\(\frac{6^2.15-6^3}{13.3^2-4.3^2}\)

\(=\frac{6^2.15-6^2.6}{\left(13-4\right)3^2}\)

\(=\frac{6^2\left(15-6\right)}{9.3^2}\)

\(=\frac{6^2.9}{9.3^2}\)

\(=\frac{6^2}{3^2}\)

\(=\frac{3^2.2^2}{3^2}\)

\(=2^2\)

\(=4\)

\(\frac{6^2.15-6^3}{13.3^2-4.3^2}=\frac{6^2\left(15-6\right)}{3^2\left(13-4\right)}=\frac{6^2.9}{3^2.9}=2^2\)

\(\frac{6^2.15-6^3}{13.3^2-4.3^2}=\frac{6^2\left(15-1\right)}{3^2\left(13-4\right)}=\frac{6^2.14}{3^2.9}=\frac{2^3.3^2.7}{3^4}=\frac{2^3.7}{3^2}=\frac{56}{9}\)

\(=13\cdot\dfrac{3^n}{3^m\cdot2^m}=\dfrac{13\cdot3^{n-m}}{2^m}\)

-0,26

p/s: bấm máy tính có thể sai chỗ nào đó nên sai không chịu trách nhiệm đâu nhé @@

=\(-\frac{13}{50}\)=-0,26

dễ vậy hỏi làm gì.chịu khó bấm máy cho quen

Câu 1 xem kỉ đề

\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)

a) A=2¹².3⁵-\(\frac{2^{12}.3^6}{2^{12}}\)+9³+8⁴.3⁵

=2¹².3⁵-3⁶+3⁶+2¹².3⁵

=2¹³.3⁵

^b)B=49⁶.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)

=49⁶.5-7.5-2.49⁵

⁼7¹².5-7.5-2.7¹⁰

Ta có : 

\(\frac{4.5}{2.15}=\frac{2.1}{1.3}=\frac{2}{3}\)

Tham khảo nha !!!