tính nhanh
A=2/1.3+2/3.5+2/5.7+...+2/49.51
B=2/5+2/7-1/6-1/8+11/35-34/48+11/12
Những câu hỏi liên quan
bai 1 tinh nhanh neu co
a) 5/12-21/10.5/14
b) (41/15+17/100).80/129
c) 48/25.27/35+2và 4/9.14/33
d) 1 và 19/22 /(47/77-16/55)
e)5 và 2/7 .8/11+5 và 2/7.5/11-5 và 2/7.2/11
f)(3va10/99+4va11/99-5va8/99).(1/2-1/3-1/6)
bai 2 tinh tong
1/5.6+1/6.7+1/7.8+.............+1/99.100
2/1.3+2/3.5+2/5.7+.............+2/2013.2015
lm xong chắc zô quan tài nằm vì say sóng qá
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Tính
A=13/21.2/11+13/21.9/11+8/21.
B=(1-1/5).(1-2/5).(1-3/5)...(1-9/5)
C= (1-1/2).(1-1/3).(1-1/4)...(1-1/50)
D= 2²/1.3 . 3²/2.4 . 4²/3.5 . 5²/4.6 . 6²/5.7
A = 13/21.2/11 + 13/21.9/11 + 8/21
= (13/21) + (13/21) + (8/21)
= (13 + 13 + 8)/21
= 34/21
B = (1 - 1/5)(1 - 2/5)(1 - 3/5)...(1 - 9/5)
= (4/5)(3/5)(2/5)(1/5)(0/5)(-1/5)(-2/5)(-3/5)(-4/5)
= 0
C = (1 - 1/2)(1 - 1/3)(1 - 1/4)...(1 - 1/50)
= (1/2)(2/3)(3/4)(4/5)...(49/50)
= 1/50
D = (2^2/1.3) * (3^2/2.4) * (4^2/3.5) * (5^2/4.6) * (6^2/5.7)
= (4/3) * (9/8) * (16/15) * (25/23) * (36/35)
= 0.979
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tínhA frac{11}{1.3}+ frac{47}{3.5}+ frac{107}{5.7}+ frac{191}{7.9}+...+ frac{971}{17.19}B frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}- frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3-5^9.7^3.2^3}C 1.3+3.5+5.7+...+ (2n-1)(2n+1)Giúp mình vs nhanh nhanh nha các bạn
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tính
A =\(\frac{11}{1.3}\)+ \(\frac{47}{3.5}\)+ \(\frac{107}{5.7}\)+ \(\frac{191}{7.9}\)+...+ \(\frac{971}{17.19}\)
B = \(\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\)- \(\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3-5^9.7^3.2^3}\)
C = 1.3+3.5+5.7+...+ (2n-1)(2n+1)
Giúp mình vs nhanh nhanh nha các bạn
Tính tổng
a. 1/1.2 + 1/2.3 + 1/3.4 + ...+ 1/2015.2016
b. 2/1.3 + 2/3.5 + 2/5.7 + ...+ 2/99.101
c. 5/1.3 + 5/3.5 + 5/5.7 + ...+ 5/99.101
d. 1/2 + 1/6 + 1/12 + 1/20 + ...+ 1/9900
bn nào trả lời nhanh mik tích, cảm ơn ạ
còn cần không bạn, mk làm cho
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\(A=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{2025\cdot2016}\\ =\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2025}-\dfrac{1}{2026}\\ =\dfrac{1}{1}-\dfrac{1}{2026}=\dfrac{2025}{2026}\\ B=\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+...+\dfrac{2}{99\cdot101}\\ =\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{99}-\dfrac{1}{101}\\ =\dfrac{1}{1}-\dfrac{1}{101}=\dfrac{100}{101}\\ C=\dfrac{5}{1\cdot3}+\dfrac{5}{3\cdot5}+\dfrac{5}{5\cdot7}+...+\dfrac{5}{99\cdot101}\\ =\dfrac{5}{2}\cdot\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\\ =\dfrac{5}{2}\cdot\left(\dfrac{1}{1}-\dfrac{1}{101}\right)=\dfrac{5}{2}\cdot\dfrac{100}{101}=\dfrac{250}{101}\)
\(D=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{9900}\\ =\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}\\ =\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\\ =\dfrac{1}{1}-\dfrac{1}{100}=\dfrac{99}{100}\)
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Bài 5: Tính nhanh tổng sau(nếu có):Mdfrac{3}{2}-dfrac{5}{6}+dfrac{7}{12}-dfrac{9}{20}+dfrac{11}{30}-dfrac{13}{42}+dfrac{15}{56}-dfrac{17}{72} ; Adfrac{5}{1.3}+dfrac{5}{3.5}+dfrac{5}{5.7}+.....+dfrac{5}{2019.2021}
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Bài 5: Tính nhanh tổng sau(nếu có):
M=\(\dfrac{3}{2}\)-\(\dfrac{5}{6}\)+\(\dfrac{7}{12}\)-\(\dfrac{9}{20}\)+\(\dfrac{11}{30}\)-\(\dfrac{13}{42}\)+\(\dfrac{15}{56}\)-\(\dfrac{17}{72}\) ; A=\(\dfrac{5}{1.3}\)+\(\dfrac{5}{3.5}\)+\(\dfrac{5}{5.7}\)+.....+\(\dfrac{5}{2019.2021}\)
= \(\dfrac{5}{2}(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{2019}-\dfrac{1}{2021})\)
= \(\dfrac{5}{2}\left(1-\dfrac{1}{101}\right)\)
= \(\dfrac{5}{2}.\dfrac{100}{101}\)
= \(\dfrac{250}{101}\)
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1/1.3+1/3.5+1/5.7+......+1/x.(x+2)=5/11
Có:
\(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{x.\left(x+2\right)}=\dfrac{5}{11}\)
\(\Rightarrow\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)
\(\Rightarrow\dfrac{1}{2}.\left(1-0-0-0...-0-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)
\(\Rightarrow\dfrac{1}{2}.\left(1-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)
\(\Rightarrow1-\dfrac{1}{x+2}=\dfrac{5}{11}:\dfrac{1}{2}=\dfrac{10}{11}\)
\(\Rightarrow\dfrac{1}{x+2}=1-\dfrac{10}{11}\)
\(\Rightarrow\dfrac{1}{x+2}=\dfrac{1}{11}\)
\(\Rightarrow x+2=11\)
\(\Rightarrow x=11-2=9\)
Vậy x = 9.
Chúc bạn học tốt!
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1/1.3 + 1/3.5 + 1/5.7 + ... +1/x.(x+2)
= 1/2.(1/1 - 1/3) + 1/2.(1/3 - 1/5) + 1/2.(1/5 - 1/7) + ... + 1/2.(1/x -1/x+2)
= 1/2.(1/1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/x - 1/x+2 )
= 1/2.(1/1 - 0 - 1/x+2 )
= 1/2 . ( 1/1 - 1/x+2 )
= 1/2 . ( x+2/x+2 - 1/x+2 )
= 1/2 . x+1/x+2
Mà 1/1.3 + 1/3.5 + 1/5.7 + ... +1/x.(x+2) = 5/11
=> 1/2 . x+1/x+2 = 5/11
=> x+1/x+2 = 5/11 : 1/2
=> x+1/x+2 = 10/11
=> x+1/x+2-1 = 10/11-1
=> x+1/x+1 = 10/10
=> x + 1 = 10
=> x = 10 - 1
=> x = 9
Vậy x = 9
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\(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{x.\left(x+2\right)}=\dfrac{5}{11}\)
\(\dfrac{1.2}{2.1.3}+\dfrac{1.2}{2.3.5}+\dfrac{1.2}{2.5.7}+...+\dfrac{1.2}{2x\left(x+2\right)}\dfrac{5}{11}\)\(\dfrac{1}{2}\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{x\left(x+2\right)}\right)=\dfrac{5}{11}\)\(\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{5}{11}\)\(\dfrac{1}{2}\left(1+0+0+...+0+\dfrac{1}{x-2}\right)=\dfrac{5}{11}\)
\(\dfrac{1}{2}\left(1-\dfrac{1}{x-2}\right)=\dfrac{5}{11}\)
\(1-\dfrac{1}{x-2}=\dfrac{5}{11}:\dfrac{1}{2}\)
\(1-\dfrac{1}{x-2}=\dfrac{10}{11}\)
\(\dfrac{1}{x-2}=1-\dfrac{10}{11}\)
\(\dfrac{1}{x-2}=\dfrac{1}{11}\)
\(\Rightarrow x-2=11\)
\(x=11+2\)
\(x=13\)
Vậy x=13
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Tìm x: [12/11-(1/2+1/44].(x-0,2)=1/1.3+1/3.5+1/5.7+1/7.9+1/9.11
Mik giải phía dưới rồi đó. Câu lúc nãy bạn đăng ý
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Tính tổng:
a, B=11^2+13^2+15^2+...+2005^2
b,C=20^2+22^2+24^2+...+48^2+50^2
c, D=1^2+2^2-3^2+4^2-5^2+6^2-...-15^2+20^2
d, E=2.4+4.6+6.8+...+98.100
e, G=1.3+3.5+5.7+...+(2n-1).(2n+1)
Help me, chiều mình đi học
Tìm x: [12/11-(1/2+1/44].(x-0,2)=1/1.3+1/3.5+1/5.7+1/7.9+1/9.11
\(\left[\frac{12}{11}-\left(\frac{1}{2}+\frac{1}{44}\right)\right].\left(x-0,2\right)=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\)
\(\frac{25}{44}.\left(x-0,2\right)=\frac{1}{2}.\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{9.11}\right)\)
\(x-0,2=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{11}\right):\frac{25}{44}\)
\(x-\frac{1}{5}=\frac{22}{25}.\left(1-\frac{1}{11}\right)=\frac{22}{25}.\frac{10}{11}=\frac{4}{5}\)
\(x=\frac{4}{5}+\frac{1}{5}\)
\(x=1\)
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