bạn nào giúp mình với ạ!!
mọi người giúp mình với ạ, biết câu nào các bạn giúp mình luôn nhé, mình đang cần gấp ạ.
Giúp mình với ạ. Mình sẽ tick cho những bạn nào giúp mình
Bạn nào giúp mình với ạ, tí nữa mình cần gấp rùi ạ! 🥺
Giúp mình với ạ mai mình phải nộp cô rồi ạ,bạn nào nhanh mình tick nhé
1) 43 . 78 - 43 . 48 + 30 . 80 - 30 . 23
= 43.(78 - 48) + 30.(80 - 23)
= 43.30 + 30.57
= 30.(43 + 57)
= 30.100
= 3000
2) 31.175 - 31.50 + 69.125
= 31.(175 - 50) + 69.125
= 31.125 + 69.125
= 125.(31 + 69)
= 125.100
= 12500
3) 2.[(7 - 3¹³ : 3¹²) : 2² + 99] - 10²
= 2.[(7 - 3) : 4 + 99] - 100
= 2.(4 : 4 + 99) - 100
= 2.(1 + 99) - 100
= 2.100 - 100
= 200 - 100
= 100
4) 2²⁰¹⁹.2² : 2²⁰¹⁶ - 125 : 5² + 2019⁰
= 2²⁰²¹ : 2²⁰¹⁶ - 125 : 25 + 1
= 2⁵ - 5 + 1
= 32 - 4
= 28
Bạn nào giúp mình với ạ , mình đg cần gấp .
a,\(\dfrac{2}{3}\)-\(\dfrac{5}{7}\).\(\dfrac{14}{25}\)
=\(\dfrac{2}{3}\)-\(\dfrac{2}{5}\)
=\(\dfrac{4}{15}\)
b,\(\dfrac{-2}{5}\).\(\dfrac{5}{8}\)+\(\dfrac{5}{8}\).\(\dfrac{3}{5}\)
=\(\dfrac{5}{8}\).(\(\dfrac{-2}{5}\)+\(\dfrac{3}{5}\))
=\(\dfrac{5}{8}\).\(\dfrac{1}{5}\)
=\(\dfrac{1}{8}\)
Giải:
a) \(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{4}{15}\)
b) \(\dfrac{-2}{5}.\dfrac{5}{8}+\dfrac{5}{8}.\dfrac{3}{5}\)
\(=\dfrac{5}{8}.\left(\dfrac{-2}{5}+\dfrac{3}{5}\right)\)
\(=\dfrac{5}{8}.\dfrac{1}{5}\)
\(=\dfrac{1}{8}\)
c) \(\left(\dfrac{1}{2}\right)^2-1\dfrac{1}{2}+0,5.\dfrac{12}{5}+5\%\)
\(=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{1}{2}.\dfrac{12}{5}+\dfrac{1}{20}\)
\(=\dfrac{-5}{4}+\dfrac{6}{5}+\dfrac{1}{20}\)
\(=0\)
Chúc bạn học tốt!
c,\(\left(\dfrac{1}{2}\right)^2\)-1\(\dfrac{1}{2}\)+0,5.\(\dfrac{12}{5}\)+5%
=\(\dfrac{1}{4}\)-\(\dfrac{3}{2}\)+\(\dfrac{1}{2}\).\(\dfrac{12}{5}\)+\(\dfrac{1}{20}\)
=\(\dfrac{1}{4}\)-\(\dfrac{3}{2}\)+\(\dfrac{6}{5}\)+\(\dfrac{1}{20}\)
=\(\dfrac{-5}{4}\)+\(\dfrac{6}{5}\)+\(\dfrac{1}{20}\)
=\(\dfrac{-1}{20}\)+\(\dfrac{1}{20}\)
=0
=
Bạn nào giải giúp mình hai câu này vs ạ , trình bày hộ mình với , mình cám ơn ạ
22/ \(\omega A=8\pi\)
\(A^2=x^2+\dfrac{v^2}{\omega^2}\Leftrightarrow A^2=3,2^2+\dfrac{\left(4,8\pi\right)^2}{\omega^2}\)
\(\Leftrightarrow\omega^2A^2=3,2^2\omega^2+23,04\pi^2\Leftrightarrow64\pi^2=3,2^2.\omega^2+23,04\pi^2\Leftrightarrow\omega=2\pi\left(rad/s\right)\)
\(\Rightarrow f=\dfrac{\omega}{2\pi}=\dfrac{2\pi}{2\pi}=1\left(Hz\right)\Rightarrow D.1Hz\)
23/ \(\omega A=20;\omega^2A=80\Rightarrow\left\{{}\begin{matrix}\omega=4\left(rad/s\right)\\A=5cm\end{matrix}\right.\)
\(\Rightarrow v=\omega\sqrt{A^2-x^2}=4.\sqrt{5^2-4^2}=12\left(cm/s\right)\Rightarrow A.12cm/s\)
bạn nào làm giúp mình với ạ mình cần gấp lắm ^^
1 Ann is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights
2 A committe has been set up to examine the question
3 Our class football team lost the match, so we tried to cheer them up
4 "Can I wear jeans at wedding party?" - "Of course not. You'll have to cover up smart clothes"
5 Before I come to a decision, I'll have to think over their offer very carefullyAnn is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights
A committe has been set up to examine the question
Our class football team lost the match, so we tried to spirit them up /cheer them up
"Can I wear jeans at wedding party?" - "Of course not. You'll have to cover up smart clothes"
Before I come to a decision, I'll have to think over their offer very carefully
1.Ann is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights.
2.A committe has been set up to examine the question.
3.Our class football team lost the match, so we tried to cheer them up,
4.''Can I wear jeans at wedding party?'' - ''Of course not.You'll have to cover up smart clthes''
5.Before I come to a decision, I'll have to think over their offer very carefully.
bạn nào giải giúp mình với ạ 🙏🏻
bạn nào giúp mình hình 4 với ạ!!