\(10^{80}=\left(10^8\right)^{10}=1000000000^{10}\)

\(30^{50}=\left(30^5\right)^{10}=24300000^{10}\)

Ta có: \(1000000000>24300000\)

\(\Rightarrow1000000000^{10}>24300000^{10}\)

\(\Rightarrow10^{80}>30^{50}\)

Tham khảo nhé~

Ta có:

\(\left(-5\right)^{30}=\left(-5^3\right)^{10}=\left(-125\right)^{10}=125^{10}\)

\(\left(-3\right)^{50}=\left(-3^5\right)^{10}=\left(-81\right)^{10}=81^{10}\)

Vì \(125^{10}>81^{10}\)

⇒\(\left(-5\right)^{30}>\left(-3\right)^{50}\)

\(\left(-5\right)^{30}\) và \(\left(-3\right)^{50}\)

Ta có: \(\left(-5\right)^{30}=\left[\left(-5\right)^3\right]^{10}=\left(-125\right)^{10}\)

\(\left(-3\right)^{50}=\left[\left(-3\right)^5\right]^{10}=\left(-243\right)^{10}\)

Vì \(\left(-125\right)^{10}< \left(-243\right)^{10}\) nên \(\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(3^{40}=\left(3^4\right)^{10}=81^{10}\)

\(4^{30}=\left(4^3\right)^{10}=64^{10}\)

Vì \(81>64\)

`-> 81^10 > 64^10`

`-> 3^40 > 4^30`

`----`

`2^75=(2^3)^25=8^25`

`3^50=(3^2)^25=9^25`

Vì `9>8`

`-> 9^25 > 8^25`

`-> 3^50 > 2^75`.

a: 3^40=81^10

4^30=64^10

=>3^40>4^30

b: 2^75=8^25

3^50=9^25

=>2^75<3^50

Có : (-1/5)^30 = -1/5^30

(-1/5)^50 = -1/5^50

Ta có : 5^30 < 5^50 => 1/5^30 > 1/5^50

=> -1/5^30 < -1/5^50

=> (-1/5)^30 < (-1/5)^50

Tk mk nha

\(\left(\frac{-1}{5}\right)^{30}=-\left(\frac{1}{5}\right)^{30}=-\left(\frac{1}{5^{30}}\right)\)

\(\left(\frac{-1}{5}\right)^{50}=-\left(\frac{1}{5}\right)^{50}=-\left(\frac{1}{5^{50}}\right)\)

ta thấy \(5^{30}< 5^{50}\Rightarrow\frac{1}{5^{30}}>\frac{1}{5^{50}}\Rightarrow-\left(\frac{1}{5^{30}}\right)< -\left(\frac{5}{5^{50}}\right)\)

\(\Rightarrow\left(\frac{-1}{5}\right)^{30}< \left(\frac{-1}{5}\right)^{50}\)

\(\left(-5\right)^{30}=5^{30}=5^{3.10}=\left(5^3\right)^{10}=125^{10}\)

\(\left(-3\right)^{50}=3^{50}=3^{5.10}=\left(3^5\right)^{10}=243^{10}\)

do   \(125^{10}< 243^{10}\)

nên   \(\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(\left(-5\right)^{30}=\left[\left(-5\right)^3\right]^{10}=125^{10}\)

\(\left(-3\right)^{50}=\left[\left(-3\right)^5\right]^{10}=243^{10}\)

mà \(125^{10}< 243^{10}=>\left(-5\right)^{30}< \left(-3\right)^{50}\)

\(7^{50}=\left(7^5\right)^{10}=16807^{10}>2197^{10}=\left(13^3\right)^{10}=13^{30}\)

4⁵⁰=  ( 4³ ) ^50/3 = 64 ^50/3

8³⁰ =( 8² ) ¹⁵ = 64¹⁵

ta có 50/3 > 15 => 4⁵⁰ > 8³⁰

\(4^{50}\)= \(\left(2^2\right)^{^{50}^{ }}\)\(=2^{100}\)

\(8^{30}=\left(2^3\right)^{30}=2^{90}\)

vì \(2^{100}>2^{90}\)nên\(4^{50}>8^{30}\)

(-5)^30=(-5)^(3.10)

=(-125)^10

(-3)^50=(-3)^(5.10)=(-243)^10

tuân theo quy luật mũ chẵn luôn dương mà |-125|<|-243| nên (-5)^30>(-3)^50

ta co: (-5)³⁰=((-5)³)¹⁰=(-125)¹⁰

             (-3)⁵⁰=((-3)⁵)¹⁰=(-243)¹⁰

Vì (-125)>(-243) nên (-125)¹⁰>(-243)¹⁰

Vậy (-5)³⁰>(-3)⁵⁰

a, 24^10 < 3^30 + 4^30 + 5^30

b, 2^100 < 5^50 < 3^75.