\(2^{20}+3^{30}+4^{30}=4^{10}+9^{10}+64^{10}320^{10}=\left(5.64\right)^{10}=5^{10}.64^{10}>3.64^{10}\)

\(\Rightarrow2^{20}+3^{30}+4^{30}

99²⁰=(99²)¹⁰=9801¹⁰<9999¹⁰

sức mik nhiêu thôi

99²⁰=99¹⁰ *99¹⁰

9999¹⁰=(99*101)¹⁰=99¹⁰*101¹⁰

^=> 9999^10>99²⁰

4^30=2^30*2^30

=2^30*4^15

3*24^10=3*3^10*8^10=3^11*2^30

mà 4^30>3^11

nên 2^30+3^30+4^30>3*24^10

Ta có: 4^30=2^30.2^30=2^30.4^15

3.24^10=3.(3.2^3)^10=2^30.3^11

Ta thấy: 3^11<3^15<4^15 => 4^15>3^11

Vì 4^15>3^11 nên 2^30.4^15>2^30.3^11

=>2^30+3^30+4^30>3.24^10

\(3\times24^{10}\)

\(=3\times\left(2^3\times3\right)^{10}\)

\(=3\times3^{10}\times\left(2^3\right)^{10}\)

\(=3^{11}\times2^{30}\)

\(=3^{11}\times\left(2^2\right)^{15}\)

\(=3^{11}\times4^{15}\)

Vì \(3^{11}\)<\(4^{15}\left(3;4;11;15\inℕ\right)\)

Nên \(3^{11}\times4^{15}\)< \(4^{15}\times4^{15}=4^{30}\)

Do đó : \(3\times24^{10}\)< \(4^{30}\)

Vậy \(2^{30}+3^{30}+4^{30}\)> \(3\times24^{10}\)

4^30=2^30*2^30

=2^30*4^15

3*24^10=3*3^10*8^10=3^11*2^30

mà 4^30>3^11

nên 2^30+3^30+4^30>3*24^10

4^30=2^30*2^30

=2^30*4^15

3*24^10=3*3^10*8^10=3^11*2^30

mà 4^30>3^11

nên 2^30+3^30+4^30>3*24^10

99²⁰ = 99^2.10 = (99²)¹⁰ = 9801¹⁰ < 9999¹⁰ ( vì 9801 < 9999 ) nên 99²⁰<9999¹⁰.

3¹⁷>3¹⁶ = 3^2.8 = (3²)⁸ = 9⁸

2³² = 2^4.8 = (2⁴)⁸ = 16⁸

16⁸ > 9⁸ ( vì 16>9 ) nên 3¹⁷<2³²