Tính hợp lí
\(\frac{\left(1,2\right)^{10}.25^5}{\left(-12\right)^8}\)
Tính hợp lí: E =\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}\)+ (1,2 . 0,5 ) : \(\frac{4}{5}\)
Tính
a,\(\frac{2^{10}\cdot55+2^{10}\cdot26}{2^8\cdot27}\)
b,120:{300:[150-(2.53-23.25)]}
c,\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\cdot40\%+0,15\right]:\frac{-5}{52}\)
d,\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\left(1,2+0,5\right):\frac{1}{5}\)
tính hợp lí
\(\left[\left(25\frac{12}{67}+9\frac{13}{41}\right)_{ }-\left(8\frac{12}{67}-3\frac{28}{41}\right)\right]X\frac{21}{-13}\)
làm ơn giúp mk nhanh nhé mai mk đi học rồi
\(=\left(25+\dfrac{12}{67}+9+\dfrac{13}{41}-8-\dfrac{12}{67}+3+\dfrac{28}{41}\right)\cdot\dfrac{-21}{13}\)
\(=\left(25+9-8+3+1\right)\cdot\dfrac{-21}{13}=\dfrac{-630}{13}\)
TÍNH BẰNG CÁCH HỢP LÍ NHẤT
\(\frac{5}{3}+\left(\frac{-2}{7}\right)-\left(-1,2\right)\)
\(\frac{5}{3}+\left(-\frac{2}{7}\right)-\left(-1.2\right)\)
\(=\frac{5}{3}+\left(-\frac{2}{7}\right)+1.2\)
\(=\frac{271}{105}\)
tíc mình nha
Tính hợp lí:
a) \(A=\left(\frac{3}{4}-\frac{4}{7}-\frac{5}{6}\right):\left(-\frac{3}{10}+\frac{4}{14}-\frac{-5}{12}\right)\left(\frac{1}{12}-\frac{7}{6}\right)\)
b) 123.(-234+4356-2312)+234.(123-2312)-2312.(-234-123)
a: \(A=\dfrac{63-48-70}{84}:\dfrac{-3\cdot84+4\cdot60+5\cdot70}{840}\cdot\dfrac{1-14}{12}\)
\(=\dfrac{-55}{84}\cdot\dfrac{840}{338}\cdot\dfrac{-13}{12}=\dfrac{55}{1}\cdot\dfrac{10}{338}\cdot\dfrac{13}{12}=\dfrac{275}{156}\)
b: \(=-234\cdot123+123\cdot4356-123\cdot2312+234\cdot123-234\cdot2312+2312\cdot234+2312\cdot123\)
\(=123\cdot4356-123\cdot2312+123\cdot2312=123\cdot4356=535788\)
Bài 1. Tính hợp lí nếu có thể:
a) \(10\frac{1}{4}:\left(\frac{-3}{5}\right)-8\frac{1}{4}:\left(\frac{-3}{5}\right)-5\)
b) \(\sqrt{\frac{25}{49}}+\left(-2013\right)^0+I\frac{-2}{7}I+\frac{2^{10}.8^3}{4^9}\)
Lưu ý: "I" là giá trị tuyệt đối
a) \(=10\frac{1}{4}\cdot\frac{-5}{3}-8\frac{1}{4}\cdot\frac{-5}{3}-5=\left(10\frac{1}{4}-8\frac{1}{4}\right)\cdot\frac{-5}{3}-5\)
\(=\left(\frac{41}{4}-\frac{33}{4}\right)\cdot\frac{-5}{3}-5=2\cdot\frac{-5}{3}-5\)\(=\frac{-10}{3}-\frac{15}{3}=\frac{-25}{3}\)
b)\(=\frac{5}{7}+1+\frac{2}{7}+\frac{2^{10}\cdot\left(2^3\right)^3}{\left(2^2\right)^9}\)
\(=\frac{5}{7}+\frac{2}{7}+1+\frac{2^{10}\cdot2^9}{2^{27}}\)
\(=1+1+\frac{1}{2^8}=2+\frac{1}{256}=\frac{512}{256}+\frac{1}{256}=\frac{513}{256}\)
Thực hiện phép tính ( bằng cách hợp lí nếu có thể )
a) \(\frac{2}{5}+\frac{3}{5}:\left(-\frac{3}{5}\right)+\frac{1}{2}\)
b) \(10\frac{1}{4}\left(-\frac{3}{5}\right)-8\frac{1}{4}:\left(-\frac{3}{5}\right)\)
c) \(\frac{4^{30}\cdot3^{43}}{2^{57}\cdot27^{15}}\)
d) \(\left(1-\frac{2}{5}\right)^2+\left|-\frac{3}{5}\right|+\left(-\frac{7}{10}\right)-\frac{9}{25}\)
Thực hiện các phép tính bằng cách hợp lí nhất
a) \(\frac{5}{3}+\left\{\frac{-2}{7}\right\}-\left(-1,2\right)\)
b) \(\frac{-4}{9}+\left\{\frac{-5}{6}\right\}-\frac{17}{4}\)
Thực hiện phép tính
\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\left(ĐA:A=\frac{1}{6}-\frac{-10}{3}=\frac{7}{2}\right)\)
Gợi ý : Phân tích hết ra thành tích các thừa số nguyên tố rồi đặt cái chung ra ngoài
-> rút gọn
-> kết quả
P/S : bài này cx ko dài lắm nhưg lười ^^