`2x-15=-25`

`2x=-10`

`x=-5`

___________

`3/5<x/10<4/5`

`3/5=(3xx10)/(5xx10)=30/50`

`x/10=(5x)/(10xx5)=(5x)/50`

`4/5=(4xx10)/(5xx10)=40/50`

`=>30/50<(5x)/50<40/50`

`=>30<5x<40`

`=>x=7`

mình chỉ tính vế bên thôi nhé bn tích x

\(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{25.28}\)

\(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-.....+\frac{1}{25}-\frac{1}{28}\right)\)

=\(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

=\(???\)

ban oi sai roi

ban oi minh cung lam giong zay nhung sai

a/\(\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{25}{28}\)
\(=1\times\dfrac{25}{28}\)
\(=\dfrac{25}{28}\)
b/\(\dfrac{4}{7}\times\dfrac{17}{18}\times\dfrac{7}{4}\times\dfrac{18}{17}\)
\(=\left(\dfrac{4}{7}\times\dfrac{7}{4}\right)\times\left(\dfrac{17}{18}\times\dfrac{18}{17}\right)\)
\(=1\times1\)
\(=1\)

\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\left(x+\dfrac{1}{5}\right)^2=\left(\dfrac{3}{5}\right)^2\)

➩ \(x+\dfrac{1}{5}=\dfrac{3}{5}\)

    \(x=\dfrac{3}{5}-\dfrac{1}{5}\)

   \(x=\dfrac{2}{5}\)

1) ĐKXĐ: \(x\notin\left\{1;-2\right\}\)

Ta có: \(\dfrac{2x}{x-1}-\dfrac{1}{x+2}=2\)

\(\Leftrightarrow\dfrac{2x\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}-\dfrac{x-1}{\left(x-1\right)\left(x+2\right)}=\dfrac{2\left(x-1\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)}\)

Suy ra: \(2x^2+4x-x+1=2\left(x^2+x-2\right)\)

\(\Leftrightarrow2x^2+3x+1=2x^2+2x-4\)

\(\Leftrightarrow2x^2+3x+1-2x^2-2x+4=0\)

\(\Leftrightarrow x+5=0\)

hay x=-5(thỏa ĐK)

Vậy: S={-5}

2) ĐKXĐ: \(x\notin\left\{5;-5\right\}\)

Ta có: \(\dfrac{x}{x^2-25}-\dfrac{1-x}{x-5}=\dfrac{1}{x+5}\)

\(\Leftrightarrow\dfrac{x}{\left(x-5\right)\left(x+5\right)}+\dfrac{\left(x-1\right)\left(x+5\right)}{\left(x-5\right)\left(x+5\right)}=\dfrac{x-5}{\left(x+5\right)\left(x-5\right)}\)

Suy ra: \(x+x^2+5x-x-5=x-5\)

\(\Leftrightarrow x^2+5x-5-x+5=0\)

\(\Leftrightarrow x^2+4x=0\)

\(\Leftrightarrow x\left(x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(nhận\right)\\x=-4\left(nhận\right)\end{matrix}\right.\)

Vậy: S={0;-4}

a/ ĐKXĐ : \(x\ne1;-2\)

\(\dfrac{2x}{x-1}-\dfrac{1}{x+2}=2\)

\(\Leftrightarrow\dfrac{2x\left(x+2\right)-\left(x-1\right)}{\left(x-1\right)\left(x+2\right)}=2\)

\(\Leftrightarrow2x^2+3x-x+1=2x^2+4x-2x-4\)

\(\Leftrightarrow2x+1=2x-4\)

\(\Leftrightarrow1=-4\left(loại\right)\)

Vậy...

b/ĐKXĐ :  \(x\ne\pm5\)

\(\dfrac{x}{x^2-25}-\dfrac{1-x}{x-5}=\dfrac{1}{x+5}\)

\(\Leftrightarrow\dfrac{x}{\left(x-5\right)\left(x+5\right)}+\dfrac{\left(x-1\right)\left(x+5\right)}{\left(x+5\right)\left(x-5\right)}=\dfrac{x-5}{\left(x+5\right)\left(x-5\right)}\)

\(\Leftrightarrow x+x^2+5x-x-5=x-5\)

\(\Leftrightarrow x^2+4x=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)

Vậy...

\(\left(\dfrac{1}{3}+\dfrac{1}{5}\right).x=\dfrac{8}{25}\)

\(\dfrac{8}{15}.x=\dfrac{8}{25}\)

\(x=\dfrac{8}{25}:\dfrac{8}{15}\)

\(x=\dfrac{3}{5}\)

3/25 x ( 15/7 - 2/7 ) + 3/7 x 1/25 

= 3/25 x 13/7 + 3/7 x 1/25 

= (3 x 13/7 + 3/7 ) x 1/25 

= 42/7 x 1/25 

= 6 x 1/25 

= 6/25

\(\dfrac{3}{25}\times\dfrac{15}{7}+\dfrac{3}{7}\times\dfrac{1}{25}-\dfrac{2}{7}\times\dfrac{3}{25}\)

\(=\dfrac{3}{25}\times\left(\dfrac{15}{7}-\dfrac{2}{7}\right)+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3}{25}\times\dfrac{13}{7}+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3\times13}{25\times7}+\dfrac{3\times1}{7\times25}\)

\(=\dfrac{39}{175}+\dfrac{3}{175}\)

\(=\dfrac{39+3}{175}\)

\(=\dfrac{42}{175}\)

\(=\dfrac{6}{25}\)

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{15}{7}\) + \(\dfrac{3}{25}\) \(\times\) \(\dfrac{1}{7}\) - \(\dfrac{2}{7}\times\) \(\dfrac{3}{25}\)

A = \(\dfrac{3}{25}\) \(\times\)( \(\dfrac{15}{7}\) + \(\dfrac{1}{7}-\dfrac{2}{7}\))

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{14}{7}\)

A = \(\dfrac{6}{25}\)

a, 7x + 10x  = 5x 

    17x = 5x

17x - 5x = 0

      12x = 0

          x =0

2; 

a, 4x + 7x = 22

    11x = 22

        x = 2

b, 12x - 8x = 25

     4x = 25

       x = \(\dfrac{25}{4}\)

c,  \(\dfrac{1}{2}\)x - \(\dfrac{1}{3}\)x = \(\dfrac{4}{5}\) 

     (\(\dfrac{1}{2}-\dfrac{1}{3}\))x = \(\dfrac{4}{5}\)

    \(\dfrac{1}{6}\)x     = \(\dfrac{4}{5}\) 

      x = \(\dfrac{4}{5}\) : \(\dfrac{1}{6}\)

     x = \(\dfrac{24}{5}\)

a, 2x3x4x8x25x125= (2x3)x(4x25)x(8x125)= 6x100x1000=600000

b,42/5 +56/9+23/4+3/5+1/3+1/4= (42/5+3/5)+(23/4+1/4)+(56/9+1/3)=9+6+59/9=

a)  2 x 3 x 4 x 8 x 25 x 125=600000

b) 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4=14

a)  2 x 3 x 4 x 8 x 25 x 125

=(2x3)x(4x25)x(8x125)

=6x100x1000

=600000

b) 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4

(4+\(\frac{2}{5}\)+\(\frac{3}{5}\))+(5+\(\frac{6}{9}\)+1/3)+(2+\(\frac{3}{4}\)+\(\frac{1}{4}\))

=(4+1)+(5+1)+(2+1)

=5+6+3

=14

a) \(\dfrac{7}{5}x\div\left(9-6\dfrac{13}{21}\right)=2\dfrac{13}{25}\)

\(\dfrac{7}{5}x\div\left(9-\dfrac{139}{21}\right)=\dfrac{63}{25}\)

\(\dfrac{7}{5}x\div\dfrac{50}{21}=\dfrac{63}{25}\)

\(\dfrac{7}{5}x=6\)

\(x=\dfrac{30}{7}\)

b) \(\left(1,16-x\right)\times5,25\div\left(10\dfrac{5}{9}-7\dfrac{1}{4}\right)\times2\dfrac{2}{17}=75\%\)

\(\left(1,16-x\right)\times5,25\div\left(\dfrac{95}{9}-\dfrac{29}{4}\right)\times\dfrac{36}{17}=\dfrac{75}{100}\)

\(\left(1,16-x\right)\times5,25\div\dfrac{119}{36}=\dfrac{17}{48}\)

\(\left(1,16-x\right)\times5,25=\dfrac{2023}{1728}\)

\(1,16-x=\dfrac{289}{1296}\)

\(x=0,9370061728\)

52 ×.(y : 78) = 3380

         y : 78   = 3380 : 52

         y : 78   = 65

         y           = 65 ×. 78

         y           = 5070