=1140,281042

\(\frac{5}{27}+\frac{3}{4}+\frac{22}{27}+\frac{1}{4}\)

\(=\left(\frac{5}{27}+\frac{22}{27}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\)

\(=1+1\)

\(=2\)

\(\frac{89}{92}-\frac{30}{92}-\frac{59}{92}\)

\(=\frac{89-30-59}{92}\)

\(=\frac{59-59}{92}\)

\(=\frac{0}{92}\)

\(=0\)

bài 2 đề sai rồi

bạn xem lại nhé

1) \(\dfrac{1}{4}x-\dfrac{1}{3}=\dfrac{-5}{9}\)

\(\Rightarrow\dfrac{1}{4}x=-\dfrac{2}{9}\Rightarrow x=-\dfrac{8}{9}\)

2) \(2^{x-3}-3.2^x=-92\)

\(\Rightarrow2^x\left(2^{-3}-3\right)=-92\)

\(\Rightarrow2^x.\dfrac{-23}{9}=-92\)

\(\Rightarrow2^x=32\Rightarrow x=5\)

2:

1: =>36x+14x=69+81=150

=>50x=150

=>x=3

2: 3^x=81

=>3^x=3^4

=>x=4

3: 3(2x+1)^2=75

=>(2x+1)^2=25

=>2x+1=5 hoặc 2x+1=-5

=>x=-3 hoặc x=2

1:

1: \(\dfrac{13\cdot17^4+4\cdot17^4}{17^3}-\dfrac{14\cdot3^3-14\cdot3^2}{9}\)

\(=\dfrac{17^4\cdot\left(13+4\right)}{17^3}-\dfrac{14\cdot3^2\left(3-1\right)}{9}\)

\(=17\cdot17-14\cdot2\)

=289-28

=261

2:

\(2^3\cdot5^2-\left[131-\left(23-2^3\right)^2\right]\)

\(=8\cdot25-131+\left(-1\right)^2\)

=69+1

=70

1: \(\Leftrightarrow\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+4}{96}+1\right)=\left(\dfrac{x+6}{94}+1\right)+\left(\dfrac{x+8}{92}+1\right)\)

=>x+100=0

hay x=-100

2: \(\Leftrightarrow x\cdot\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{4}x+\dfrac{3}{4}=3-\dfrac{1}{3}x-\dfrac{2}{3}\)

=>3/4x+5/4=-1/3x+7/3

=>13/12x=13/12

hay x=1