PTĐTTNT :
9-16(x-1)^2
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ptđttnt
x3-9x2+6x+16
1 câu thôi giúp nhá
nhẩm x=-1 là nghiệm
\(\left(x+1\right)\left(x^2-10x+16\right)=\left(x+1\right)\left[\left(x-5\right)^2-9\right]=\left(x+1\right)\left(x-8\right)\left(x-2\right)\)
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PTĐTTNT:
a) x(x+1)2 + x(x-5) - 5(x+1)
b) 25x2 - 4y2 - 9 + 12y
1)x^2-2x+1+x^2y-xy
2)x^2+6x+9+x^2y+3x^2y
Làm theo PTĐTTNT bằng cách nhóm các hạng tử
Lm giúp m vs nha
Xem chi tiết
1) \(x^2-2x+1+x^2y-xy=\left(x-1\right)^2+xy\left(x-1\right)=\left(x-1\right)\left(x+xy-1\right)\)
2) \(x^2+6x+9+x^2y+3xy\)
\(=\left(x+3\right)^2+xy\left(x+3\right)\)
\(=\left(x+3\right)\left(x+xy+3\right)\)
I : PTĐTTNT
\(\left(x^2-3\right)^2+16\)
help me
\(x^4-6x^2+25=x^4+10x^2+25-16x^2\)
\(=\left(x^2+5\right)^2-\left(4x\right)^2=\left(x^2-4x+5\right)\left(x^2+4x+5\right)\)
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\(=x^4-6x^2+25\)
\(=x^4+10x^2+25-16x^2\)
\(=\left(x^2+5\right)^2-\left(4x\right)^2\)
\(=\left(x^2-4x+5\right)\left(x^2+4x+5\right)\)
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I : PTĐTTNT
a)A= (x-1)(x+2)(x+7)-16
b) A= \(\left(x^2-x-2\right)^2+\left(x-2\right)^2\)
c) \(81x^4+4\)
d) \(\left(x^2-3\right)^2+16\)
help me
a) \(A=\left(x^2+x-2\right)\left(x+7\right)-16\)
\(=x^3+8x^2+5x-14-16\)
\(=x^3+8x^2+5x-30\)
\(=x^3+3x^2+5x^2+15x-10x-30\)
\(=x^2\left(x+3\right)+5x\left(x+3\right)-10\left(x+3\right)\)
\(=\left(x^2+5x-10\right)\left(x+3\right)\)
b) \(A=x^4-2x^3-3x^2+4x+4+x^2-4x+4\)
\(=x^4-2x^3-2x^2+8\)
\(=x^3\left(x-2\right)-2\left(x^2-4\right)\)
\(=\left(x-2\right)\left(x^3-2x-4\right)\)
\(=\left(x-2\right)\left[x^2\left(x+2\right)+2x\left(x+2\right)-2\left(x+2\right)\right]\)
\(=\left(x-2\right)\left(x+2\right)\left(x^2+2x-2\right)\)
c) \(81x^4+4=81x^4+36x^2+4-36x^2\)
\(=\left(9x^2+2\right)^2-\left(6x\right)^2\)
\(=\left(9x^2-6x+2\right)\left(9x^2+6x+2\right)\)
d) \(\left(x^2-3\right)^2+16=x^4-6x^2+25\)
\(=\left(x^4+10x^2+25\right)-16x^2\)
\(=\left(x^2+5\right)^2-\left(4x\right)^2\)
\(=\left(x^2-4x+5\right)\left(x^2+4x+5\right)\)
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sửa câu b) xíu nha!
\(A=\left(x-2\right)\left(x^3-2x-4\right)\)
\(=\left(x-2\right)\left[x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\right]\)
\(=\left(x-2\right)^2\left(x^2+2x+2\right)\)
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tl nhanh cho mik nhá, mik đag cần gấp. Tks nhiều :)))
1, Rút gọn biểu thức sau:
a, (2x-3)(x+2)-2(x+1)^2
b,(x-2)^2+2(x-2)(2x+2)+4(x+1)^2
c,(x^2-2x+4)(x+2)-(x-1)^3+3(x-1)(x+1)
d,(x+y+z-t)^2-(-x-y-z+t)^2
e,(x+1)^3-3(x-2)(x+1)-(x^2+x+1)(x+1)
2,PTĐTTNT
a,x^2-9-x^2(x^2-9)
b, 9x^2-25y^2-6x+10y
c,x^2-8x-4y^2+16
PTĐTTNT
`x^12+x^2+1`
PTĐTTNT
(x+1)(x+2)(x+3)(x+4) + 1
\(\left(x+1\right)\left(x+4\right)\left(x+2\right)\left(x+3\right)+1\)
\(=\left(x^2+5x+4\right)\left(x^2+5x+6\right)+1\)
\(=\left(x^2+5x+4\right)^2+2\left(x^2+5x+4\right)+1\)
\(=\left(x^2+5x+4+1\right)^2\)
\(=\left(x^2+5x+5\right)^2\)
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Tìm x
a/ 8x^2-(2x+5)(4x-2)-9=0
PTĐTTNT
1/ 5x^2-10-x+2
2/ 3x^2-6xy-3y^2-12z^2
3/ x^2-3x+2
Tìm x:
\(8x^2-\left(2x+5\right)\left(4x-2\right)-9=0\)
\(\Leftrightarrow8x^2-\left(8x^2-4x+20x-10\right)-9=0\)
\(\Leftrightarrow8x^2-8x^2+4x-20x+10-9=0\)
\(\Leftrightarrow-16x+1=0\)
\(\Leftrightarrow-16x=-1\)
\(\Leftrightarrow x=\dfrac{-1}{-16}=\dfrac{1}{16}\)
Vậy \(x=\dfrac{1}{16}\)
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Bài 1:
\(a,8x^2-\left(2x+5\right)\left(4x-2\right)-9=0\)
\(\Rightarrow8x^2-\left(8x^2+16x-10\right)-9=0\)
\(\Rightarrow8x^2-8x^2-16x+10-9=0\)
\(\Rightarrow-16x+1=0\)
\(\Rightarrow x=\dfrac{1}{16}\)
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Tìm x:
a) 8x2 - (2x + 5)(4x - 2) - 9 =0
8x2 - (8x2 - 4x + 20x - 10) - 9= 0
8x2 - (8x2 + 16x - 10) - 9 =0
8x2 - 8x2 - 16x + 10 - 9 = 0
- 16x + 1 =0
- 16x = - 1
x = \(\frac{1}{16}\)
Vậy \(x = \frac{1}{16}\)
PTĐTTNT:
3/ x2 - 3x + 2
= x2 - x - 2x + 2
= x(x - 1) - 2(x - 1)
= (x - 1)(x - 2)
pn coi lại câu 1 và 2 nhé
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