Ta có

(|x|-2011)^(n+2008)(n+2009)=-(-355)^2009=355 ^2009

 n+2008 và n+2009 là 2 số nguyên liên tiếp => (n+2009)(n+2008) là số chẵn => (|x|-2011)^(n+2008)(n+2009) là số chính phương

=> 355 ^2009  là số chính phương mà 355^2009=5^2009 x 71^2009  

                                                              5,7 là số nguyên tố 

=> 2009 là số lẻ (vô lý)

Không có x t/m

(Có gì mắc bạn nhắn mình giải đáp cho)

(|x|-2011)^{(n+2008)(n+2009)}=-(2³-3²)²⁰⁰⁹=-(-1)²⁰⁰⁹=1=1^{(n+2008)(n+2009)}

=>|x|-2011=1

|x|=1+2011

|x|=2012

=>x=2012 hoặc x=-2012

x=2012

\(\left(\left|x\right|-2011\right)^{\left(2+2008\right)}\cdot\left(2+2009\right)=-\left(2^3-3^2\right)^{2009}\)

\(\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(8-9\right)^{2009}\)

\(\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)^{2009}\)

\(\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)\)

\(\left(\left|x\right|-2011\right)^{2010}\cdot2011=1\)

\(\left(\left|x\right|-2011\right)^{2010}=\dfrac{1}{2011}\)

???

\(\dfrac{x-1}{2011}+\dfrac{x-2}{2010}-\dfrac{x-3}{2009}=\dfrac{x-4}{2008}\)

<=> \(\left(\dfrac{x-1}{2011}-1\right)+\left(\dfrac{x-2}{2010}-1\right)-\left(\dfrac{x-3}{2009}-1\right)=\left(\dfrac{x-4}{2008}-1\right)\)

<=> \(\dfrac{x-2012}{2011}+\dfrac{x-2012}{2010}-\dfrac{x-2012}{2009}-\dfrac{x-2012}{2008}=0\)

<=> \(\left(x-2012\right)\left(\dfrac{1}{2011}+\dfrac{1}{2010}-\dfrac{1}{2009}-\dfrac{1}{2008}\right)=0\)

<=> x - 2012 = 0

<=> x = 2012

trừ 1 vào mỗi tỉ số,ta đc:

\(\frac{x-1}{2011}-1+\frac{x-2}{2010}-1-\frac{x-3}{2009}-1=\frac{x-4}{2008}-1\)

\(\Rightarrow\frac{x-1-2011}{2011}+\frac{x-2-2010}{2010}-\frac{x-3-2009}{2009}=\frac{x-4-2008}{2008}\)

\(\Rightarrow\frac{x-2012}{2011}+\frac{x-2012}{2010}-\frac{x-2012}{2009}=\frac{x-2012}{2008}\)

\(\Rightarrow\frac{x-2012}{2011}+\frac{x-2012}{2010}-\frac{x-2012}{2009}-\frac{x-2012}{2008}=0\)

\(\Rightarrow\left(x-2012\right)\left(\frac{1}{2011}+\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\right)=0\)

\(mà\frac{1}{2011}<\frac{1}{2010}<\frac{1}{2009}<\frac{1}{2008}\Rightarrow\frac{1}{2011}+\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\ne0\)

=>x-2012=0

=>x=2012

vậy x=2012

sao cộng mà ko trừ đi

bn -3 đi mà hiệu chỉ có trừ 1 à

`Answer:`

\(\left(\frac{x+1}{2013}\right)+\left(\frac{x+2}{2012}\right)+\left(\frac{x+3}{2011}\right)=\left(\frac{x+4}{2010}\right)+\left(\frac{x+5}{2009}\right)+\left(\frac{x+6}{2008}\right)\)

\(\Leftrightarrow\frac{x+1}{2013}+1+\frac{x+2}{2012}+1+\frac{x+3}{2011}+1=\frac{x+4}{2010}+1+\frac{x+5}{2009}+1+\frac{x+6}{2008}+1\)

\(\Leftrightarrow\frac{x+2014}{2013}+\frac{x+2014}{2012}+\frac{x+2014}{2011}=\frac{x+2014}{2010}+\frac{x+2014}{2009}+\frac{x+2014}{2008}\)

\(\Leftrightarrow\frac{x+2014}{2013}+\frac{x+2014}{2012}+\frac{x+2014}{2011}-\frac{x+2014}{2010}-\frac{x+2014}{2009}-\frac{x+2014}{2008}=0\)

\(\Leftrightarrow\left(x+2014\right)\left(\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}-\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\right)=0\)

\(\Rightarrow x+2014=0\)

\(\Leftrightarrow x=-2014\)

tìm x hử

(2008 x 2009 x 2010 x 2011) x (1 + 1/2 : 3/2 - 4/3)

=(2008 x 2009 x 2010 x 2011) x (1 + 1/3 - 4/3)

=(2008 x 2009 x 2010 x 2011) x (4/3 - 4/3)

=(2008 x 2009 x 2010 x 2011) x 0

=0

đáp số:0

ủng hộ nha

kết ban đi

đáp số: 0

dễ như ăn cháo

thảo mai ăn hủ tiếu mì nha

\(\frac{x-1}{2011}+\frac{x-2}{2010}-\frac{x-3}{2009}=\frac{x-4}{2008}\)

\(\Rightarrow\left(\frac{x-1}{2011}+1\right)+\left(\frac{x-2}{2010}+1\right)-\left(\frac{x-3}{2009}+1\right)=\frac{x-4}{2008}+1\)

\(\Rightarrow\frac{x-1+2011}{2011}+\frac{x-2+2010}{2010}-\frac{x-3+2009}{2009}=\frac{x-4+2008}{2008}\)

\(\Rightarrow\frac{x-2012}{2011}+\frac{x-2012}{2010}-\frac{x-2012}{2009}=\frac{x-2012}{2008}\)

\(\Rightarrow\frac{x-2012}{2011}+\frac{x-2012}{2010}-\frac{x-2012}{2009}-\frac{x-2012}{2008}=0\)

\(\Rightarrow\left(x-2012\right)\left(\frac{1}{2011}+\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\right)=0\)

Mà \(\frac{1}{2011}+\frac{1}{2010}-\frac{1}{2009}-\frac{1}{2008}\ne0\)

=> x - 2012 = 0

=> x = 2012

Vậy x = 2012