\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=\)-480
BÌNH THƯỜNG LÀ =480 NHƯNG THỬ
2^x + 2^(x+1) + 2^(x+2) + 2^(x+3)=480
2^x × (1 + 2 + 2^2 + 2^3)= 480
2^x × 15 = 480
2^x =32
x = 5
2^x+2^x+1+2^x+2+2^x+3 = 480
Ta có : 2^x + 2^x+1 + 2^x+2 + 2^x+3 = 480
=> 2^x . (1+2+2^2+2^3)=480
=> 2^x . 15=480
=> 2^x=480:15
=> 2^x=32
=> 2^x=2^5
=> x=5
Vậy x=5
Tk và kb với mk nha :)))
Ta có: \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=480\)
\(\Rightarrow2^x.\left(1+2+2^2+2^3\right)=480\)
\(\Rightarrow2^x.15=480\)
\(\Rightarrow2^x=480\div15=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
Tìm x
2^x + 2^x+1 + 2^x+2 + 2^x+3= 480
\(2^x+2^x+1+2^x+2+2^x+3=480\)
\(8^x+6=480\)
\(8^x=474\)
\(\Rightarrow x\in\varnothing\)
a)2^x+2^x+1+2^x+2+2^x+3=480
b)(1/2+1/3+...+1/2012+1/2013)*x=2012/1+2011/2+2010/3+..+2/2011+1/2012
Tìm x biết:
2^x + 2^x+1 + 2^x+2 + 2^x+3 - 480 = 0
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}-480=0\)
\(\Leftrightarrow2^x\left(1+2+2^2+2^3\right)-480=0\)
\(\Leftrightarrow2^x.15-480=0\)
\(\Leftrightarrow2^x.15=480\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
Vậy ..
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\) tìm x
2x + 2x + 1 + 2x + 2 + 2x + 3 = 480
=> 2x.(1 + 2 + 4 + 8) = 480
=> 2x.15 = 480
=> 2x = 480 : 15
=> 2x = 32
=> 2x = 25
=> x = 5
có \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=\)480
\(2^x\cdot1+2^x\cdot2+2^x\cdot4+2^x\cdot8=480\)
\(2^x\cdot\left(1+2+4+8\right)=480\)
\(2^x\cdot15=480\)
\(2^x=32\)
do đó x = 5
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x\times\left(1+2+4+8\right)=480\)
\(\Rightarrow2^x\times15=480\)
\(\Rightarrow2^x=480:15\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=32=2^5\)
\(\Rightarrow x=5\)
Tìm x biết
1)(x-0)^6-(x-2)^8
2)2^x+2^x+1+2^x+2+2^x+3=480
câu 1 sai đề :>>>
1) \(\left(x-2\right)^6=\left(x-2\right)^8\)
\(\Leftrightarrow\left(x-2\right)^8-\left(x-2\right)^6=0\)
\(\Leftrightarrow\left(x-2\right)^6.\left[\left(x-2\right)^2-1\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\\left(x-2\right)^2=1\end{cases}}\) \(\Leftrightarrow\orbr{\begin{cases}x=2\\x=3,x=1\end{cases}}\)
2) \(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Leftrightarrow2^x.\left(1+2+2^2+2^3\right)=480\)
\(\Leftrightarrow2^x.15=480\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Leftrightarrow x=5\)
2x+2x+1+2x+2+2x+3=480. Tìm x.
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(2^x+2^x.2+2^x.4+2^x.8=480\)
\(2^x.\left(1+2+4+8\right)=480\)
\(2^x.15=480\)
\(2^x=32\)
\(2^x=2^5\)
\(x=5\)
Vậy \(x=5\)
2x+2x+1+2x+2+2x+3=480
\(\Leftrightarrow2^x\left(1+2+2^2+2^3\right)=480\)
\(\Leftrightarrow2^x.15=480\)
\(\Leftrightarrow2^x=32=2^5\)
\(\Leftrightarrow x=5\)
2x+2x+1+2x+2+2x+3=480
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=480\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=480\)
\(\Rightarrow2^x.\left(1+2+2^2+2^3\right)=480\)
\(\Rightarrow2^x.15=480\)
\(\Rightarrow2^x=480:15\)
\(\Rightarrow2^x=32\)
\(\Rightarrow x=5\)
Chúc bạn học tốt !!!!