olm chưa death ak ?

a; - \(\dfrac{1}{3}\).(15\(x-9\)) + \(\dfrac{2}{7}\).(- \(x-34\)) = 1 - \(\dfrac{3}{4}\).(-16\(x+4\))

    - 5\(x\) + 3 - \(\dfrac{2}{7}\)\(x\) - \(\dfrac{68}{7}\) = 1 + 12\(x\) - 3 

    12\(x\) + 5\(x\)  + \(\dfrac{2}{7}x\) =  3 - \(\dfrac{68}{7}\)  - 1 + 3 

    17\(x\) + \(\dfrac{2}{7}x\) =  (3 - 1 + 3) - \(\dfrac{68}{7}\)

    \(\dfrac{121}{7}\)\(x\)    =  5 - \(\dfrac{68}{7}\)

     \(\dfrac{121}{7}\) \(x\)  = -  \(\dfrac{33}{7}\)

           \(x\)  =    - \(\dfrac{33}{7}\): \(\dfrac{121}{7}\)

            \(x\) =  - \(\dfrac{3}{11}\)

Vậy  \(x\) = - \(\dfrac{3}{11}\) 

a) x = 72

b) x = 15

c) x = 34

d) x = 6

e)

f) x =  2 , x =3

g) x=1,x=-3

h)x=3,x=-2

mik chỉ bt giải thế thôi

CHÚC BẠN HỌC TỐT

Bài làm

a) ( x - 15 ) : 3 = 19

x - 15 = 19 . 3

x - 15 = 57

x        = 57 + 15

x        = 72

Vậy x = 72.

b) ( 5x - 45 ) . 15 = 450

5x - 45 = 450 : 15

5x - 45 = 30

5x        = 75

  x        = 15

Vậy x = 15.

c) 187 - 3( x  + 4 ) = 34

              3( x + 4 ) = 187 - 34

              3( x + 4 ) = 153

                  x + 4   = 153 : 3

                  x + 4   = 51

                  x         = 47

Vậy x = 47.

d) 9x - 45 = 3⁷ : 3⁵ 

    9x - 45 = 3²

    9x - 45 = 9

 9( x - 5 ) = 9

      x - 5   = 9 : 9

      x - 5   = 1

      x        = 6

Vậy x = 6.

e ) ( 12x - 4³ ) . 8³ = 4 . 8⁴ 

     ( 12x - 64 )        = 4 . 8⁴ : 8³

        12x - 64          = 4 . 8

        12x - 64          = 32

        12x                  = 96

            x                  = 8

Vậy x = 8.

f ) Đề bài không rõ ràng.

g ) ( x + 1 )² = 4

=> ( x + 1 )² = 2² 

=> x + 1 = 2

=> x = 1

Vậy x = 1.

h ) ( 2x - 1 )² = 25

=> ( 2x - 1 )² = 5² 

=> 2x - 1 = 5

=> 2x = 6

=> x = 3

Vậy x = 3

k ) ( 2x - 1 )⁵ = 243

=> ( 2x - 1 )⁵ = 3⁵

=> 2x - 1 = 3

=> 2x = 4

=> x = 2

Vậy x = 2

# Học tốt #

a) ( x - 15 ) : 3 = 19

    ( x - 15 )      = 19 . 3

      x - 15        = 57

             x        = 57 + 15

             x        = 72

b) ( 5x - 45 ) x 15 = 450

      5x - 45           = 450 : 15

      5x - 45           = 30

      5x                  = 30 + 45

      5x                  = 75

c) 187 - 3( x + 4 ) = 34

             3( x + 4 ) = 187 - 34

             3( x + 4 ) = 153

                 x + 4   = 153 : 3

                 x + 4   = 51

                 x         = 51 - 4

                 x         = 47

d) 9x - 45 = 3⁷ : 3⁵

    9x - 45 = 3²

    9x - 45 = 9

           9x = 9 + 45

           9x = 54

             x = 54 : 9

             x = 6

e) ( 12x - 4³ ) x 8³ = 4 x 8⁴

    ( 12x - 64 ) x 512 = 4 x 4096

    ( 12x - 64 ) x 512 = 16384

      12x - 64             = 16384 : 512

      12x - 64             = 32

      12x                    = 32 + 64

      12x                    = 96

          x                    = 96 : 12

          x                    = 8

f) x² = 4

   x² = 2²

=> x = 2

   x³ = 27

   x³ = 3³

=> x = 3

g) ( x + 1 )² = 4

    ( x + 1 )² = 2²

=> x + 1 = 2

     x        = 2 - 1

     x        = 1

h) ( 2x - 1 )² = 25

    ( 2x - 1 )² = 5²

=> 2x - 1 = 5

     2x       = 5 + 1

     2x       = 6

       x       = 6 : 2

       x       = 3

k) ( 2x - 1 )⁵ = 243

    ( 2x - 1 )⁵ = 3⁵

=> 2x - 1 = 3

     2x       = 3 + 1

     2x       = 4

       x       = 4 : 2

       x       = 2

Chúc bn hok tốt

a: \(\Leftrightarrow x\cdot\dfrac{1}{4}+\dfrac{3}{4}=3-\dfrac{1}{2}x-\dfrac{1}{2}-\dfrac{1}{3}x-\dfrac{2}{3}\)

=>13/12x=13/12

hay x=1

b: \(\Leftrightarrow\dfrac{3x-11}{11}-\dfrac{x}{3}=\dfrac{3x-5}{7}-\dfrac{5x-3}{9}\)

\(\Leftrightarrow\dfrac{3}{11}x-1-\dfrac{1}{3}x=\dfrac{3}{7}x-\dfrac{5}{7}-\dfrac{5}{9}x+\dfrac{1}{3}\)

\(\Leftrightarrow x\cdot\dfrac{46}{693}=\dfrac{13}{21}\)

hay x=429/46

a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)

    - 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50

       2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51

            7\(x\)            = 67

               \(x\)           =  67 : 7

                \(x\)         =  \(\dfrac{67}{7}\)

Vậy \(x\) = \(\dfrac{67}{7}\) 

b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)

    17\(x\) - 48\(x\)  - 111 =  2\(x\) - 4\(x\) + 43

    - 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43

        - \(x\) x (31 + 2 - 4) = 154

        - \(x\) x (33 - 4) =  154

         - \(x\) x 29 = 154

         - \(x\)         = 154 : (-29)

           \(x\)        = - \(\dfrac{154}{29}\)

          Vậy \(x=-\dfrac{154}{29}\) 

c; {-3\(x\) + 2.[45 - \(x\) - 3(3\(x\) + 7) - 2\(x\)] + 4\(x\) } = 55

    {-3\(x\) + 2.[45 - \(x\) - 9\(x\) - 21 - 2\(x\)] + 4\(x\)} = 55

    {- 3\(x\) + 2.[(45 - 21) - (\(x+9x\)+2\(x\))] + 4\(x\) } = 55

     { (- 3\(x\) + 4\(x\)) + 2.[24 - 12\(x\)] } = 55

                   \(x\) + 48 - 24\(x\) = 55

                   \(x-24x\)         = 55 - 48

                     - 23\(x\)           = 7

                            \(x\)           = 7 : - 23

                             \(x=-\dfrac{7}{23}\)

Vậy \(x=-\dfrac{7}{23}\) 

1: =>3^x=81

=>x=4

2: =>2^x=8

=>x=3

3: =>x^3=2^3

=>x=2

4: =>x^20-x=0

=>x(x^19-1)=0

=>x=0 hoặc x=1

5: =>2^x=32

=>x=5

6: =>(2x+1)^3=9^3

=>2x+1=9

=>2x=8

=>x=4

7: =>x^3=115

=>\(x=\sqrt[3]{115}\)

8: =>(2x-15)^5-(2x-15)^3=0

=>(2x-15)^3*[(2x-15)^2-1]=0

=>2x-15=0 hoặc (2x-15)^2-1=0

=>2x-15=0 hoặc 2x-15=1 hoặc 2x-15=-1

=>x=15/2 hoặc x=8 hoặc x=7

1. Tìm số tự nhiên x biết:

1) \(3^x.3=243\)

\(3^x=243:3\)

\(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

_____

2) \(7.2^x=56\)

\(2^x=56:7\)

\(2^x=8\)

\(2^x=2^3\)

\(\Rightarrow x=3\)

_____

3) \(x^3=8\)

\(x^3=2^3\)

\(\Rightarrow x=3\)

_____

4) \(x^{20}=x\)

\(x^{20}-x=0\)

\(x\left(x^{19}-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x=1\)

5) \(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

_____

6) \(\left(2x+1\right)^3=9.81\)

\(\left(2x+1\right)^3=729=9^3\)

\(\rightarrow2x+1=9\)

\(2x=9-1\)

\(2x=8\)

\(x=8:2\)

\(\Rightarrow x=4\)

_____

7) \(x^6:x^3=125\)

\(x^3=125\)

\(x^3=5^3\)

\(\Rightarrow x=5\)

_____

8) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=7\\x=8\end{matrix}\right.\)

_____

9) \(3^{x+2}-5.3^x=36\)

\(3^x.\left(3^2-5\right)=36\)

\(3^x.\left(9-5\right)=36\)

\(3^x.4=36\)

\(3^x=36:4\)

\(3^x=9\)

\(3^x=3^2\)

\(\Rightarrow x=2\)

_____

10) \(7.4^{x-1}+4^{x+1}=23\)

\(\rightarrow7.4^{x-1}+4^{x-1}.4^2=23\)

\(4^{x-1}.\left(7+4^2\right)=23\)

\(4^{x-1}.\left(7+16\right)=23\)

\(4^{x-1}.23=23\)

\(4^{x-1}=23:23\)

\(4^{x-1}=1\)

\(4^{x-1}=4^1\)

\(\rightarrow x-1=0\)

\(x=0+1\)

\(\Rightarrow x=1\)

Chúc bạn học tốt

a: 3^x=243

=>3^x=3^5

=>x=5

b: 4^x=4096

=>4^x=4^5

=>x=5

c: 5^3-x=25

=>3-x=2

=>x=1

d: =>2x-3=3

=>2x=6

=>x=3

j: =>2^x*8+2^x*2=80

=>2^x=8

=>x=3

a: \(\Leftrightarrow4x^2+4x+1-4\left(x^2+4x+4\right)-9=0\)

\(\Leftrightarrow4x^2+4x-8-4x^2-16x-16=0\)

=>-12x-24=0

=>-12x=24

hay x=-2

b: \(\Leftrightarrow x^2+6x+9-x^2-4x+32=1\)

=>2x=1-41=-40

hay x=-20

c: \(\Leftrightarrow3x^2+12x+12+4x^2-4x+1-7\left(x^2-9\right)=36\)

\(\Leftrightarrow7x^2+8x+13-7x^2+63=36\)

=>8x=-40

hay x=-5