\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)
Những câu hỏi liên quan
Tính nhanh: \(\frac{-5}{11}+\frac{7}{22}-\frac{-4}{33}-\frac{5}{44}=38\frac{1}{22}-39\frac{7}{22}\)
a,\(\left\{\frac{2}{3}\right\}^3-\left\{\frac{3}{4}\right\}^2.\left\{-1\right\}^5\)
b,\(12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)
c,\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)
d,\(\frac{12}{35}.\left\{\frac{7}{4}+\frac{13}{4}\right\}-\frac{1}{3}\)
a. \(\left(\frac{2}{3}\right)^3-\left(\frac{3}{4}\right)^2.\left(-1\right)^5=\frac{8}{27}-\frac{9}{16}.\left(-1\right)=\frac{8}{27}+\frac{9}{16}=\frac{371}{432}\)
b. \(12:\left(\frac{3}{4}-\frac{5}{6}\right)^2=12:\left(-\frac{1}{12}\right)^2=12:\frac{1}{144}=12.144=1728\)
c. \(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}=\frac{7}{22}.\frac{11}{3}+\frac{7}{22}.\frac{11}{4}=\frac{7}{22}\left(\frac{11}{3}+\frac{11}{4}\right)\)
\(=\frac{7}{22}.\frac{77}{12}=\frac{49}{24}\)
d. \(\frac{12}{35}\left(\frac{7}{4}+\frac{13}{4}\right)-\frac{1}{3}=\frac{12}{35}.5-\frac{1}{3}=\frac{12}{7}-\frac{1}{3}=\frac{29}{21}\)
Tính :\(A=\frac{115-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{22}}+\frac{\frac{3}{5}+\frac{3}{13}-0,9}{\frac{7}{91}+0,2-\frac{3}{10}}\)
\(\frac{93}{17}:x+\left(\frac{-4}{17}\right):x+\frac{22}{7}:\frac{52}{3}=\frac{4}{11}\)
Tính:
\(\left(\frac{3}{4}+\frac{-7}{2}\right).\left(\frac{2}{11}+\frac{12}{22}\right)\)
Xem thêm câu trả lời
tinh nhanh
M=\(\frac{75-\frac{6}{13}+\frac{3}{17}-\frac{3}{19}}{275-\frac{22}{13}+\frac{11}{7}-\frac{11}{9}}\)
Tính nhanh
a ) \(\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{10}{11}\)
b) \(\frac{4}{1.3}.\frac{9}{2.4}.\frac{16}{3.5}.\frac{25}{4.6}.\frac{36}{5.7}\)
c) \(6\frac{4}{11}+\frac{8}{72}-\left(3\frac{8}{22}+\frac{1}{9}\right)\)
Tính các tổng sau:Cfrac{5}{7}.frac{5}{11}+frac{5}{7}.frac{2}{11}-frac{5}{7}.frac{14}{11}Tìm xx-frac{3}{10}frac{5}{7}x+frac{3}{22}frac{27}{121}.frac{11}{9}frac{8}{23}.frac{46}{24}-xfrac{1}{3}1-xfrac{49}{65}.frac{5}{7}x+frac{4}{5.9}+frac{4}{9.13}+frac{4}{13.17}+...+frac{4}{41.45}frac{-37}{45}
Đọc tiếp
Tính các tổng sau:
\(C=\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
Tìm x
\(x-\frac{3}{10}=\frac{5}{7}\)
\(x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)
\(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\)
\(1-x=\frac{49}{65}.\frac{5}{7}\)
\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=\frac{-37}{45}\)
1, Tính tổng:
\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)
\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)=\frac{5}{7}\cdot\frac{-7}{11}=\frac{-5}{11}\)
2, Tìm x:
\(x+\frac{5}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+...+\frac{4}{41\cdot45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+...+\frac{1}{41}-\frac{1}{45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{1}{5}-\frac{1}{45}=\frac{-37}{45}\Rightarrow x+\frac{9}{45}-\frac{1}{45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{8}{45}=\frac{-37}{45}\Rightarrow x=\frac{-37}{45}-\frac{8}{45}=\frac{-45}{45}=-1\)
- Các bài tìm x còn lại bạn cứ theo trình tự thực hiện phép tính mà làm nhé!
Đúng 0
Bình luận (0)
\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)
\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)
\(=\frac{5}{7}\cdot-\frac{7}{11}\)
\(=-\frac{5}{11}\)
Đúng 0
Bình luận (0)
\(C=\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
\(\Leftrightarrow C=\frac{5}{7}\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)
\(\Leftrightarrow C=\frac{5}{7}\times\frac{-7}{11}\)
\(\Leftrightarrow C=\frac{-35}{77}=\frac{-5}{11}\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tính:
\(\frac{-7}{13}+\frac{5}{11}-\frac{6}{13}+\frac{7}{22}\)\(\frac{-4}{5}-\frac{2}{17}+\frac{3}{10}+\frac{15}{17}\)
a) \(\frac{-77}{143}+\frac{65}{143}-\frac{66}{143}+\frac{7}{22}\)
= \(\frac{-78}{143}+\frac{7}{22}\)= \(\frac{-6}{11}+\frac{7}{22}\)= \(\frac{-12}{22}+\frac{7}{22}\)
= \(\frac{-5}{22}\)
b) \(\frac{-4}{5}-\frac{20}{170}+\frac{51}{170}+\frac{150}{170}\)= \(\frac{-4}{5}-\frac{221}{170}\)
\(\frac{-4}{5}-\frac{13}{10}\)= \(\frac{-8}{10}-\frac{13}{10}\)=\(\frac{-21}{10}\)
Đúng 0
Bình luận (0)