2004 x 37 + 2004 x 2 + 2004 x 59 +2004 / 334 x 321 -201 x 334 - 334 x 102 - 17 x 334
giúp mình nha mình đang vội
Tính nhanh
2004*37+2004*2+2004*59+2004/334*321-201*334-334*102-18*334
A= 2004 x 37 + 2004 + 2 x 2004 + 2004 x 59 + 2004
324 x 321 - 201 x 324 - 324 x 101 - 18 x 324
A = 2004×37+2004+2×2004+2004×59+2004 324×321−201×324−324×101−18×324
tính nhanh 2004 . 37 + 2004 + 2 * 2004 + 2004 * 59 + 2004 / 324 * 321 - 201 * 324 - 324 * 101 - 18 * 324
\(\frac{2004.37+2004+2.2004+2004.59+2004}{324.321-201.324-101.324-18.324}\)
\(=\frac{2004.\left(37+1+2+59+1\right)}{324.\left(321-201-101-18\right)}\)
\(=\frac{2004.100}{324.1}\)
\(=\frac{200400}{324}\)
\(=\frac{16700}{27}\)
cái con THANH NGÂN ngu thế
A = x17- 2004.x16 + 2004.x15 - 2004.x14 +...+2004.(x - 1)
Tính A tại x = 2003
Thay \(x=2003\) vào A ta có:\(A=2003^{17}-2004.2003^{16}+2004.2003^{15}-2004.2003^{14}+...+2004.\left(2003-1\right)\)
\(=2003^{17}-\left(2003+1\right).2003^{16}+\left(2003+1\right).2003^{15}-\left(2003+1\right).2003^{14}+...+\left(2003+1\right).\left(2003-1\right)\)
\(=2003^{17}-2003^{17}+2003^{16}-2003^{16}+2003^{15}-2003^{15}+2003^{14}-2003^{14}+...+\left(2003+1\right).\left(2003-1\right)\)
\(=2004.2002=4012008\)
tim x biết
x + (x+1) +9x+2) +....+ (x+2003)=2004
giúp mình nha đang cần gấp
Dãy trên có 2004x
2004x+(1+2+3+4+...+2003)=2004
2004x+[(2003+1)x{(2003-1):1+1]:2}=2004
2004x+2007006=2004
2004x=2004-2007006
2004x=-2005002
x=-2005002:2004
x=-2001/2
Chúc em học tốt^^
cho đa thức f(x)=\(x^{17}-2004.x^{16}+2004.x^{15}-2004.x^{14}+...+2004.x-1\) tính giá trị đa thức tại x=2003
f(x)=\(x^{17}-2004.x^{16}+2004.x^{15}-2004.x^{2014}+...+2004.x-1\)
= \(x^{17}-\left(2003+1\right)x^{16}+\left(2003+1\right)x^{15}-\left(2003+1\right)^{14}+...+\left(2003+1\right)-1\)
Thay x = 2003
=> f(x)= \(x^{17}-\left(x+1\right)x^{16}+\left(x+1\right)x^{15}-\left(x+1\right)x^{14}+...+\left(x+1\right)x-1\)
=\(x^{17}-x^{17}-x^{16}+x^{16}+x^{15}-x^{15}-x^{14}+...+x^2+x-1\)
= \(x-1\)
= 2003 -1
=2002
Tìm x biết Ax + B = C
A = 158 x 12 - 12/7 - 12/289 -12/85 // 4 - 4/7 - 4/289 - 4/85 : 1/6 x 505505505 / 711711711 - 2005
B = 2003 x [2004 ^2003 + 2004^2002 + ..... + 2004 + 1] - 2004^2004 - 5
C= 2003 x 1986 + 2002 x 17 + 2020 / 2003 x 2004 - 2003 ^2
jup mik nhe
(x+4/2000)+(x+3/2001)=(x+2/2003)+(x+1/2004
Tìm x giup mình nha!