tim x
a,2x-138=2^3.3^2
b,20-[7.(x-3)+4]=2
c,[6x-39]*3.28=5628
Tìm x :
a) 2x - 138 = 2^3 . 3^2
b) 20 - [ 7 . ( x - 3 ) + 4 ] = 2
c) 310 - ( 118 - x ) = 217
d) 2010^5 . ( x - 60 ) = 2010^6
e) 5 . ( x + 35 ) = 515
f) [ ( 6x - 39 ) : 3 ] . 28 = 5628
g) 720 : [ 41 - ( 2x - 5 ) ] = 2^3 . 5
h) ( 6x - 3^4 ) . 7^3 = 3 . 7^4
v) 4x^3 + 12 = 120
m) 3 . 2^x - 3 = 45
--- Giải nhanh, đúng sẽ hậu tạ. '-' ( Trong khả năng ) ---
tìm x
1)[2.(70-x)+23.32]:2=46
2)6x-39=5628:28
3)2x-138=23.32
4)219-7(x+1)=100
5)14 chia hết (2.x+3)
6)2.(x-8)=22
14 chia hêt cho 2x+3
=>2x+3 thuộc Ư (14)
=>Ư (14)={1;2;7;14}
ta có
2x+3 | 1 | 2 | 3 | 14 |
x | X | X | 0 | X |
vậy x=0
219-7(x+1)=100
7(x+1)=219-100
7(x+1)=119
x+1 =119:7
x+1 =17
x =17-1
x =16
1) [2.(70-x)+23.32]:2=46
2.(70-x)+8.9=92
2.(70-x)+72=92
2.(70-x)=20
70-x=10
x=60
2) 6x-39=5628:28
6x-39=201
6x=240
x=40
3)2x-138=23.32
2x-138=8.9
2x-138=72
2x=210
x=105
4)219-7(x+1)=100
7(x+1)=119
x+1=17
x=16
5)14 chia het cho (2x+3)
=> (2x+3) thuoc U(14)={1;-1;2;-2;7;-7;14;-14}
TH1: 2x+3=1
2x=-2
x=-1
TH2: 2x+3=-1
2x=-4
x=-2
TH3: 2x+3=2
2x=-1
x= -1/2
TH4: 2x+3=-2
2x=-5
x=-5/2
TH5: 2x+3=7
2x=4
x=2
TH6: 2x+3=-7
2x=-10
x= -5
TH7: 2x+3=14
2x=11
x=11/2
TH8: 2x+3=-14
2x=-17
x=-17/2
Vay x thuoc {-1; -2; -1/2; -5/2; 2; -5; 11/2; -17/2}
6)2.(x-8)=22
x-8=2
x=10
1) Tìm x:
a) 20 - [7.(x - 3) + 4 ]=2
b) [ (6x - 39 ) : 3 ] . 28=5628
[(6x-39):3] . 28 = 5628
(6x - 39) : 3 = 201
6x - 39 = 603
6x = 642
x = 107
a) 7.(x - 3) + 4 = 18
7. (x - 3) = 14
x - 3 = 2
x = 5
b) 2x - 13 = 201
2x = 214
x = 107
c) (7x + x – 28) :100 – 38 = 9.
d) 936 – (4x + 5x ) = 900
e) 280 + 78 : (135 – x :7) =286
f) x – 18 :3 = 16 + 16 : 23.
g) (3x – 10) : 10 = 20.
h) (3x – 24 ).73= 2.74
i) 123 – 5.( x + 4) = 38.
k) [(6x – 72) :2 – 84].28 = 5628.
m) 2x – 138 = 23.32.
n) [(10 - x).2 + 7]:3 -2 = 3.
Trình bày kết quả rõ ràng nha cảm ơn mọi người rất nhiều❤❤❤
c) (7x + x – 28) :100 – 38 = 9
<=> 8x - 28 = 4700
<=> x = 591
d) 936 – (4x + 5x ) = 900
<=> 9x = 36
<=> x = 4
Tìm x thuộc N biết :
A, (2367-x)-1017=205
B,(6x-39):3.28=5628
C, 5x-x+2x=42
D,1339:[231-(x-6)]=13
E, (x-2)(x-3)=0
Ai giúo mình với mỉnh sắp nộp rồi !!
Làm được câu nào thì làm nhưng cố làm hết đùng bỏ nha
\(a)(2367-x)-1017=205\)
\(\Leftrightarrow(2367-x)=205+1017\)
\(\Leftrightarrow(2367-x)=1222\)
\(\Leftrightarrow x=2367-1222\)
\(\Leftrightarrow x=1145\)
\(b)(6x-39):3\cdot28=5628\)
\(\Leftrightarrow(6x-39):3=\frac{5628}{28}\)
\(\Leftrightarrow(6x-39):3=201\)
\(\Leftrightarrow(6x-39)=201\cdot3\)
\(\Leftrightarrow(6x-39)=603\)
\(\Leftrightarrow6x=603+39\)
\(\Leftrightarrow6x=642\)
\(c)5x-x+2x=42\)
\(\Rightarrow5x-1x+2x=42\)
\(\Rightarrow6x=42\)
\(\Rightarrow x=7\)
d\()\)Tương tự câu a và b
e\()(x-2)(x-3)=0\)
Xét có hai trường hợp :
TH1 : x - 2 = 0 => x = 2
TH2 : x - 3 = 0 => x = 3
Vậy : \(\hept{\begin{cases}x=2\\x=3\end{cases}}\)
\(\Leftrightarrow x=\frac{642}{6}=107\)
tìm số tự nhiên x biết
a) ( 2600 +6400 ) -3 x X =1200
b) [ ( 6x X -72 ) : 2 -84 ] x 28 =5628
c) 2x -138 = 23 x 32
d) 42x =39 x 42 - 37 x 42
tìm số tự nhiên x biết
a) ( 2600 +6400 ) -3 x X =1200
b) [ ( 6x X -72 ) : 2 -84 ] x 28 =5628
c) 2x -138 = 23 x 32
d) 42x =39 x 42 - 37 x 42
Tim so tu nhien x biet :
A,(2600+6400)-3×x=1200
B,[(6×x-72):2-84].28=5628
C,2x-138=2^3÷3^2
d,42x=39×42-37×42
Dup minh nhe
\(a,\left(2600+6400\right)-3\times x=1200\)
\(9000-3\times x=1200\)
\(3\times x=9000-1200\)
\(3\times x=7800\)
\(x=7800:3\)
\(x=2600\)
\(b,\left[\left(6\times x-72\right):2-84\right]\times28=5628\)
\(\left(6\times x-72\right):2-84=5628:28\)
\(\left(6\times x-72\right):2-84=201\)
\(\left(6\times x-72\right):2=201+84\)
\(\left(6\times x-72\right):2=285\)
\(6\times x-72=285\times2\)
\(6\times x-72=570\)
\(6\times x=570+72\)
\(6\times x=642\)
\(x=107\)
\(c,2x-138=2^3:3^2\)
\(2x-138=\frac{8}{9}\)
\(2x=\frac{8}{9}+138\)
\(2x=\frac{1250}{9}\)
\(x=\frac{1250}{9}:2\)
\(x=\frac{625}{9}\)
\(d,42x=39\times42-37\times42\)
\(42x=42\times\left(39-37\right)\)
\(42x=42\times2\)
\(42x=84\)
\(x=2\)
1.Tìm x
a) 310-(118-x)=217
b) 814-(x-305)=712
c)5(x+35)=515
d)(6.x-39):3].28=5628
e)2.x-138=23.22
g)20-[7.(x-3)+4]=2
a) 310-(118-x)=217
118-x=310-217
118-x=93
x=118-93
x=25
b) 814-(x-305)=712
x-305=814-712
x-305=102
x =102+305
x = 407
c)5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x =68
\(a,310-\left(118-x\right)=217\) \(c,5\left(x+35\right)=515\)
\(118-x=310-217\) \(x+35=515:5\)
\(118-x=93\) \(x+35=103\)
\(x=118-93\) \(x=103-35\)
\(x=25\) \(x=68\)
\(b,814-\left(x-305\right)=712\) \(\left[\left(6.x-39\right):3\right].28=5628\)
\(x-305=814-712\) \(\left(6.x-39\right):3=5628:28\)
\(x-305=102\) \(\left(6.x-39\right):3=201\)
\(x=102+305\) \(6.x-39=201x3\)
\(x=407\) \(6.x-39=603\)
\(6x=603+39\)
\(6x=642\)
\(x=107\)
\(e,2.x-138=2^3.2^2\)
\(2.x-138=32\)
\(2.x=32+138\)
\(2.x=170\)
\(x=170:2\)
\(x=85\)
310 - ( 118-x) = 217
118 - x = 310 - 217
118 -x = 93
x = 118 - 93
x = 25