2:7=x:14
7 x 2 = ..... 7 x 4 = ..... 7 x 6 = ..... 7 x 3 = .....
2 x 7 = ..... 4 x 7 = ..... 6 x 7 = ..... 3 x 7 = .....
14 : 7 = ..... 28 : 7 = ..... 42 : 7 = ..... 21 : 7 = .....
14 : 2 = ..... 28 : 4 = ..... 42 : 6 = ..... 21 : 3 = .....
7 x 2 = 14 7 x 4 = 28 7 x 6 = 42 7 x 3 = 21
2 x 7 = 14 4 x 7 = 28 6 x 7 = 42 3 x 7 = 21
14 : 7 = 2 28 : 7 = 4 42 : 7 = 6 21 : 7 = 3
14 : 2 = 7 28 : 4 = 7 42 : 6 = 7 21 : 3 = 7
Tính nhẩm:
7 x 5 =
7 x 6 =
7 x 2 =
7 x 4 =
35 : 7 =
42 : 7 =
14 : 7 =
28: 7 =
35 : 5 =
42 : 6 =
14 : 2 =
28 : 4 =
Học sinh nhẩm và ghi kết quả như sau:
7 x 5 = 35
7 x 6 = 42
7 x 2 = 14
7 x 4 = 28
35 : 7 =5
42 : 7 = 6
14 : 7 = 2
28: 7 =4
35 : 5 = 7
42 : 6 = 7
14 : 2 = 7
28 : 4 = 7
4/ 5 x 15/11 x 2/9
4/7 x 2/5 + 4/7 x 3/5
(5/7 + 7/8) x 2
2/14 + 3/7 - 3/14 x 2
4/5 x 15/11 x 2/9 = 8/33
4/7 x 2/5 + 4/7 x 3/5 = 4/7
( 5/7 + 7/8 ) x 2 = 89/28
2/14 + 3/7 - 3/14 x 2 = 1/7
tk mình nhé, mk nhanh nhất
4/5 x 15/11 x2/9
= 4x15x2/5x11x9
= 4x5x3x2/5x11x3x3
= 8/33
4/7x2/6+4/7x3/5
=4/7x(2/6+3/5)
=4/7x 14/15
=8/15
\(\frac{1}{2}\cdot\frac{18}{14}+\frac{1}{2}\cdot\frac{3}{14}-\frac{1}{2}\cdot\frac{7}{14}\)
\(=\frac{1}{2}\left(\frac{18}{14}+\frac{3}{14}-\frac{7}{14}\right)\)
\(=\frac{1}{2}\cdot1=\frac{1}{2}\)
tính nhanh 5/14 x 2/9 + 5/14 + 5/14 x 7/9, 6/8 : 7/6 - 6/8 : 1/6
a: \(=\dfrac{5}{14}\left(\dfrac{2}{9}+\dfrac{7}{9}+1\right)=\dfrac{5}{14}\cdot2=\dfrac{5}{7}\)
b: \(=\dfrac{6}{8}\left(\dfrac{6}{7}-6\right)=\dfrac{6}{8}\cdot\dfrac{-36}{7}=\dfrac{-216}{56}=\dfrac{-27}{7}\)
| 7 - 3/4 . x | - 3/2 = 1/1/2
5 - | x - 3 | = 5
| 7/2 - 42 | + 14 = 14
2/3 - | x + 2 | = 2
5/6 . | 3 - x | + 4 = 2
Giải giúp mình với
|7 - \(\dfrac{3}{4}\)\(x\)| - \(\dfrac{3}{2}\) = \(\dfrac{1}{\dfrac{1}{2}}\)
|7 - \(\dfrac{3}{4}x\)| - \(\dfrac{3}{2}\) = 2
|7 - \(\dfrac{3}{4}\)\(x\)| = 2 + \(\dfrac{3}{2}\)
|7 - \(\dfrac{3}{4}x\)| = \(\dfrac{7}{2}\)
\(\left[{}\begin{matrix}7-\dfrac{3}{4}x=\dfrac{7}{2}\\7-\dfrac{3}{4}x=-\dfrac{7}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}\dfrac{3}{4}x=7-\dfrac{7}{2}\\\dfrac{3}{4}=7+\dfrac{7}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}\dfrac{3}{4}x=\dfrac{7}{2}\\\dfrac{3}{4}x=\dfrac{21}{2}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{14}{3}\\x=14\end{matrix}\right.\)
5 - |\(x-3\)| = 5
|\(x-3\)| = 5 - 5
|\(x-3\)| = 0
\(x-3\) = 0
\(x\) = 3
|\(\dfrac{7}{2}\) - 42| + 14 = 14 ( vô lý xem lại đề bài nhé em)
\(\dfrac{2}{3}\) - |\(x+2\)| = 2
|\(x+2\)| = \(\dfrac{2}{3}\) - 2
|\(x+2\)| = - \(\dfrac{4}{3}\)
|\(x+2\)| ≥ 0 ∀ \(x\)
Vậy \(x\in\) \(\varnothing\)
2\(^7\) + ( x - 3\(^7\) ) = 5\(^7\) - 4\(^7\)
3 \(^x\) - (x + 2 \(^x\)) = 7
7 \(^2\) - (15 + x) = 5.2 \(^2\)
7 \(^3\) - 7(13 - x) = 14
a: \(2^7+\left(x-3^7\right)=5^7-4^7\)
=>\(128+x-2187=78125-16384\)
=>\(x-2059=61741\)
=>\(x=61741+2059=63800\)
c: \(7^2-\left(x+15\right)=5\cdot2^2\)
=>49-(x+15)=5*4=20
=>x+15=29
=>x=14
d: 7^3-7(13-x)=14
=>343-7(13-x)=14
=>7(13-x)=343-14=329
=>13-x=47
=>x=13-47=-34
7 x 1 x 7 x 7 x 2 + 14 + 7 x 3 + 21 =
Tìm x: Cần gấp ạ
1, -15 + x= - 14 - (-57) 2,(-14) + x - 7 = -10 3, -x - 14 + 32 = -26 4, x-(-19) - (-11) = 0
1, -15 + \(x\) = -14 - (-57)
-15 + \(x\) = -14 + 57
\(x\) = -14 + 57 + 15
\(x\) = 43 + 15
\(x\) = 58
2, (-14) + \(x\) - 7 = -10
-14 + \(x\) - 7 = -10
- 21 + \(x\) = - 10
\(x\) = -10 + 21
\(x\) = 11
3, - \(x\) - 14 + 32 = -26
- \(x\) + 18 = - 26
\(x\) = 18 + 26
\(x\) = 44
tinh nhanh
12/7 x 4/13 +12/14 x 14/26 -6/7 x 2/13