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Lê Minh Hiệp
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Lê Thị Phương Dung
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Trần Quỳnh Anh
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Hồng Nguyễn
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Kiều Vũ Linh
29 tháng 10 2023 lúc 6:17

1) 43 . 78 - 43 . 48 + 30 . 80 - 30 . 23

= 43.(78 - 48) + 30.(80 - 23)

= 43.30 + 30.57

= 30.(43 + 57)

= 30.100

= 3000

2) 31.175 - 31.50 + 69.125

= 31.(175 - 50) + 69.125

= 31.125 + 69.125

= 125.(31 + 69)

= 125.100

= 12500

3) 2.[(7 - 3¹³ : 3¹²) : 2² + 99] - 10²

= 2.[(7 - 3) : 4 + 99] - 100

= 2.(4 : 4 + 99) - 100

= 2.(1 + 99) - 100

= 2.100 - 100

= 200 - 100

= 100

4) 2²⁰¹⁹.2² : 2²⁰¹⁶ - 125 : 5² + 2019⁰

= 2²⁰²¹ : 2²⁰¹⁶ - 125 : 25 + 1

= 2⁵ - 5 + 1

= 32 - 4

= 28

Tasia
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OH-YEAH^^
4 tháng 6 2021 lúc 10:37

a,\(\dfrac{2}{3}\)-\(\dfrac{5}{7}\).\(\dfrac{14}{25}\)

=\(\dfrac{2}{3}\)-\(\dfrac{2}{5}\)

=\(\dfrac{4}{15}\)

b,\(\dfrac{-2}{5}\).\(\dfrac{5}{8}\)+\(\dfrac{5}{8}\).\(\dfrac{3}{5}\)

=\(\dfrac{5}{8}\).(\(\dfrac{-2}{5}\)+\(\dfrac{3}{5}\))

=\(\dfrac{5}{8}\).\(\dfrac{1}{5}\)

=\(\dfrac{1}{8}\)

 

Giải:

a) \(\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{4}{15}\) 

b) \(\dfrac{-2}{5}.\dfrac{5}{8}+\dfrac{5}{8}.\dfrac{3}{5}\) 

\(=\dfrac{5}{8}.\left(\dfrac{-2}{5}+\dfrac{3}{5}\right)\) 

\(=\dfrac{5}{8}.\dfrac{1}{5}\) 

\(=\dfrac{1}{8}\) 

c) \(\left(\dfrac{1}{2}\right)^2-1\dfrac{1}{2}+0,5.\dfrac{12}{5}+5\%\) 

\(=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{1}{2}.\dfrac{12}{5}+\dfrac{1}{20}\) 

\(=\dfrac{-5}{4}+\dfrac{6}{5}+\dfrac{1}{20}\) 

\(=0\) 

Chúc bạn học tốt!

OH-YEAH^^
4 tháng 6 2021 lúc 10:44

c,\(\left(\dfrac{1}{2}\right)^2\)-1\(\dfrac{1}{2}\)+0,5.\(\dfrac{12}{5}\)+5%

=\(\dfrac{1}{4}\)-\(\dfrac{3}{2}\)+\(\dfrac{1}{2}\).\(\dfrac{12}{5}\)+\(\dfrac{1}{20}\)

=\(\dfrac{1}{4}\)-\(\dfrac{3}{2}\)+\(\dfrac{6}{5}\)+\(\dfrac{1}{20}\)

=\(\dfrac{-5}{4}\)+\(\dfrac{6}{5}\)+\(\dfrac{1}{20}\)

=\(\dfrac{-1}{20}\)+\(\dfrac{1}{20}\)

=0

=

TayBD Channel
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Hoàng Tử Hà
29 tháng 4 2021 lúc 19:57

22/ \(\omega A=8\pi\)

\(A^2=x^2+\dfrac{v^2}{\omega^2}\Leftrightarrow A^2=3,2^2+\dfrac{\left(4,8\pi\right)^2}{\omega^2}\)

\(\Leftrightarrow\omega^2A^2=3,2^2\omega^2+23,04\pi^2\Leftrightarrow64\pi^2=3,2^2.\omega^2+23,04\pi^2\Leftrightarrow\omega=2\pi\left(rad/s\right)\)

\(\Rightarrow f=\dfrac{\omega}{2\pi}=\dfrac{2\pi}{2\pi}=1\left(Hz\right)\Rightarrow D.1Hz\)

23/ \(\omega A=20;\omega^2A=80\Rightarrow\left\{{}\begin{matrix}\omega=4\left(rad/s\right)\\A=5cm\end{matrix}\right.\)

\(\Rightarrow v=\omega\sqrt{A^2-x^2}=4.\sqrt{5^2-4^2}=12\left(cm/s\right)\Rightarrow A.12cm/s\)

Nguyễn Xuân Nam
20 tháng 10 2021 lúc 22:05
Là xem naruto
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Hưng Lâm
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Đỗ Thanh Hải
13 tháng 7 2021 lúc 7:36

1 Ann is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights

2 A committe has been set up to examine the question

3 Our class football team lost the match, so we tried to cheer them up

4 "Can I wear jeans at wedding party?" - "Of course not. You'll have to cover up smart clothes"

5 Before I come to a decision, I'll have to think over their offer very carefully  
Khinh Yên
13 tháng 7 2021 lúc 7:37

Ann is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights

A committe has been set up to examine the question

Our class football team lost the match, so we tried to spirit them up /cheer them up

"Can I wear jeans at wedding party?" - "Of course not. You'll have to cover up smart clothes"

Before I come to a decision, I'll have to think over their offer very carefully

Phương Nora kute
13 tháng 7 2021 lúc 8:36

1.Ann is very upset because the local authorities have turned down her proposals to install solar panels to supply electricity for traffic lights.

2.A committe has been set up to examine the question.

3.Our class football team lost the match, so we tried to cheer them up,

4.''Can I wear jeans at wedding party?'' - ''Of course not.You'll have to cover up smart clthes''

5.Before I come to a decision, I'll have to think over their offer very carefully.

mjfsdoak
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Nguyễn Minh Trang
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