ta có công thức như sau :

\(a^{-x}=?\)

lời giải công thức này như sau :

\(a^{-x}=\left(\frac{1}{a}\right)^x\)

vậy bài cũng gải tương tự 

\(32^{-x}.16^x=\left(\frac{1}{32}\right)^x.\left(16^x\right)\)

\(=\left(\frac{16}{32}\right)^x=\left(\frac{1}{2}\right)^x=2^{-x}\)

mà \(2048=2^{11}\)

 \(\Rightarrow-x=11\)

 \(\Leftrightarrow x=-11\)

vậy \(x=-11\)

\(\Rightarrow\)\(\left(\frac{1}{32}\right)^x\cdot16^x=2048\)

\(\Rightarrow\)\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^{-11}\)

\(\Rightarrow\)\(x=-11\)

\(\frac{2^{4-x}}{16^5}=32^6\)

\(\Rightarrow\frac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\)

\(\Rightarrow\frac{2^{4-x}}{2^{20}}=2^{30}\)

\(\Rightarrow2^{4-x}=2^{30}.2^{20}\)

\(\Rightarrow2^{4-x}=2^{50}\)

\(\Rightarrow4-x=50\)

\(\Rightarrow x=-46\)

64 . 4^x = 168

<=> 43. 4^x = 416

=> 3 + x = 16

<=> x = 13

Vậy x = 13

2^x.16² = 1024

<=> 2^x. 2⁸ = 210

=> x + 8 = 10

<=> x = 2

Vậy x = 2

b: Ta có: \(2^x\cdot16^2=1024\)

\(\Leftrightarrow2^x\cdot2^8=2^{10}\)

\(\Leftrightarrow x+8=10\)

hay x=2

  64.4^x=16³

  2⁶. (2²)^x = (2⁴)³

=> 2⁶. 2^2x = 2¹²

        2^2x   = 2 ¹² : 2⁶

       2^2x   = 2⁶

  =>  2x = 6

         x = 6 :2

         x=3

- Vậy x =3

x = -11 do ban

a: =>31-x=60

=>x=-29

b: =>(x-140):35=280-270=10

=>x-140=350

=>x=490

c: =>(1900-2x):35=48

=>1900-2x=1680

=>2x=220

=>x=110

d: =>\(2^{2x-1}=2^9\cdot2=2^{11}\)

=>2x-1=11

=>x=6

e: =>(x+2)^5=4^5

=>x+2=4

=>x=2

f: =>3x-4=0 hoặc x-1=0

=>x=4/3 hoặc x=1

g: =>(2x-1)^2=49

=>2x-1=7 hoặc 2x-1=-7

=>x=-3 hoặc x=4

h: =>x(x+1)/2=78

=>x(x+1)=156

=>x=12

\(2^{3x+4}=1024\)

Đổi 1024=\(2^{10}\)

\(=>2^{3x+4}\)=\(2^{10}\)

3x+4=\(2^{10}\)

3x=10-4

3x=6

x=6:3

x=2

tk m nhé

\(2^{3x+4}=1024\)

Đổi: \(1024=2^{10}\)

\(\Rightarrow3x+4=10\)

\(3x=10-4\)

\(3x=6\)

\(x=6:3\)

\(x=2\)

a)x=-2

b)x=-102

c)x=123

d)x=10

e)x=-48