a) \(x^8+14x^4+1=\left(x^4+1\right)^2+12x^4=\left(x^4+1\right)^2+4x^2\left(x^4+1\right)+4x^4-4x^2\left(x^4+1\right)+8x^4\)

\(=\left(x^4+2x^2+1\right)^2-4x^2\left(x^4-2x^2+1\right)=\left(x^4+2x^2+1\right)^2-\left(2x\left(x^2-1\right)\right)^2\)

\(=\left(x^4-2x^3+2x^2+2x+1\right)\left(x^4+2x^3+2x^2-2x+1\right)\)

Ta có : \(x^8+14x^4+1\)

\(=x^8+2.x^4.7+1\)

\(=x^8+2.x^4.7+49-48\)

\(=\left(x^4+7\right)^2-48\)

\(=\left(x^4+7-\sqrt{48}\right)\left(x^4+7+\sqrt{48}\right)\)

a/\(=\left(x^4+1\right)^2+12x^4=\left(x^4+1\right)^2+4x^2\left(x^4+1\right)+4x^4-4x^2\left(x^4+1\right)+8x^4\)

\(=\left(x^4+1+2x^2\right)^2-4x^2\left(x^4+1-2x^2\right)=\left(x^4+2x^2+1\right)-\left(2x^3-2x\right)^2\)

\(=\left(x^4+2x^3+2x^2-2x+1\right)\left(x^4-2x^3+2x^2+2x+1\right)\)

b/\(=\left(x^4+1\right)^2+96x^4=\left(x^4+1\right)^2+16x^2\left(x^4+1\right)+64x^4-16x^2\left(x^4+1\right)+32x^4\)

\(=\left(x^4+1+8x^2\right)^2-16x^2\left(x^4+1-2x^2\right)=\left(x^4+8x^2+1\right)-\left(4x^3-4x\right)^2\)

\(=\left(x^4+4x^3+8x^2-4x+1\right)\left(x^4-4x^3+8x^2+4x+1\right)\)

a) = a^10 - a + a^5 - a^2 + a^2 + a + 1

= a(a^9 - 1) + a^2(a^3 - 1) + (a^2 + a + 1)

= a.(a^3-1)(a^6 + a^3 + 1) + a^2(a-1)(a^2+a+1) + (a^2 + a + 1)

= a.(a-1)(a^2 + a + 1)(a^6 + a^3 + 1) + a^2(a-1)(a^2+a+1) + (a^2 + a + 1)

= (a^2 + a + 1)[(a.(a-1)(a^6 + a^3 + 1) + a^2 + 1]

b) x^5 - x^4 - 1 = x^5 - x^4 + x^3 - x^3 + x^2 - x - x^2 + x - 1

= x^3(x^2 - x + 1) - x(x^2 - x + 1) - (x^2 - x + 1)

= (x^2 - x + 1)(x^3 - x - 1)

a) \(a^{10}+a^5+1\)

\(=\left(a^{10}-a^9+a^7-a^6+a^5-a^3+a^2\right)\)

\(+\left(a^9-a^8+a^6-a^5+a^4-a^2+a\right)\)

\(+\left(a^8-a^7+a^5-a^4+a^3-a+1\right)\)

\(=a^2\left(a^8-a^7+a^5-a^4+a^3-a+1\right)\)

\(+a\left(a^8-a^7+a^5-a^4+a^3-a+1\right)\)

\(+\left(a^8-a^7+a^5-a^4+a^3-a+1\right)\)

\(=\left(a^2+a+1\right)\left(a^8-a^7+a^5-a^4+a^3-a+1\right)\)

b) \(x^5-x^4-1\)

\(=\left(x^5-x^3-x^2\right)-\left(x^4-x^2-x\right)+\left(x^3-x-1\right)\)

\(=x^2\left(x^3-x-1\right)-x\left(x^3-x-1\right)+\left(x^3-x-1\right)\)

\(=\left(x^2-x+1\right)\left(x^3-x-1\right)\)

x⁸ + 14x⁴ + 1

= [(x⁴)² + 2.7.x² + 49] - 48

=(x⁴ + 7)² - (\(\sqrt{48}\))²

=(x⁴ + 7 + căn48²).(x⁴ + 7 - căn48²)

không ai phan tích kiểu này

câu b thì sao 

a.\(A=\dfrac{x^2-4x+4}{x^3-2x^2-\left(4x-8\right)}=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}=\dfrac{\left(x-2\right)^2}{\left(x^2-4\right)\left(x-2\right)}=\dfrac{x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x+2}\)

\(A=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}\left(x\ne\pm2\right)\\ A=\dfrac{\left(x-2\right)^2}{\left(x-2\right)^2\left(x+2\right)}=\dfrac{1}{x+2}\\ B=\dfrac{x+2-x+\sqrt{x}-1}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}\cdot\dfrac{4\sqrt{x}}{3}\left(x>0\right)\\ B=\dfrac{4\sqrt{x}\left(\sqrt{x}+1\right)}{3\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}=\dfrac{4\sqrt{x}}{3\left(x-\sqrt{x}+1\right)}\)

a) \(x=0,05\)

b) \(x=1,125\)

c) \(x=0,96\)

d) \(x=0,025\)

Bạn tự làm đi dễ mà . Cố mag vận động đầu óc đừng copy làm bài nữa khó lắm mới hỏi thôi

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