 - 1000 : [19 - 2 . 32 ]
= 2345 - 1000 : [19 - 18]
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
c) 128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8 . 22 ] : 4
= 128 - [68 + 32 ] : 4
= 128 - 100 : 4
= 128 - 25
= 103
d) 568 - {5[143 - (4 - 1)2 ] + 10} : 10
= 568 - {5[143 - 9 ] + 10} : 10
= 568 - {5 . 134 + 10 } : 10
= 658 - {670 + 10 } : 10
= 658 - 680 : 10
= 658 - 68
= 590
a) 3.52 + 15.22 – 26:2 b) 53.2 – 100 : 4 + 23.5
c) 62 : 9 + 50.2 – 33.3 d) 32.5 + 23.10 – 81:3
e) 2345 – 1000 : [19 – 2(21 – 18)2] f) 128 – [68 + 8(37 – 35)2] : 4
g) 568 – {5[143 – (4 – 1)2] + 10} : 10 h) 107 – {38 + [7.32 – 24 : 6+(9
\(a.3.52+15.22-26:2\\ 156+330-13\\ =486-13\\ =473\)
\(b.53.2-100:4+23.5\\ =106-25+115\\ =81+115\\ =196\)
Bài 2: Tính hợp lí
1) 125.(-24) + 24.225
2) 512.(2 – 128) – 128. (-512)
3) (187 -23) – (20 – 180)
4) (-37 – 17). (-9) + 35. (-9 – 11)
5) (-50 +19 +143) – (-79 + 25 + 48)
6) (-8).25.(-2). 4. (-5).125
7) 3784 + 23 – 3785 – 15
8) 215 +(-38) – (-58) –15
9) 5.(-3)2 –14.(-8)+(-40)
10) 215 + (-38) – (- 58) + 90 – 852)
Bài 3*: Tìm các cặp số nguyên (x;y) thỏa mãn xy2 + 2x – y2 =
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)