= 32-4\(^2\)(x-1)\(^2\)
=[3-4(x-1)].[(3+4(x-1)]
=(3-4x+4)(3+4x-4)
=(7-4x)(4x-1)
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= 32-4\(^2\)(x-1)\(^2\)
=[3-4(x-1)].[(3+4(x-1)]
=(3-4x+4)(3+4x-4)
=(7-4x)(4x-1)
ptđttnt
x3-9x2+6x+16
1 câu thôi giúp nhá
tl nhanh cho mik nhá, mik đag cần gấp. Tks nhiều :)))
1, Rút gọn biểu thức sau:
a, (2x-3)(x+2)-2(x+1)^2
b,(x-2)^2+2(x-2)(2x+2)+4(x+1)^2
c,(x^2-2x+4)(x+2)-(x-1)^3+3(x-1)(x+1)
d,(x+y+z-t)^2-(-x-y-z+t)^2
e,(x+1)^3-3(x-2)(x+1)-(x^2+x+1)(x+1)
2,PTĐTTNT
a,x^2-9-x^2(x^2-9)
b, 9x^2-25y^2-6x+10y
c,x^2-8x-4y^2+16
PTĐTTNT
`x^12+x^2+1`
PTĐTTNT
a,(x2+y2-5)2 -4x2y2 -16xy-16
b,x3+5x2+8x+4
c,x3-6x2-x+30
d,125x3-10x2+2x-1
PTĐTTNT :
`-(x+2)+3(x^2-4)`
1,PTĐTTNT:
x2+6xy+9y2-3x-9y+2
x ³ + y ³ -2(x ² - y ²)
ptđttnt
PTĐTTNT :
x^2-(m+n)x+mn