bài 1:thực hiện phep tính
a)[(-7)+(-3)+11]+2
b)(7-5)3+77:75+20140
c)80-[130-(12-4)2]
Thực hiện phép tính một cách hợp lý: 13-12+11+10-9+8-7-6+5-4+3+2-1
thực hiện phép tính sau bằng cách hợp lý: 13-12+11+10-9+8-7-6+5-4+3+2-1
chia ra làm các nhóm (13-12+11)+(10-9+8)-(7-6+5) -(4+3+2-1)
hay ta thấy 3 nhóm đầu có tổng =số trừ trong các nhóm đó tức là 12+9-6+(4+3+2-1)
Hay= 23
thực hiện phép tính( tính nhanh nếu có thể)
a/ \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
b/ \(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}\)
c/ \(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)
d/ \(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)
\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)
\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=\frac{5}{7}.0=0\)
c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)
\(=\frac{27}{5}.10=27.2=54\)
\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)
\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)
cho mk hỏi, bn có thể lm thêm c d dc ko
Thực hiện phép tính
a, \(\dfrac{3}{x+3}-\dfrac{x-6}{x^2+3}\)
b, \(\dfrac{2x^2-x}{x-1}+\dfrac{x+1}{1-x}+\dfrac{2-x^2}{x-1}\)
\(\dfrac{2x^2-x}{x-1}+\dfrac{x+1}{1-x}+\dfrac{2-x^2}{x-1}.\left(x\ne1\right).\)
\(\dfrac{2x^2-x-x-1+2-x^2}{x-1}=\dfrac{x^2-2x+1}{x-1}=\dfrac{\left(x-1\right)^2}{x-1}=x-1.\)
Thực hiện phép tính
a) (x\(^2\)-3x+4)(-3x+1)
b)\(\dfrac{1}{x}\)+\(\dfrac{1}{x+5}\)+\(\dfrac{x-5}{x^2+5x}\)
Mọi người giúp mình nhanh nha mình cần gấp
b: \(=\dfrac{x+5+x+x-5}{x\left(x+5\right)}=\dfrac{3x}{x\left(x+5\right)}=\dfrac{3}{x+5}\)
\(a,=-3x^3+x^2+9x^2-3x-12x+4=-3x^3+10x^2-15x+4\\ b,=\dfrac{x+5+x+x-5}{x\left(x+5\right)}=\dfrac{3x}{x\left(x+5\right)}=\dfrac{3}{x+5}\)
Thực hiện phép tính:
a) 3 . ( 5 - 3 + 1 ) + ( 2 - 13 ) - ( 10 - 13 )
b) 28 . 76 - 13 . 28 + 11 x 28
c) 100 - [ 75 - ( 7 - 2 ) 2 ]
d) 50% x 11/3 . 10 . 7/35 x 0,75
f) 2/3 + 1/3 (- 4/9 + 5/6 ) : 7/12
g) 21 . 72 - 11 . 72 + 90 . 72 + 49 . 125 . 16
m) 25 - ( 930019 - 20070 ) - ( 102 - 930019 )
n) ( - 1/2) 3 . 11/3 - | -3/4 | : ( 1/3 ) 2 + | -2/5|
Các cậu giải nhanh giúp tớ với nhé! ^^
a,3 . ( 5 - 3 + 1 ) + ( 2 - 13 ) - ( 10 - 13 )=3.3+(-11)-(-3)=9+(-11)+3=1
b,28 . 76 - 13 . 28 + 11 x 28=28.(76-13+11)=28.74=2072
c) 100 - [ 75 - ( 7 - 2 ) 2 ] =100-(75-5^2)=100-(75-25)=100-50=50
Thực hiện phép tính
1, 3×(1/7+1/3—3/14):11/4
2, (21/8+1/2):5/16
\(\text{Thực hiện phép tính}\)
\(3\text{ × }\left(\frac{1}{7}+\frac{1}{3}-\frac{3}{14}\right) : \frac{11}{4}\)
\(=3\text{ x }\left(\frac{3}{21}+\frac{7}{21}-\frac{3}{14}\right)\text{ : }\frac{11}{4}\)
\(=3\text{ x }\left(\frac{10}{21}-\frac{3}{14}\right)\text{ : }\frac{11}{4}\)
\(=3\text{ x }\left(\frac{140}{294}-\frac{63}{294}\right)\text{ : }\frac{11}{4}\)
\(=3\text{ x }\frac{77}{294}\text{ : }\frac{11}{4}\)
\(=\frac{231}{294}:\frac{11}{4}\)
\(=\frac{231}{294}\text{ x }\frac{4}{11}\)
\(=\frac{924}{3234}=\text{Phân số này có thể rút gọn đó bạn ! Bạn tự rút gọn nha !}\)
\(\left(\frac{21}{8}+\frac{1}{2}\right)\text{ : }\frac{5}{16}\)
\(=\left(\frac{21}{8}+\frac{4}{8}\right)\text{ : }\frac{5}{16}\)
\(=\frac{25}{8}\text{ : }\frac{5}{16}\)
\(=\frac{25}{8}\text{ x }\frac{16}{5}\)
\(=\frac{400}{40}=10\)
>,<,=
3/5...1/2 5/6...7/8 8/9...7/6
9/4..7/3 8/12...2/3 77/99...7/9
50/75 ... 10/15
a: 3/5>1/2
b: 5/6<7/8
c: 8/9<7/6
d: 9/4<7/3
e: 8/12=2/3
f: 77/99=7/9
\(\dfrac{3}{5}>\dfrac{1}{2}\)
\(\dfrac{5}{6}< \dfrac{7}{8}\)
\(\dfrac{8}{9}< \dfrac{7}{6}\)
\(\dfrac{9}{4}< \dfrac{7}{3}\)
\(\dfrac{8}{12}=\dfrac{2}{3}\)
\(\dfrac{77}{99}=\dfrac{7}{9}\)
\(\dfrac{3}{5}>\dfrac{1}{2}\)
\(\dfrac{5}{6}< \dfrac{7}{8}\)
\(\dfrac{8}{9}< \dfrac{7}{6}\)
\(\dfrac{9}{4}< \dfrac{7}{3}\)
\(\dfrac{8}{12}=\dfrac{2}{3}\)
\(\dfrac{77}{99}=\dfrac{7}{9}\)
rút gọn biểu thức chứa căn số học
a)-√20+3√45-6√80-1/5√125
b)2√3-√75+2√12-√147
c)3/2√12+7/5√75-9/10√300+11/6√108
\(a,=-2\sqrt{5}+9\sqrt{5}-24\sqrt{5}-\sqrt{5}=-18\sqrt{5}\)
\(b,=2\sqrt{3}-5\sqrt{3}+4\sqrt{3}-7\sqrt{3}=-6\sqrt{3}\)
\(c,=3\sqrt{3}+7\sqrt{3}-9\sqrt{3}+11\sqrt{3}=12\sqrt{3}\)
a) Ta có: \(-\sqrt{20}+3\sqrt{45}-6\sqrt{80}-\dfrac{1}{5}\sqrt{125}\)
\(=-2\sqrt{5}+9\sqrt{5}-24\sqrt{5}-\dfrac{1}{5}\cdot5\sqrt{5}\)
\(=-17\sqrt{5}-\sqrt{5}=-18\sqrt{5}\)
b) Ta có: \(2\sqrt{3}-\sqrt{75}+2\sqrt{12}-\sqrt{147}\)
\(=2\sqrt{3}-5\sqrt{3}+4\sqrt{3}-7\sqrt{3}\)
\(=-6\sqrt{3}\)