tìm x a I x +\(\frac{4}{15}\)I - I -3,75 I= -I-2,15I b I x + \(\frac{1}{4}\)I- \(\frac{3}{4}\)= 5% c \(\frac{3}{2}+\frac{4}{5}\)I x -\(\frac{3}{4}\)I=\(\frac{7}{4}\)
Tìm x biết
a, \(\left|x+\frac{1}{5}\right|-4+-2 \)
b, \(\left|x-\frac{1}{3}\right|+\frac{4}{5}=\left|\left(-3,2\right)+\frac{2}{5}\right|\)
c, \(\frac{1}{3}.\left|2.x-3\right|=5\)
d, \(\frac{15}{28}-\left|x-\frac{3}{4}\right|=\frac{-5}{12}\)
a)\(\left|x+\frac{1}{5}\right|-4=-2\)
\(\Rightarrow\left|x+\frac{1}{5}\right|=2\)
\(\Rightarrow x+\frac{1}{5}=2\) hoặc \(-2\)
Xét \(x+\frac{1}{5}=2\Leftrightarrow x=\frac{9}{5}\)
Xét \(x+\frac{1}{5}=-2\Leftrightarrow x=-\frac{11}{5}\)
Tìm x biết :
a) \(\left[\left(6\frac{3}{5}-3\frac{3}{14}\right).2,5\right]:\left(21-1,25\right)=x:5\frac{5}{6}\)
b) \(\left(4-\frac{3}{4}\right):\left(2\frac{1}{3}-1\frac{1}{9}\right)=31x:\left(45\frac{10}{63}-44\frac{25}{84}\right)\)
c) \(\frac{x-1}{x+5}=\frac{6}{7}\)
d) \(\frac{x^2}{6}=\frac{24}{25}\)
e) \(\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
giúp mình nhé
e)
=> (x-2) . (x+7) = ( x-1 ) . ( x +4)
=> x2 +7x - 2x -14 = x2 - x + 4x - 4
x2 + 5x - 14 = x2 + 3x - 4
=> 5x - 14 = 3x - 4
=> 5x - 3x = 14-4
=> 2x = 10 => x = 10 : 2 => x = 5
c)
=>( x-1) . 7 = ( x + 5 ) . 6
=> 7x - 7 = 6x + 30
=> 7x - 6x= 30 + 7
=> x = 37
a,x=\(\frac{5}{2}\)
b,x=\(\frac{13}{176}\)
c,x=37
d, x=\(\frac{12}{5}\)
e, x=5
BÀI 1:Tính bằng cách hợp lý nhất: | BÀI 2:Tìm x biết:
a) 1\(\frac{4}{23}\)+\(\frac{5}{21}\)-\(\frac{4}{23}\)+0,5+\(\frac{16}{21}\) ; | a) |x+5|-6=9
b) \(23\frac{1}{4}\).\(\frac{7}{5}\)-13\(\frac{1}{4}\):\(\frac{5}{7}\) ; | b) \(\left(x-1\right)^2=25\)
c) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\) |
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BÀI 3:Tìm x biết:
a) \(\frac{x}{12}-\frac{5}{6}=\frac{1}{12}\) e) \(1\frac{1}{2}.x-4=0,5\)
b) \(\frac{2}{3}-1\frac{4}{15}x=\frac{-3}{5}\) f) 2x-1 =16
c) -23 +0.5x=1.5 g) (x-1)2 =25
d) \(\frac{\left(-3\right)^x}{81}=27\) h) |2x-1|=5
Tìm x biết :
1) \(\left(\frac{2}{5}-x\right):1\frac{1}{3}+\frac{1}{2}=-4\)
2) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
3) \(\frac{-3x}{4}.\left(\frac{1}{x}+\frac{2}{7}\right)=0\)
4) \(3-\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
5) \(3.\left|4x-1\right|-2=19\)
6) \(\left(2x+\frac{1}{3}\right)^2=\frac{9}{16}\)
7) \(\left|x+2\right|-6x=1\)
8) \(\left|x-3\right|+\left|x-2\right|=7\)
9) \(\left|2x+1\right|+\left|x+8\right|=4x\)
10) \(4^x+4^{x+3}=4160\)
giúp mình nhé
Bài 1: Tính nhanh
a, \(\frac{-3}{7}-\left(\frac{2}{3}-\frac{3}{7}\right)\)
b, \(\frac{2}{15}:\left(\frac{1}{3}.\frac{4}{5}-\frac{1}{3}.\frac{6}{5}\right)\)
Bài 2: Tìm x:
a, \(\frac{3}{4}+\frac{1}{4}.x=\frac{5}{8}\)
b, 25% . x+x= -1,25
Bài 1
a/
\(=\left(\frac{-3}{7}+\frac{3}{7}\right)-\frac{2}{3}\)
\(=0-\frac{2}{3}\)
\(=\frac{-2}{3}\)
Tìm x biết :
1) \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2) \(\left(x-2,5\right):1\frac{1}{2}=x:2\)
3) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
4) \(0,81:\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
giúp mình nhé
1)\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
\(\Leftrightarrow\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}-\frac{x+1}{5}-\frac{x+1}{6}=0\)
\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)=0\)
\(\Leftrightarrow\left(x+1\right)=0\).Do \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\ne0\)
\(\Leftrightarrow x=-1\)
\(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\\ \Leftrightarrow\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}-\frac{x+1}{5}-\frac{x+1}{6}=0\\ \Leftrightarrow\left(x+1\right)\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)=0\)
Gọi \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}-\frac{1}{5}-\frac{1}{6}\right)\)là A
Vì A ≠0
⇒\(x+1=0\Rightarrow x=-1\)
Vậy \(x=-1\)
\(\frac{x}{3}=\frac{y}{3}\) và x+y=10 A)
\(4\frac{3}{4}+\frac{5}{19}-\frac{3}{4}+1.5+\frac{14}{9}\) B)
\(\left(-3\right)^2\cdot\frac{1}{3}-\sqrt{49}+\left(-5\right)^3:\sqrt{25}\) C)
\(\frac{1}{3}-0.84-0.16+\frac{2}{3}+\frac{2}{11}\) D)
a: Vì x/3=y/3 nên x=y
mà x+y=10
nên x=y=10/2=5
b: \(=\left(4+\dfrac{3}{4}-\dfrac{3}{4}\right)+\left(\dfrac{5}{19}+\dfrac{14}{19}\right)+1.5=5.5+1=6.5\)
c: \(=9\cdot\dfrac{1}{3}-7+\left(-125\right):5=3-7-25=-29\)
a) |x + 2| - 6x = 1
b) |x - 3| + |x - 2| = 7
c) |2x + 1| + |x + 8| = 4x
d) 4x + 4x+3 = 4160
e) (x - 2,5) : \(1\frac{1}{2}\) = x : 2
g) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
h) 0,81 : \(\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
giúp mk nhé
a: \(\Leftrightarrow\left|x+2\right|=6x+1\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-\dfrac{1}{6}\\\left(6x+1-x-2\right)\left(6x+1+x+2\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{1}{6}\\\left(5x-1\right)\left(7x+3\right)=0\end{matrix}\right.\)
\(\Leftrightarrow x=\dfrac{1}{5}\)
b: Trường hợp 1: x<2
Pt sẽ là 3-x+2-x=7
=>5-2x=7
=>2x=-2
hay x=-1(nhận)
Trường hợp 2: 2<=x<3
Pt sẽ là 3-x+x-2=7
=>1=7(vô lý)
Trường hợp 3: x>=3
Pt sẽ là x-3+x-2=7
=>2x-5=7
=>x=6(nhận)
d: \(\Leftrightarrow4^x\cdot\left(1+4^3\right)=4160\)
\(\Leftrightarrow4^x=64\)
hay x=3
bài3
a,\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
b,\(2x.\left(x\frac{-1}{7}\right)=0\)
c,\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
bài 4:
a,|x-1,5|=2 b,|\(x+\frac{4}{15}\)|-|-3,75|=-|-2,15|
c,|\(x+\frac{3}{4}\)| - \(\frac{1}{2}\)=0