hay- tích đi

\(A=\frac{\left(4^2\right)^{17}.64^{36}}{8^{35}.32^{34}}\)

\(A=\frac{\left(2^4\right)^{17}.\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)

\(A=\frac{2^{68}.2^{216}}{2^{105}.2^{170}}=\frac{2^{284}}{2^{275}}=2^9=512\)

a) Vì \(-45< -16\) nên \(\left(-\dfrac{45}{17}\right)^{15}< \left(\dfrac{-16}{17}\right)^{15}\)

b) Vì \(21< 23\) nên \(\left(-\dfrac{8}{9}\right)^{21}< \left(-\dfrac{8}{9}\right)^{23}\)

c) \(27^{40}=3^{3^{40}}=3^{120}\)

\(64^{60}=8^{2^{60}}=8^{120}\)

Vì \(3< 8\) nên \(3^{120}< 8^{120}\) hay \(27^{40}< 64^{60}\)

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so sánh

1.16¹³ =(2⁴)¹³=2⁵²

8⁴³=(2³)⁴³=2¹²⁹

suy ra 2¹²⁹>2⁵²

8⁴³  > 16¹³ 

2.4³⁴=(2²)³⁴=2⁶⁸

32¹⁵=(2⁵)¹⁵=2⁷⁵

2⁷⁵ > 2⁶⁸

32¹⁵ > .4³⁴

3.9²³ =(3²)²³=3⁴⁶

81¹¹=(3⁴)¹¹=3⁴⁴

3⁴⁶ > 3⁴⁴

.9²³ >81¹¹

4.512¹¹=(2⁹)¹¹=2⁹⁹

64⁴⁵=(2⁶)⁴⁵=2²⁷⁰

2²⁷⁰ > 2⁹⁹

64⁴⁵ > 512¹¹

          Bài làm :

1) So sánh 16¹³ và 8⁴³

Ta có :

Vì 2⁵² < 2¹²⁹ =>16¹³ < 8⁴³

2) So sánh 4³⁴ và 32¹⁵

Ta có :

Vì 2⁶⁸ < 2⁷⁵ => 4³⁴ < 32¹⁵

3) So sánh 9²³ và 81¹¹

Ta có :

Vì 3⁴⁶ > 3⁴⁴ => 9²³ > 81¹¹

4) So sánh 512¹¹ và 64⁴⁵

Ta có :

Vì 2⁹⁹ < 2²⁷⁰ =>512¹¹ < 64⁴⁵

\(8^3.64^2=8^3.8^4=8^7>8^5\)

Bạn viết rõ ràng các phân số ra nhé.

A = \(\dfrac{11}{2^3.3^4.5^2}\) = \(\dfrac{11.5}{2^3.3^4.5^3}\) =  \(\dfrac{55}{2^3.3^4.5^3}\)

B = \(\dfrac{29}{2^2.3^4.5^3}\) = \(\dfrac{29.2}{2^3.3^4.5^3}\) = \(\dfrac{58}{2^3.3^4.5^3}\) 

A < B