\(\frac{1+5^2+5^4+....+5^{30}}{1+5^4+5^8+....+5^{28}}\)
Tính : \(B=\frac{1+5^4+5^8+5^{12}+...+5^{28}}{1+5^2+5^4+5^8+5^{10}+...+5^{30}}\)
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
Rút gọn phân số sau :
\(\frac{5^{28}+5^{24}+...+5^4+1}{5^{30}+5^{28}+...+5^2+1}\)
A)\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}....\frac{30}{62}.\frac{31}{64}=4^x\)
B)\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=8^x\)
Tìm x biết :
\(\frac{1}{1×2×3×4}+\frac{1}{2×3×4×5}+\frac{1}{3×4×5×6}+...+\frac{1}{27×28×29×30}×x=-3\)
Tính A= 5^28+5^24+...+5^4+1/5^30+5^28+5^26+...+5^2+1
Mình cần gấp. Mong các bạn giúp đỡ
Đặt \(A=\frac{5^{28}+5^{24}+.........+5^4+1}{5^{30}+5^{28}+5^{26}+.....+5^2+1}=\frac{B}{C}\)
Xét tử \(B=5^{28}+5^{24}+........+5^4+1\)
\(\Rightarrow5^4.B=5^{32}+5^{28}+........+5^8+5^4\)
\(\Rightarrow625.B=5^{32}+5^{28}+........+5^8+5^4\)
\(\Rightarrow625.B-B=624.B=5^{32}-1\)
\(\Rightarrow B=\frac{5^{32}-1}{624}\)
Xét mẫu \(C=5^{30}+5^{28}+5^{26}+........+5^2+1\)
\(\Rightarrow5^2.C=5^{32}+5^{30}+5^{28}+.........+5^4+5^2\)
\(\Rightarrow25.C=5^{32}+5^{30}+5^{28}+........+5^4+5^2\)
\(\Rightarrow25.C-C=24.C=5^{32}-1\)
\(\Rightarrow C=\frac{5^{32}-1}{24}\)
\(\Rightarrow A=\frac{B}{C}=\frac{5^{32}-1}{624}:\frac{5^{32}-1}{24}=\frac{5^{32}-1}{624}.\frac{24}{5^{32}-1}=\frac{24}{624}=\frac{1}{26}\)
Đặt \(B=5^{28}+5^{24}+...+5^4+1\Rightarrow5^4B=5^{32}+5^{28}+...+5^8+5^4\)
\(\Rightarrow\left(5^4-1\right)B=5^{32}-1\Rightarrow B=\frac{5^{32}-1}{5^4-1}\)
Đặt \(C=5^{30}+5^{28}+...+5^2+1\Rightarrow5^2C=5^{32}+5^{30}+...+5^4+5^2\)
\(\Rightarrow\left(5^2-1\right)C=5^{32}-1\Rightarrow C=\frac{5^{32}-1}{5^2-1}\)
Khi đó \(A=\frac{B}{C}=\frac{\frac{5^{32}-1}{5^4-1}}{\frac{5^{32}-1}{5^2-1}}=\frac{5^2-1}{5^4-1}=\frac{1}{26}\)
Vậy................
1.rút gọn rồi tính
a.2/5+9/15 15/45+25/30 28/32+45/72
b.4/6+2/10 4/8+8/24 8/28+5/30
ai mik tick cho
mn ơi e vít nhầm là tính rồi rút gọn mn sửa lại là rút gọn rùi tính
a: =2/5+3/5=1
b: =1/3+5/6=2/6+5/6=7/6
c: =7/8+5/8=12/8=3/2
d: =2/3+2/10
=20/30+6/30
=26/30=13/15
e: =1/2+1/3
=3/6+2/6
=5/6
f: =2/7+1/6
=12/42+7/42
=19/42
a,A=1-2+3+4-5-6+7+8-9-...+2007+2008-2009-2010
b, \(\frac{1}{5^2}-\frac{1}{5^3}+\frac{1}{5^4}-\frac{1}{5^5}+..-\frac{1}{5^{101}}\).CM<\(\frac{1}{30}\)
3/4 + 1/2 +5/8 =
5/7 + 9/8 - 15/28 =
11/30 - 9/25 * 15/27
3/4 : 5/8 :3/10
3/4+1/2 +5/8 = 5/4 + 5/8 =15/8
b, 1/47/56 - 15/28= 73/ 56
c, 11/30 - 1/5 = 1/6
d tương tự nhé