a) \(153^2-53^2=\left(153-53\right)\left(153+53\right)=100.206=20600\)

b)

\(\left(2020^2-2019^2\right)+\left(2018^2-2017^2\right)+...+\left(2^2-1^2\right)\\ =\left(2020+2019\right)\left(2020-2019\right)+\left(2018+2017\right)\left(2018-2017\right)+...+\left(2+1\right)\left(2-1\right)\\ =2020+2019+2018+2017+...+2+1\\ =\dfrac{\left(2020+1\right)2020}{2}=2041210\)

Lời giải:

a. $153^2-53^2=(153-53)(153+53)=100.206=20600$

b. 

$2020^2-2019^2+2018^2-2017^2+...+2^2-1^2$

$=(2020^2-2019^2)+(2018^2-2017^2)+...+(2^2-1^2)$

$=(2020-2019)(2020+2019)+(2018-2017)(2018+2017)+...+(2-1)(2+1)$

$=2020+2019+2018+2017+...+2+1$

$=\frac{2020.2021}{2}=2041210$

a) 153²-53²=(153-53)(153+53)=100.206=20600

1. 

$=153^2+2.47.153+47^2=(153+47)^2=200^2=40000$

2.

$=1,24^2-2.1,24.0,24+0,24^2=(1,24-0,24)^2=1^2=1$

3. Không phù hợp để tính nhanh 

4. 

$=15^8-(15^8-1)=1$

5.

$=(1^2-2^2)+(3^2-4^2)+(5^2-6^2)+...+(2019^2-2020^2)$

$=(1-2)(1+2)+(3-4)(3+4)+(5-6)(5+6)+...+(2019-2020)(2019+2020)$

$=(-1)(1+2)+(-1)(3+4)+(-1)(5+6)+....+(-1)(2019+2020)$

$=(-1)(1+2+3+4+....+2019+2020)=(-1).2020(2020+1):2=-2041210$

6:

\(\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =1.\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^4-1\right)\left(2^4+1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^8-1\right)....\left(2^{2020}+1\right)+1\\ =\left(2^{2020}-1\right)\left(2^{2020}+1\right)+1\\ =2^{4040}-1+1=2^{4040}\)

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\)

\(\Rightarrow\left(2x-2\right)^{15}\)

\(\Rightarrow2x-2=0\Rightarrow2x=2\Rightarrow x=1\)

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\)

\(\Rightarrow\left(2x-2\right)^9=1\)

\(\Rightarrow2x-2=1\)

\(\Rightarrow2x=3\Rightarrow x=\dfrac{3}{2}\)

\(\left(2x-2\right)^3=\left(2x-2\right)^{12}\\ \Rightarrow\left[{}\begin{matrix}2x-2=0\\2x-2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

ủa ,có đáp án ở trên rồi kìa bạn ,28 : (28 + 22) = 0,56 =56% đó thì đáp án là c 

số hạng là:

(21,25-3,25):1,50+1=13(số hạng)

tổng là:

(3,25+21,25).13:2=159,25

cái chỗ 78 . 27 đó là mình đánh sai là 78 . 4

78.31+78.4+78.17+22.77

= 78.(31+4+17) + 22.77

= 78.52+22.77

=4056+1694

=5750

k mình nha

78 . 31 + 78 . 27 + 78 . 17 + 22 . 72

= 78 . ( 31 + 27 + 17 ) + 22 . 72

= 78 . 75 + 22 . 72

= 5850 + 1584

= 7434

Số số hạng là :

   ( 30 - 20 ) : 1 + 1 = 11 ( số )

Tổng dãy trên là :

   ( 30 + 20 ) . 11 : 2 = 275 

Bằng 275 nha bạn

Số số hạng: ( 30 - 20 ) :1 + 1 = 11 (số)

Số cặp : 11 : 2 = 5,5 (cặp)

Tổng 1 cặp: 20 + 30 = 50 

Tổng: 5,5 x 50 = 275

Đ/S: 

a, 23 + ( -77 ) + ( -23 ) + 77

= [ 23 + ( -23 ) ] + [ ( -77 ) + 77 ]

= 0 + 0 = 0

b, ( -2020 ) + 2021 + 21 + ( -22 )

= ( - 2020 ) + 2021 + 21 + ( -21 ) + ( -1 )

= [ ( -2020 ) + 2021 + ( -1 ) ] + [ 21 + ( -21 ) ]

= 0 + 0 = 0

a) 23 + (-77) + (-23) + 77 =
[23 + (-23)] + [(-77) + 77]
=0+0=0
b) (-2 020) + 2 021 + 21 + (-22)
=[(-2 020) + 2 021] + [21 + (-22)]
=1+(-1)
= 0. 

3 số tự nhiên chẵn liên tiếp: 2n; 2n+2;2n+4 ( n ∈ N )