\(a,\left(x-15\right)\times7-270=169\times45\\ \left(x-15\right)\times7-270=7605\\ \left(x-15\right)\times7=7605+270\\ \left(x-15\right)\times7=7875\\ x-15=7875:7\\ x-15=1125\\ x=1125+15\\ x=1140\\ b,64-\left(34\times x-8\right)=4\\ 34\times x-8=64-4\\ 34\times x-8=60\\ 34\times x=60+8\\ 34\times x=68\\ x=68:34\\ x=2\)

a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)

\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)

=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)

b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)

\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)

Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)

c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)

\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)

=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)

d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)

\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6

=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)

Tính nhanh:

a) 36.(65-79)+65|35-79|

=36.(-14) + 65.44

=-504 + 2860

=2356

b) 12.(34-86)+34.(86-12)+86.(12-34)-12.(34+86)

= 12.(-52) +34.74+86. (-22) - 12.120

=-624 + 2516 +(-1892) -1440

= 1892 + (-1892) -1440

=0- 1440

=-1440

a) 36 . (-14) + 65 . 44

= -504 + 2860

= 2356

Mình làm cho bạn câu cuối

...(x-3)+(x-2)+(x-1)+0+1+2+...+11=11

VP =11

=> VT=11

Để VT =11 cần có đủ cặp số đối đến (10)=> x-3=-10=> x=-7

34*56+34+43+34

=34*(56+43+1)

=34*100

=3400

15*23+15+53+15*23+15

=15*(23+53+23+1)

=15*100

=1500

a, 34 x 56 + 34 x 43 + 34

= 34 x ( 56 + 43 + 1 )

= 34 x 100

= 3400

b, 15 x 23 + 15 + 53 + 15 x 23 + 15

= 15 x ( 23 + 53 + 23 + 1 )

= 15 x 100

= 1500

a, 34 x 56 + 34 x 43 + 34 = 34 x ( 56 + 43 + 1 )

                                      = 34 x 100

                                      = 3400

b, 15 x 23 + 15 x 53 + 15 x 23 + 15 = 15 x ( 23 + 53 + 23 + 1 )

                                                     = 15 x 100

                                                     = 1500

(8,9 x 14,7 + 2,5 x 14,7) x (34 x 11 - 3400 x 0,1 - 34)

= (8,9 x 14,7 + 2,5 x 14,7) x (34 x 11 - 3400 : 10 - 34)

= [14,7 x (8,9 + 2,5)] x (34 x 11 - 34 x 10 - 34 x 1)

= (14,7 x 11,4) x [34 x (11 - 10 - 1)]

= (14,7 x 11,4) x (34 x 0)

= 0

 ( 14,7 x(8,9 + 2,5) ) x (34 x (11-100x0,1-1 )

=(14,7x11,4)x(34.(11-10-1))

=(14,7x11,4)x(34.0)

=(14,7x11,4)x0

=0

thanks ạ ☘

a) -21 + (4 - x) = -17 + (-20) + 5

=>-21 + 4 - x = -32

=> -17 - x = -32

=> x = -17 + 32

=> x = 15

b) (15 - x) - (+9) = 34 - (-31)

=> 15 - x - 9 = 34 + 31

=> 6 - x = 65

=> x = 6 - 65

=> x = -59

c) (17 + x) - (-12) = -14 - (-10)

=> 17 + x + 12 = -14 + 10

=> 29 + x = -4

=>  x = -4 - 29

=> x = -33

c) (x + 24) + 15 = 8 - 17

=> x + 24  + 15 = -9

=> x + 39 = -9

=> x = -9 - 39

=> x = -48

A -21+ ( 4 - x ) = - 17 + ( -20 ) + 5

-21 + 4 - x = - 37 + 5

- 17 - x = - 32

-x = - 17 - ( - 32 )

-x = - 17 + 32

- x = 15

=> x = -15

B   ( 15 - x ) - ( + 9 ) = 34 - ( - 31 )

15 - x - 9 = 34 + 31

15 - 9 - x = 65

6 - x = 65

x = 6 - 65

x = -59

C , ( 17 + x ) - ( - 12 ) = - 14 - ( - 10 )

17 + x + 12 = - 14 + 10

29 + x = - 4

x = - 4 - 29

x = - 33

D , ( x + 24 ) + 15 = 8 - 17

x + 24 + 15 = - 9

x + 39 = -9

x = - 9 - 39

x = - 48

1) 42/35 - [ 33/14 . 21/22 - ( 54/25 : 27/25 - 7/10 )]

= 42/35 - ( 9/4-13/10)

=42/35-19/20

=1/4

2) a) 5/21 . x/34 = 35/102     

x/34=35/102 : 5/21

x/34=49/34

=> x=34

Vậy x=34

b) 15/x . 21/13 = 45/91

15/x=45/91 : 21/13

15/x=15/49

=> x=49

Vậy x=49

lớp 4

mik chỉ ghi kết quả thôi nha

vì làm ra dài dòng lw

=> ta có:

x = 7

x = 4

x = 3

x = 4

x = 3

nha bn

5(x-7)=0

=>x-7=0

=>x=0+7

=>x=7

25(x-4)=0

=>x-4=0

=>x=0+4

=>x=4

34(2x-6)=0

=>2x-6=0

=>2x=0+6

=>2x=6

=>x=6:2

=>x=3

2016(3x-12)=0

=>3x-12=0

=>3x=0+12

=>3x=12

=>x=12:3

=>x=4

47(5x-15)=0

=>5x-15=0

=>5x=0+15

=>5x=15

=>x=15:5

=>x=3

5(x-7)=0

=>x-7=0

=>x=0+7

=>x=7

25(x-4)=0

=>x-4=0

=>x=0+4

=>x=4

34(2x-6)=0

=>2x-6=0

=>2x=0+6

=>2x=6

=>x=6:2

=>x=3

2016(3x-12)=0

=>3x-12=0

=>3x=0+12

=>3x=12

=>x=12:3

=>x=4

47(5x-15)=0

=>5x-15=0

=>5x=0+15

=>5x=15

=>x=15:5

=>x=3